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Which product, Ca or \(\mathrm{H}_{2}\), is more likely to form at the cathode in the electrolysis of \(\mathrm{CaCl}_{2}\) ? Explain your reasoning.

Short Answer

Expert verified
Hydrogen ( \(\text{H}_2\)) is more likely to form at the cathode.

Step by step solution

01

Understand Electrolysis of CaCl2

Electrolysis involves passing an electric current through a compound to cause a chemical change. At the cathode, reduction occurs. For the electrolysis of calcium chloride (\(\text{CaCl}_2\), we need to determine which species is more likely to be reduced: calcium ions (\(\text{Ca}^{2+}\)) or hydrogen ions (\(\text{H}^{+}\) from water).
02

Identify Possible Reactions

At the cathode, two possible reduction reactions can occur:1. Reduction of calcium ions: \(\text{Ca}^{2+} + 2e^- \rightarrow \text{Ca}\)2. Reduction of water: \(2\text{H}_2\text{O} + 2e^- \rightarrow \text{H}_2 + 2\text{OH}^-\).
03

Compare Standard Electrode Potentials

To determine which reaction is more favorable, compare the standard electrode potentials:- \(\text{E}^0(\text{Ca}^{2+}/\text{Ca}) = -2.87\,\text{V}\)- \(\text{E}^0(\text{H}^{+}/\text{H}_2) = 0.00\,\text{V}\)Since \(0.00\,\text{V}\) is less negative than \(-2.87\,\text{V}\), the reduction of hydrogen is thermodynamically more favorable than the reduction of calcium.
04

Conclusion

Given the electrode potentials, hydrogen (\(\text{H}_2\)) will preferentially be produced over calcium (\(\text{Ca}\)) at the cathode during electrolysis of \(\text{CaCl}_2\). This is because the reduction potential of hydrogen ions is higher than that of calcium ions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Electrode Potentials
Standard electrode potentials are crucial in determining the likelihood of a reaction occurring at an electrode during electrolysis. They are a measure of the tendency of a chemical species to acquire electrons and be reduced. For each species, a standard electrode potential, denoted as \(E^0\), is gathered under standard conditions. These conditions typically include a temperature of 298 Kelvin, a 1 M concentration for the ions, and a pressure of 1 atmosphere for gases.

In the context of which product forms at the cathode during electrolysis, comparing their \(E^0\) values helps us predict which reduction reaction is more favorable. A less negative or more positive standard electrode potential indicates a higher likelihood of reduction occurring for that species. For instance, in the electrolysis of \(\text{CaCl}_2\), we compare the \(E^0\) values for \(\text{Ca}^{2+}/\text{Ca}\) and \(\text{H}^{+}/\text{H}_2\).

- \(E^0(\text{Ca}^{2+}/\text{Ca}) = -2.87 \, \text{V}\)- \(E^0(\text{H}^{+}/\text{H}_2) = 0.00 \, \text{V}\)

Hydrogen's electrode potential is higher, indicating that hydrogen ions are more easily reduced than calcium ions under these conditions. Therefore, hydrogen production is favored at the cathode.
Reduction Reactions
Reduction reactions are processes where a species gains electrons, decreasing its oxidation state. In electrolysis, these reactions occur at the cathode, where positive ions move to acquire electrons.

During the electrolysis of \(\text{CaCl}_2\), two main reduction reactions can occur, each involving a different species:
  • Reduction of calcium ions: \(\text{Ca}^{2+} + 2e^- \rightarrow \text{Ca}\)
  • Reduction of water or hydrogen ions from water: \(2\text{H}_2\text{O} + 2e^- \rightarrow \text{H}_2 + 2\text{OH}^-\)
The reaction that occurs more readily will be the one with the higher standard electrode potential. As evidenced by the potential values provided, the reduction of hydrogen ions is preferred, leading to the formation of \(\text{H}_2\) gas at the cathode. This preference is due to the less negative or more positive potential for the hydrogen reduction reaction. Thus, despite both reactions being possible, the thermodynamically favorable one will dominate.

