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The "alum" used in cooking is potassium aluminum sulfate hydrate, \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} \cdot x \mathrm{H}_{2} \mathrm{O} .\) To find the value of \(x,\) you can heat a sample of the compound to drive off all of the water and leave only \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} .\) Assume you heat \(4.74 \mathrm{g}\) of the hydrated compound and that the sample loses \(2.16 \mathrm{g}\) of water. What is the value of \(x ?\)

Short Answer

Expert verified
The value of \(x\) is 12.

Step by step solution

01

Determine Mass of Anhydrate

First, find the mass of the anhydrous compound after the water has been driven off. This can be done by subtracting the mass of water lost from the initial mass of the hydrated compound. \[\text{Mass of anhydrate} = 4.74\, \text{g} - 2.16\, \text{g} = 2.58\, \text{g}\]
02

Calculate Moles of Anhydrate

Next, calculate the moles of the anhydrous compound \(\text{KAl(SO}_4)_2\). Use the molar mass provided in the periodic table:\[\text{Molar Mass of } \text{KAl(SO}_4)_2 = K(39.10) + Al(26.98) + 2\times(S(32.07) + 4\times O(16.00))\]\[= 39.10 + 26.98 + 2 \times (32.07 + 64.00) = 258.21 \, \text{g/mol}\]Now:\[\text{Moles of anhydrate} = \frac{2.58\, \text{g}}{258.21\, \text{g/mol}} = 0.00999 \, \text{mol}\]
03

Calculate Moles of Water Lost

Calculate the moles of water that were lost. Use the molar mass of water (\(18.02\, \text{g/mol}\)):\[\text{Moles of } \text{H}_2\text{O} = \frac{2.16\, \text{g}}{18.02\, \text{g/mol}} = 0.1199 \, \text{mol}\]
04

Determine Value of x

Now find the value of \(x\) by dividing the moles of water lost by the moles of the anhydrate:\[x = \frac{0.1199 \, \text{mol}}{0.00999 \, \text{mol}} = 12.00\]Therefore, the value of \(x\) is 12. This indicates there are 12 water molecules per formula unit of the compound.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Molar mass calculation is a fundamental concept in chemistry, crucial for converting between grams and moles of a substance. To perform a molar mass calculation, you'll need to refer to the periodic table, where each element's atomic mass is listed. The molar mass is calculated by adding up the atomic masses of all the atoms in a compound's formula.
For example, with potassium aluminum sulfate \((\mathrm{KAl(SO}_4)_2)\), you would find the molar mass by summing:
  • the atomic mass of potassium (K): 39.10
  • the atomic mass of aluminum (Al): 26.98
  • two sulfate ions \((\mathrm{SO}_4)\)\(\Rightarrow 2 \times(32.07 + (4 \times 16.00))\)
This results in a molar mass of 258.21 g/mol for \(\mathrm{KAl(SO}_4)_2 \). Understanding how to calculate molar mass is essential for converting a substance's mass in grams to moles, which is often necessary for stoichiometric calculations.
Water of Crystallization
Water of crystallization refers to water molecules that are part of a compound's crystalline structure. It is commonly seen in hydrates, where water molecules are integrated into the crystal lattice.
A classic example is found in the hydrated form of potassium aluminum sulfate, where water molecules are a key part of the compound structure. As you determine the hydrate formula, you are essentially finding out how many water molecules are associated with each formula unit of the compound.
In practice, this might involve heating the hydrate to remove the water and analyzing the change in mass to understand the role water played in the crystalline structure. By losing water upon heating, one can determine the amount of water initially present, thus indicating how many water molecules were involved in the formation of the crystalline structure, which is crucial for determining the \(x\) value in formulas such as \(\mathrm{KAl(SO}_4)_2 \cdot x \mathrm{H}_2\mathrm{O} \). This process helps understand the stoichiometry and consumption of water molecules in such compounds.
Anhydrous Compound Analysis
Analyzing an anhydrous compound involves studying a substance that has had all its water of crystallization removed. This condition allows us to focus on the "dry" part of the compound, without the influence of water content.
When dealing with hydrated crystals, such as \(\mathrm{KAl(SO}_4)_2 \cdot x \mathrm{H}_2\mathrm{O}\), the goal of heating is to drive off the water, leaving you with an anhydrous form. By measuring the weight before and after heating, you can determine the mass of the anhydrous compound.
  • Start with the initial mass of the hydrate.
  • Subtract the mass of water lost to find the mass of the anhydrate.
This subtraction yields the mass of the anhydrous compound, crucial for further calculations like establishing the molar ratio between the anhydrous compound and the water of crystallization. Such analyses not only aid in determining the value of \(x\) in hydrates but also provide insights into the stability and composition of the anhydrous form compared to its hydrated counterpart.

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Most popular questions from this chapter

Write the formula for each of the following compounds and indicate which ones are best described as ionic: (a) sodium hypochlorite (b) boron triiodide (c) aluminum perchlorate (d) calcium acetate (e) potassium permanganate (f) ammonium sulfite (g) potassium dihydrogen phosphate (h) disulfur dichloride (i) chlorine trifluoride (j) phosphorus trifluoride

Consider an atom of \(^{64} \mathrm{Zn.}\) (a) Calculate the density of the nucleus in grams per cubic centimeter, knowing that the nuclear radius is \(4.8 \times 10^{-6} \mathrm{nm}\) and the mass of the \(^{64} \mathrm{Zn}\) atom is \(1.06 \times 10^{-22} \mathrm{g}\). (Recall that the volume of a sphere is \(\left.[4 / 3] \pi r^{3} .\right)\) (b) Calculate the density of the space occupied by the electrons in the zinc atom, given that the atomic radius is \(0.125 \mathrm{nm}\) and the electron mass is \(9.11 \times 10^{-28} \mathrm{g}\) (c) Having calculated these densities, what statement can you make about the relative densities of the parts of the atom?

The action of bacteria on meat and fish produces a compound called cadaverine. As its name and origin imply, it stinks! (It is also present in bad breath and adds to the odor of urine.) It is 58.77\% C, 13.81\% H, and 27.40\% N. Its molar mass is \(102.2 \mathrm{g} / \mathrm{mol} .\) Determine the molecular formula of cadaverine.

If Epsom salt, \(\mathrm{MgSO}_{4} \cdot x \mathrm{H}_{2} \mathrm{O},\) is heated to \(250^{\circ} \mathrm{C},\) all the water of hydration is lost. On heating a 1.687 -g sample of the hydrate, \(0.824 \mathrm{g}\) of \(\mathrm{MgSO}_{4}\) remains. How many molecules of water occur per formula unit of \(\mathrm{MgSO}_{4} ?\)

Name each of the following ionic compounds: (a) \(\mathrm{Ca}\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)_{2}\) (b) \(\mathrm{Ni}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) (c) \(\mathrm{Al}(\mathrm{OH})_{3}\) (d) \(\mathrm{KH}_{2} \mathrm{PO}_{4}\)

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