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Acetaminophen, whose structure is drawn below, is the active ingredient in some nonprescription pain killers. The recommended dose for an adult is two \(500-\mathrm{mg}\) caplets. How many molecules make up one dose of this drug?

Short Answer

Expert verified
The one dose of acetaminophen contains approximately \(3.98 \times 10^{21}\) molecules.

Step by step solution

01

Determine the Total Mass of the Dose

Calculate the mass of the recommended dose, which consists of two caplets.Each caplet is **500 mg**, therefore, the total mass is:\[2 \times 500 \text{ mg} = 1000 \text{ mg} = 1 \text{ g}\]
02

Convert Grams to Moles

The molar mass of acetaminophen (C₈H₉NO₂) is needed. Using the periodic table, calculate the molar mass:\[C: 8 \times 12.01 \, \text{g/mol} = 96.08 \, \text{g/mol}\]\[H: 9 \times 1.01 \, \text{g/mol} = 9.09 \, \text{g/mol}\]\[N: 1 \times 14.01 \, \text{g/mol} = 14.01 \, \text{g/mol}\]\[O: 2 \times 16.00 \, \text{g/mol} = 32.00 \, \text{g/mol}\]Total molar mass = 96.08 + 9.09 + 14.01 + 32.00 = 151.18 \, \text{g/mol}Now, convert from grams to moles:\[\text{Moles of acetaminophen} = \frac{1 \, \text{g}}{151.18 \, \text{g/mol}} \approx 0.00661 \, \text{mol}\]
03

Convert Moles to Molecules

Use Avogadro's number to find the total number of molecules. Avogadro's number is\[6.022 \times 10^{23} \text{ molecules/mol}\]Thus, the number of molecules is:\[0.00661 \, \text{mol} \times 6.022 \times 10^{23} \text{ molecules/mol} \approx 3.98 \times 10^{21} \text{ molecules}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass
The molar mass is a vital concept in chemistry. It refers to the mass of one mole of a substance, typically expressed in grams per mole (g/mol). To find the molar mass of a compound, you need to add up the atomic masses of all the atoms in its molecular formula. In the case of acetaminophen, which has the formula \( \text{C}_8\text{H}_9\text{NO}_2 \), you look at the atomic mass of each element in the compound from the periodic table:

  • Carbon (C): 12.01 g/mol, and there are 8 carbons, so 8 × 12.01 = 96.08 g/mol
  • Hydrogen (H): 1.01 g/mol, and there are 9 hydrogens, so 9 × 1.01 = 9.09 g/mol
  • Nitrogen (N): 14.01 g/mol, with 1 nitrogen, so 1 × 14.01 = 14.01 g/mol
  • Oxygen (O): 16.00 g/mol, with 2 oxygens, so 2 × 16.00 = 32.00 g/mol
Adding these together gives the molar mass of acetaminophen: 151.18 g/mol. Molar mass is crucial because it allows us to convert between grams and moles, a necessary step in various chemical calculations.
Avogadro's Number
Avogadro's number is a fundamental constant in chemistry. It represents the number of constituent particles, usually atoms or molecules, that are contained in the amount of substance known as one mole. Avogadro's number is approximately \(6.022 \times 10^{23} \) per mole.

Understanding Avogadro's number is key when dealing with molecular or atomic scales. For example, if we have \(0.00661\) moles of acetaminophen, we can calculate the number of molecules by multiplying the number of moles by Avogadro's number:
  • \(0.00661 \times 6.022 \times 10^{23} \approx 3.98 \times 10^{21} \) molecules
This number helps us conceptualize how incredibly small atoms and molecules are, and how many fit into even tiny amounts of substance. It’s essential for converting between moles (a macroscopic measure) and molecules (a microscopic measure).
Acetaminophen Structure
The structure of acetaminophen is crucial for differentiating it from other compounds, as well as understanding its function and characteristics. Acetaminophen, also known by its chemical name N-(4-hydroxyphenyl)acetamide, is a simple organic compound commonly used as a pain reliever and fever reducer.

The molecular formula of acetaminophen is \(\text{C}_8\text{H}_9\text{NO}_2\). Here is a deeper look into its structure:
  • Aromatic Ring: It includes a benzene ring, a six-carbon ring that is a common feature in many compounds due to its stability.
  • Hydroxyl Group (-OH): This group is bonded to the aromatic ring, contributing to the molecule’s reactivity and polarity.
  • Acetamide Group: The NH (nitrogen-hydrogen) bond and carbonyl (C=O) group form this group, giving acetaminophen its characteristic medicinal properties.
Understanding its structural components helps in grasping how acetaminophen interacts at the molecular level, where these functional groups play crucial roles in its effectiveness as a pharmaceutical agent.

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Most popular questions from this chapter

A jar contains some number of jelly beans. To find out precisely how many are in the jar, you could dump them out and count them. How could you estimate their number without counting each one? (Chemists need to do just this kind of "bean counting" when they work with atoms and molecules. Atoms and molecules are too small to count one by one, so chemists have worked out other methods to determine the number of atoms in a sample.

Tin metal (Sn) and purple iodine (I_2) combine to form orange, solid tin iodide with an unknown formula. $$\text { Sn metal }+\text { solid } \mathrm{I}_{2} \rightarrow \text { solid } \mathrm{Sn}_{x} \mathrm{I}_{y}$$ Weighed quantities of Sn and \(\mathrm{I}_{2}\) are combined, where the quantity of Sn is more than is needed to react with all of the iodine. After \(\operatorname{Sn}_{x}\) I has been formed, it is isolated by filtration. The mass of excess tin is also determined. The following data were collected: Mass of tin (Sn) in the original mixture \(1.056 \mathrm{g}\) Mass of iodine \(\left(\mathrm{I}_{2}\right)\) in the original mixture \(1.947 \mathrm{g}\) Mass of tin (Sn) recovered after reaction \(0.601 \mathrm{g}\) What is the empirical formula of the tin iodide obtained?

Select answers to the questions listed below from the following list of elements whose symbols start with the letter \(\mathrm{C}: \mathrm{C}, \mathrm{Ca}, \mathrm{Cr}, \mathrm{Co}, \mathrm{Cd}, \mathrm{Cl}, \mathrm{Cs}, \mathrm{Ce}\) \(\mathrm{Cm}, \mathrm{Cu},\) and Cf. (You should expect to use some symbols more than once.) (a) Which are nonmetals? (b) Which are main group elements? (c) Which are lanthanides? (d) Which are transition elements? (e) Which are actinides? (f) Which are gases?

In 1886 Eugene Goldstein observed positively charged particles moving in the opposite direction to electrons in a cathode ray tube (illustrated below). From their mass, he concluded that these particles were formed from residual gas in the tube. For example, if the cathode ray tube contained helium, the canal rays consisted of \(\mathrm{He}^{+}\) ions. Describe a process that could lead to these ions.

Which of the following are correct formulas for ionic compounds? For those that are not, give the correct formula. (a) \(\mathrm{Ca}_{2} \mathrm{O}\) (b) \(\operatorname{SrBr}_{2}\) (c) \(\mathrm{Fe}_{2} \mathrm{O}_{5}\) (d) \(\mathrm{Li}_{2} \mathrm{O}\)

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