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What is the product of the following nuclear decay processes? Write an equation for each process. (a) Gallium-67 decays by electron capture. (b) Potassium-38 decays with positron emission. (c) Technetium-99m decays with \(\gamma\) emission. (d) Manganese-56 decays by \(\beta\) emission.

Short Answer

Expert verified
(a) Zn-67, (b) Ar-38, (c) Tc-99, (d) Fe-56.

Step by step solution

01

Identify Electron Capture for Gallium-67

In electron capture, a nucleus captures an inner orbital electron, which combines with a proton to form a neutron. This process decreases the atomic number by 1, without changing the mass number. The equation for Gallium-67 is as follows:\[ ^{67}_{31}\text{Ga} + e^- \rightarrow ^{67}_{30}\text{Zn} + u \] where \( u \) is a neutrino.
02

Understand Positron Emission for Potassium-38

In positron (\(\beta^+\)) emission, a proton is transformed into a neutron, releasing a positron and a neutrino. The atomic number decreases by 1, and the mass number remains unchanged. The equation for Potassium-38 is:\[ ^{38}_{19}\text{K} \rightarrow ^{38}_{18}\text{Ar} + \beta^+ + u \]
03

Analyze Gamma Emission for Technetium-99m

Gamma (\( \gamma \)) emission involves the release of energy from a nucleus in an excited state to a lower energy state, without a change in the atomic number or mass number. For Technetium-99m, the process is:\[ ^{99m}_{43}\text{Tc} \rightarrow ^{99}_{43}\text{Tc} + \gamma \]
04

Describe Beta Emission for Manganese-56

In beta (\(\beta^-\)) emission, a neutron is converted into a proton while emitting an electron (beta particle) and an antineutrino. The atomic number increases by 1, and the mass number remains constant. For Manganese-56, this can be represented as:\[ ^{56}_{25}\text{Mn} \rightarrow ^{56}_{26}\text{Fe} + \beta^- + \bar{u} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron Capture
Electron capture is a fascinating nuclear decay process in which the nucleus of an atom captures an inner orbital electron. This captured electron merges with a proton, transforming it into a neutron and releasing a neutrino. As a result, the atomic number of the element decreases by one, while the mass number remains unchanged. This type of decay generally occurs in proton-rich, heavy nuclei.

For example, when Gallium-67 undergoes electron capture, it transforms into Zinc-67. The reaction can be written as:
\[ ^{67}_{31}\text{Ga} + e^- \rightarrow ^{67}_{30}\text{Zn} + \text{neutrino} \]

It's important to remember that the overall charge and nucleon number are conserved during this process. This transformation helps unstable isotopes move towards a more stable state.
Positron Emission
Positron emission, symbolized as \(\beta^+\), involves a proton in the nucleus transforming into a neutron. During this transformation, a positron (the antimatter counterpart of an electron) and a neutrino are emitted. As a result, the atomic number decreases by one, but the mass number stays the same.

This process is common in nuclei that have an excess of protons compared to neutrons. For Potassium-38, the representation of positron emission is:
\[ ^{38}_{19}\text{K} \rightarrow ^{38}_{18}\text{Ar} + \beta^+ + \text{neutrino} \]

By emitting a positron, the nucleus moves towards a more balanced and stable state, with the reduction in the overall positive charge aiding in this stabilization process.
Gamma Emission
Unlike other types of decay, gamma (\( \gamma \) ) emission involves the release of energy rather than particles. It occurs when a nucleus in an excited state releases energy to move to a lower energy state. This release of energy takes place in the form of gamma rays, which are high-energy photons.

In this process, neither the atomic number nor the mass number changes, which means the identity of the element remains the same.

For Technetium-99m, the process can be expressed as:
\[ ^{99m}_{43}\text{Tc} \rightarrow ^{99}_{43}\text{Tc} + \gamma \]

Gamma emission is crucial in medical imaging and other applications, as it allows for the transition of atomic states without altering the elemental composition.
Beta Emission
Beta emission, or \(\beta^-\) decay, involves a neutron turning into a proton, accompanied by the emission of an electron (known as a beta particle) and an antineutrino. This conversion increases the atomic number by one while the mass number stays constant.

This process is frequent in neutron-rich isotopes, helping them achieve a more stable and balanced nuclear configuration. For Manganese-56, the beta decay can be represented as follows:
\[ ^{56}_{25}\text{Mn} \rightarrow ^{56}_{26}\text{Fe} + \beta^- + \text{antineutrino} \]

Through beta emission, the nucleus releases an excess negative charge and transitions into a slightly more positively charged state, shifting towards stability.

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Most popular questions from this chapter

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Some important discoveries in scientific history that contributed to the development of nuclear chemistry are listed below. Briefly, describe each discovery, identify prominent scientists who contributed to it, and comment on the significance of the discovery to the development of this field. (a) \(1896,\) the discovery of radioactivity (b) \(1898,\) the identification of radium and polonium (c) \(1919,\) the first artificial nuclear reaction

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