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Write formulas for all of the compounds that can be made by combining the cations \(\mathrm{NH}_{4}^{+}\) and \(\mathrm{Ni}^{2+}\) with the anions \(\mathrm{CO}_{3}^{2-}\) and \(\mathrm{SO}_{4}^{2-}.\)

Short Answer

Expert verified
The compounds are - \\(\mathrm{(NH}_4)_2\mathrm{CO}_3\\), - \\(\mathrm{(NH}_4)_2\mathrm{SO}_4\\), - \\(\mathrm{NiCO}_3\\), and - \\(\mathrm{NiSO}_4\\).

Step by step solution

01

Identify Cations and Anions

First, note the given cations: ammonium \(\mathrm{NH}_4^+\) and nickel(II) \(\mathrm{Ni}^{2+}\). The anions provided are carbonate \(\mathrm{CO}_3^{2-}\) and sulfate \(\mathrm{SO}_4^{2-}\). Each cation will be paired with each anion to form different compounds.
02

Form Compound with Ammonium and Carbonate

Combine the cation \(\mathrm{NH}_4^+\) with the anion \(\mathrm{CO}_3^{2-}\). To create a neutral compound, balance the charges: need two ammonium ions for each carbonate ion to form \(\mathrm{(NH}_4)_2\mathrm{CO}_3\).
03

Form Compound with Ammonium and Sulfate

Combine the cation \(\mathrm{NH}_4^+\) with the anion \(\mathrm{SO}_4^{2-}\). Similarly, to balance the charges, use two ammonium ions per sulfate ion to form \(\mathrm{(NH}_4)_2\mathrm{SO}_4\).
04

Form Compound with Nickel(II) and Carbonate

Combine the cation \(\mathrm{Ni}^{2+}\) with the anion \(\mathrm{CO}_3^{2-}\). Both have a charge of 2, so one nickel ion pairs with one carbonate ion to form \(\mathrm{NiCO}_3\).
05

Form Compound with Nickel(II) and Sulfate

Combine the cation \(\mathrm{Ni}^{2+}\) with the anion \(\mathrm{SO}_4^{2-}\). Again, the charges balance one-to-one, resulting in \(\mathrm{NiSO}_4\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are a class of chemical compounds made up of positively charged ions (cations) and negatively charged ions (anions). These ions form due to the transfer of electrons between atoms, resulting in charged particles. Typically, ionic compounds consist of metals and non-metals or polyatomic ions. When these oppositely charged ions come together, they form an electrically neutral compound. Ionic compounds are held together by strong electrostatic forces known as ionic bonds, which contribute to the formation of crystalline structures. For instance, in the provided exercise, we looked at ammonium and nickel(II) cations combining with carbonate and sulfate anions to form various ionic compounds.
Charge Balance
A fundamental principle in the formation of ionic compounds is ensuring overall charge neutrality. This means that the total positive charge must equal the total negative charge in the compound. Let's consider this rule with ammonium and carbonate ions. Ammonium \(\text{NH}_4^+\) carries a +1 charge, while carbonate \(\text{CO}_3^{2-}\) carries a -2 charge. To balance these, we need two ammonium ions for every carbonate ion, resulting in a neutral compound, \(\text{(NH}_4\text{)}_2\text{CO}_3\). Similarly, when nickel(II) \(\text{Ni}^{2+}\) combines with sulfate \(\text{SO}_4^{2-}\), both ions have a charge of 2, so one nickel pairs with one sulfate, forming the neutral ionic compound \(\text{NiSO}_4\). Charge balance ensures stability in the resulting compounds.
Cation and Anion Combination
Creating ionic compounds involves choosing appropriate cations and anions and matching them to form neutral combinations. In our exercise, we started with given cations: ammonium \(\text{NH}_4^+\) and nickel(II) \(\text{Ni}^{2+}\). We paired each cation with the anions carbonate \(\text{CO}_3^{2-}\) and sulfate \(\text{SO}_4^{2-}\). The task was to ensure the charges were balanced for stable compound formation. For example, ammonium can pair with carbonate by using two ammonium ions per carbonate ion. These pairings result in the production of different compounds like \(\text{(NH}_4\text{)}_2\text{CO}_3\) and \(\text{NiCO}_3\), both of which demonstrate balanced ionic interactions.
Chemical Formula Writing
Writing chemical formulas for ionic compounds involves using symbols to represent the types of ions involved and their relative numbers. This requires understanding how to balance the charges of the ions. In our examples, we wrote the formula for ammonium sulfate as \(\text{(NH}_4\text{)}_2\text{SO}_4\), indicating two ammonium cations for every sulfate anion. Meanwhile, nickel(II) carbonate is written as \(\text{NiCO}_3\), showing a one-to-one ratio of cations to anions. Understanding the charges and how they combine is essential for writing accurate chemical formulas. This task is vital for chemists to ensure proper communication about the composition of compounds.

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Most popular questions from this chapter

A piece of nickel foil, \(0.550 \mathrm{mm}\) thick and \(1.25 \mathrm{cm}\) square, is allowed to react with fluorine, \(\mathrm{F}_{2},\) to give a nickel fluoride. (a) How many moles of nickel foil were used? (The density of nickel is \(8.902 \mathrm{g} / \mathrm{cm}^{3} .\) ) (b) If you isolate \(1.261 \mathrm{g}\) of the nickel fluoride, what is its formula? (c) What is its complete name?

Mass spectrometric analysis showed that there are four isotopes of an unknown element having the following masses and abundances: $$\begin{array}{|c|c|c|c|}\hline \text { Isotope } & \begin{array}{c}\text { Mass } \\\\\text { Number }\end{array} & \begin{array}{c}\text { Isotope } \\\\\text { Mass }\end{array} & \begin{array}{c}\text { Abundance } \\\\(\%)\end{array} \\\\\hline 1 & 136 & 135.9090 & 0.193 \\\\\hline 2 & 138 & 137.9057 & 0.250 \\\\\hline 3 & 140 & 139.9053 & 88.48 \\\\\hline 4 & 142 & 141.9090 & 11.07 \\\\\hline\end{array}$$ Three elements in the periodic table that have atomic weights near these values are lanthanum (La), atomic number \(57,\) atomic weight 138.9055 cerium (Ce), atomic number \(58,\) atomic weight \(140.115 ;\) and praseodymium \((\mathrm{Pr}),\) atomic number \(59,\) atomic weight \(140.9076 .\) Using the data above, calculate the atomic weight, and identify the element if possible.

Malic acid, an organic acid found in apples, contains \(\mathrm{C}, \mathrm{H},\) and \(\mathrm{O}\) in the following ratios: \(\mathrm{C}_{1} \mathrm{H}_{1.50} \mathrm{O}_{1.25} .\) What is the empirical formula of malic acid?

The weight percent of oxygen in an oxide that has the formula \(\mathrm{MO}_{2}\) is \(15.2 \% .\) What is the molar mass of this compound? What element or elements are possible for \(\mathrm{M}\) ?

Chromium is obtained by heating chromium(III) oxide with carbon. Calculate the mass percent of chromium in the oxide, and then use this value to calculate the quantity of \(\mathrm{Cr}_{2} \mathrm{O}_{3}\) required to produce \(850 \mathrm{kg}\) of chromium metal.

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