/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 The fission of uranium- 235 rele... [FREE SOLUTION] | 91Ó°ÊÓ

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The fission of uranium- 235 releases \(2 \times 10^{10} \mathrm{kJ} /\) mol. Calculate the quantity of mass converted to energy in this process.

Short Answer

Expert verified
Approximately \(2.22 \times 10^{-4} \mathrm{kg/mol}\) of uranium-235 is converted to energy.

Step by step solution

01

Understanding the Relationship

To find the mass converted to energy during the fission of uranium-235, we must use Einstein's mass-energy equivalence principle, stated as \( E=mc^2 \), where \( E \) is the energy produced, \( m \) is the mass converted, and \( c \) is the speed of light (approximately \(3 imes 10^8 \mathrm{m/s}\)).
02

Rearranging the Formula

Since we are looking for the mass \( m \), we rearrange the formula to \( m = \frac{E}{c^2} \).
03

Converting Energy Units

The energy given is \( 2 \times 10^{10} \mathrm{kJ/mol} \). Convert this to joules, knowing that \(1 \, \mathrm{kJ} = 1000 \, \mathrm{J}\). So, \( E = 2 \times 10^{10} \, \mathrm{kJ/mol} \times 1000 \, \frac{\mathrm{J}}{\mathrm{kJ}} = 2 \times 10^{13} \, \mathrm{J/mol}\).
04

Plugging Values into the Formula

Substitute the values into the rearranged formula: \( m = \frac{2 \times 10^{13} \, \mathrm{J/mol}}{(3 \times 10^8 \, \mathrm{m/s})^2}\).
05

Calculating the Mass

Perform the division: \( m = \frac{2 \times 10^{13}}{9 \times 10^{16}}\). This results in \( m = 2.22 \times 10^{-4} \mathrm{kg/mol}\) of uranium-235 converted to energy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass-Energy Equivalence
Mass-energy equivalence is a fundamental concept in modern physics, introduced by Albert Einstein. It states that mass and energy are two forms of the same entity. The principle is often expressed through Einstein's iconic equation. This equation reveals that a small amount of mass can be converted into a tremendous amount of energy. Understanding mass-energy equivalence helps explain phenomena like nuclear fission, where part of the mass of an atom transforms into energy. It's a concept that underpins both nuclear power generation and atomic weapons. In essence, when mass is "lost" during a reaction, it doesn't just disappear. Instead, it turns into energy, which can be harnessed for various purposes, like powering cities or, unfortunately, destructive uses, as seen in weapons.
Uranium-235
Uranium-235 is a naturally occurring isotope of uranium and one of the fissile materials capable of sustaining a nuclear chain reaction. It's pivotal in nuclear fission because it can release a large amount of energy when its nucleus splits. - **Nuclear Properties**: Uranium-235 has 92 protons and 143 neutrons. When bombarded with a neutron, it splits into smaller atoms, additional neutrons, and a noteworthy amount of energy. - **Availability**: While uranium-235 makes up only about 0.7% of natural uranium, it's vital for both nuclear power plants and nuclear weapons. The fission of uranium-235 is a key focus in energy production, as the energy released by one kilogram can equal millions of kilograms of traditional chemical fuel like coal or oil.
Energy Conversion
Energy conversion in nuclear fission involves the transformation of atomic mass into usable energy. During nuclear fission, atoms are split into smaller parts, releasing energy in the form of kinetic energy of the fission fragments. This conversion, guided by mass-energy equivalence, is incredibly efficient. A single fission event releases a massive amount of energy. In the context of uranium-235, the conversion facilitates vast amounts of energy from minute quantities of matter. An important consequence is that the energy density of nuclear fuel is much higher than that of fossil fuels, making nuclear energy a potent source for electricity generation.
Einstein's Equation
Einstein's equation, expressed as \( E=mc^2 \), is the mathematical backbone that describes mass-energy equivalence. Here, \( E \) stands for energy, \( m \) stands for mass, and \( c \) represents the speed of light in a vacuum (approximately \(3 \times 10^8 \) meters per second).This formula shows that the energy produced by a process is proportional to the mass lost, multiplied by the speed of light squared. It indicates that even a small amount of mass can convert into a tremendous quantity of energy, due to the large value of \( c^2 \).Utilizing the formula: - **Rearrange it to find mass**: In many nuclear reactions, the formula is adjusted to find the amount of mass that turns into energy as \( m = \frac{E}{c^2} \).- **Practical Applications**: The principle is crucial in calculating the energy yield of nuclear reactions, like those involving uranium-235, making it indispensable in both theoretical and applied physics.

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Most popular questions from this chapter

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