Reducing the more electropositive ion first ensures a consistent and predictable result during electrolysis experiments.
Cathode Processes
Cathode processes in electrolysis are fundamental to understanding which substances are produced during the process. The cathode serves as the site for reduction reactions; thus, it attracts cations or positively charged ions that gain electrons.

In the electrolysis setup, electrons move from the external circuit into the cathode. This electron flow allows the positive ions present in the electrolytic solution to be reduced. Let's consider the example of \(\text{CaCl}_2\) electrolysis. Here, calcium ions \((\text{Ca}^{2+})\) and hydrogen ions \((\text{H}^+)\) are in competition at the cathode.

- At the cathode, the species with the higher reduction potential are more likely to gain electrons.- In this particular example, the reduction of \(\text{H}^+\) to \(\text{H}_2\) is more thermodynamically favorable than reducing \(\text{Ca}^{2+}\) to calcium metal.

Therefore, hydrogen gas is the preferred product at the cathode during the electrolysis of \(\text{CaCl}_2\). This understanding of cathode processes and the role they play in electrolysis helps predict and control the outcomes of electrochemical reactions.

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Most popular questions from this chapter

You want to set up a series of voltaic cells with specific cell potentials. \(A\) Zn \(^{2+}(\text { aq, } 1.0 \mathrm{M}) | \mathrm{Zn}(\mathrm{s})\) half- cell is in one compartment. Identify several half-cells that you could use so that the cell potential will be close to (a) \(1.1 \mathrm{V}\) and (b) \(0.50 \mathrm{V}\). Consider cells in which the zinc cell can be either the cathode or the anode.

Predict the products formed in the electrolysis of an aqueous solution of \(\mathrm{CdSO}_{4}\)

A Living organisms derive energy from the oxidation of food, typified by glucose. $$ \mathrm{C}_{0} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{aq})+6 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{g})+6 \mathrm{H}_{2} \mathrm{O}(\ell) $$ Electrons in this redox process are transferred from glucose to oxygen in a series of at least 25 steps. It is instructive to calculate the total daily current flow in a typical organism and the rate of energy expenditure (power). (See T. P. Chirpich: Journal of Chemical Education, Vol. \(52,\) p. 99 1975.) (a) The molar enthalpy of combustion of glucose is \(-2800 \mathrm{kJ} / \mathrm{mol}\) -nan. If you are on a typical daily diet of 2400 Cal (kilocalories), what amount of glucose (in moles) must be consumed in a day if glucose is the only source of energy? What amount of \(\mathrm{O}_{2}\) must be consumed in the oxidation process? (b) How many moles of electrons must be supplied to reduce the amount of \(\mathrm{O}_{2}\) calculated in part (a)? (c) Based on the answer in part (b), calculate the current flowing, per second, in your body from the combustion of glucose. (d) If the average standard potential in the electron transport chain is \(1.0 \mathrm{V},\) what is the rate of energy expenditure in watts?

Two \(\mathrm{Ag}^{+}(\mathrm{aq}) | \mathrm{Ag}(\mathrm{s})\) half-cells are constructed. The first has \(\left|\mathrm{Ag}^{+}\right|=1.0 \mathrm{M},\) the second has \(\left[\mathrm{Ag}^{+}\right]=\) \(1.0 \times 10^{-5} \mathrm{M} .\) When linked together with a salt bridge and external circuit, a cell potential is observed. (This kind of voltaic cell is referred to as a concentration cell.) (a) Draw a picture of this cell, labeling all components. Indicate the cathode and the anode, and indicate in which direction electrons flow in the external circuit. (b) Calculate the cell potential at \(298 \mathrm{K}\)

The simplest way to write the reaction for discharge in a lithium-ion battery is Li(on carbon)(s) \(+\mathrm{CoO}_{2}(\mathrm{s}) \rightarrow 6 \mathrm{C}(\mathrm{s})+\mathrm{LiCoO}_{2}(\mathrm{s})\) (a) What are the oxidation numbers for cobalt in the two substances in the battery? (b) In such a battery, what reaction occurs at the cathode? At the anode? (c) An electrolyte is needed for ion conduction within the battery. From what you know about lithium chemistry, can the electrolyte in the battery be dissolved in water?

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