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Titanium and thallium have symbols that are easily confused with each other. Give the symbol, atomic number, atomic weight, and group and period number of each element. Are they metals, metalloids, or nonmetals?

Short Answer

Expert verified
Titanium: Ti, atomic number 22, Group 4, Period 4, transition metal. Thallium: Tl, atomic number 81, Group 13, Period 6, metal.

Step by step solution

01

Identify the Symbols

The symbol for titanium is Ti, and the symbol for thallium is Tl.
02

Titanium Information

Titanium (Ti) has an atomic number of 22. Its atomic weight is approximately 47.87 amu. It is located in Group 4 and Period 4 of the periodic table. Titanium is classified as a transition metal.
03

Thallium Information

Thallium (Tl) has an atomic number of 81. Its atomic weight is approximately 204.38 amu. It is located in Group 13 and Period 6 of the periodic table. Thallium is classified as a metal.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Elements
Elements are the fundamental building blocks of everything around us. They are the simplest form of matter that cannot be broken down into any simpler substance using chemical reactions.
Elements are unique and each one is composed of just one kind of atom. These atoms bond together in different ways to create the wide variety of materials and substances we find in nature.
On the periodic table, each element is represented with a distinct place. This organization allows us to understand more about their properties and how they interact with other elements.
  • There are metals, nonmetals, and metalloids.
  • Each element has its own distinct atomic number and atomic weight.
  • Chemical symbols are used for easy identification.
Understanding the details of elements, like titanium and thallium, helps us predict what their characteristics will be based on where they fall on the periodic table.
Atomic Number
The atomic number is fundamental in identifying an element. It reflects the number of protons found in the nucleus of an atom for that element.
Each element has its own unique atomic number, and this directly determines its position on the periodic table.
For example, titanium (Ti) has an atomic number of 22, which means it has 22 protons. Thallium (Tl) has an atomic number of 81, indicating it has 81 protons in its atomic nucleus.
  • The atomic number defines the element's identity.
  • It is crucial for the chemical properties of the element.
  • This number helps to distinguish one element from another.
The atomic number helps in understanding the element's natural order and its potential chemical behaviors when it forms compounds.
Atomic Weight
Atomic weight, often referred to as atomic mass, is the average mass of atoms of an element. This value is based on the natural abundance of an element's isotopes.
It is usually expressed in atomic mass units (amu), which makes comparability between elements easier.
For instance, titanium has an atomic weight of approximately 47.87 amu, while thallium is significantly heavier with an atomic weight of approximately 204.38 amu.
  • Atomic weight is not usually a whole number.
  • It takes into account the presence of isotopes.
  • This value helps in calculating the mass of individual atoms and compounds.
Understanding atomic weight can aid in various calculations, including those required for chemical reactions and stoichiometry.
Chemical Symbols
Chemical symbols are shorthand notations for elements, each comprising one or two letters. These symbols allow scientists to quickly identify and communicate about elements without confusion. The first letter is always capitalized and if a second letter follows, it is lowercase.
For example, the chemical symbol for titanium is Ti, while thallium is Tl. These symbols are deeply rooted in history and have been standardized internationally to avoid mistakes.
  • Chemical symbols are derived from elements' Latin names.
  • They are essential for chemical equations and formulas.
  • Symbols must be memorized for a complete understanding of chemistry.
Knowing these symbols is key in fields ranging from chemistry and biology to physics and engineering, as they appear in numerous scientific and technical contexts.

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Most popular questions from this chapter

In 1886 Eugene Goldstein observed positively charged particles moving in the opposite direction to electrons in a cathode ray tube (illustrated below). From their mass, he concluded that these particles were formed from residual gas in the tube. For example, if the cathode ray tube contained helium, the canal rays consisted of \(\mathrm{He}^{+}\) ions. Describe a process that could lead to these ions.

Calculate the molar mass and the mass percent of each element in the blue solid compound \(\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{SO}_{4} \cdot \mathrm{H}_{2} \mathrm{O} .\) What is the mass of copper and the mass of water in 10.5 g of the compound?

Although carbon-12 is now used as the standard for atomic weights, this has not always been the case. Early attempts at classification used hydrogen as the standard, with the weight of hydrogen being set equal to 1.0000. Later attempts defined atomic weights using oxygen (with a weight of 16.0000 ). In each instance, the atomic weights of the other elements were defined relative to these masses. (To answer this question, you need more precise data on current atomic weights: \(\mathrm{H}, 1.00794 ;\) O, \(15.9994 .\)) (a) If \(\mathrm{H}=1.0000 \mathrm{u}\) was used as a standard for atomic weights, what would the atomic weight of oxygen be? What would be the value of Avogadro's number under these circumstances? (b) Assuming the standard is \(\mathrm{O}=16.0000\), determine the value for the atomic weight of hydrogen and the value of Avogadro's number.

Calculate the molar mass of each of the following compounds: (a) \(\mathrm{Fe}_{2} \mathrm{O}_{3},\) iron(III) oxide (b) \(\mathrm{BCl}_{3},\) boron trichloride (c) \(\left.\mathrm{C}_{6} \mathrm{H}_{8} \mathrm{O}_{6}, \text { ascorbic acid (vitamin } \mathrm{C}\right)\)

Estimating the radius of a lead atom. (a) You are given a cube of lead that is \(1.000 \mathrm{cm}\) on each side. The density of lead is \(11.35 \mathrm{g} /\) \(\mathrm{cm}^{3} .\) How many atoms of lead are in the sample? (b) Atoms are spherical; therefore, the lead atoms in this sample cannot fill all the available space. As an approximation, assume that \(60 \%\) of the space of the cube is filled with spherical lead atoms. Calculate the volume of one lead atom from this information. From the calculated volume (V) and the formula \((4 / 3) \pi r^{3}\) for the volume of a sphere, estimate the radius \((r)\) of a lead atom.

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