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Determine whether the reactions listed below are entropy-favored or disfavored under standard conditions. Predict how an increase in temperature will affect the value of \(\Delta_{\mathrm{r}} G^{\circ}.\) (a) \(\mathrm{I}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{I}(\mathrm{g})\) (b) \(2 \mathrm{SO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{g})\) (c) \(\operatorname{sicl}_{4}(g)+2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{SiO}_{2}(\mathrm{s})+4 \mathrm{HCl}(\mathrm{g})\) (d) \(\mathrm{P}_{4}(\mathrm{s}, \text { white })+6 \mathrm{H}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{PH}_{3}(\mathrm{g})\)

Short Answer

Expert verified
(a), (c), and (d) are entropy-favored; (b) is entropy-disfavored.

Step by step solution

01

Analyze Reaction (a)

For \( \mathrm{I}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{I}(\mathrm{g}) \), we start with a diatomic gas and break it into two monoatomic gases. This transformation increases disorder, or entropy (\( \Delta S > 0 \)). Thus, the reaction is entropy-favored. An increase in temperature will further increase \( T\Delta S \), making \( \Delta_r G^{\circ} \) likely to decrease (more negative).
02

Analyze Reaction (b)

For \( 2 \mathrm{SO}_{2}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{SO}_{3}(\mathrm{g}) \), we move from three moles of gas to two moles, which decreases disorder (\( \Delta S < 0 \)). Hence, the reaction is entropy-disfavored. Increasing temperature will make \( T\Delta S \) more negative, potentially increasing \( \Delta_r G^{\circ} \) (less negative).
03

Analyze Reaction (c)

In \( \operatorname{sicl}_{4}(g) + 2 \mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{SiO}_{2}(\mathrm{s}) + 4 \mathrm{HCl}(\mathrm{g}) \), we convert a solid and liquids into gases, increasing disorder (\( \Delta S > 0 \)). Therefore, the reaction is entropy-favored. An increase in temperature should decrease \( \Delta_r G^{\circ} \) (more negative) due to the positive \( T\Delta S \).
04

Analyze Reaction (d)

For \( \mathrm{P}_{4}(\mathrm{s}, \text{white})+6 \mathrm{H}_{2}(\mathrm{g}) \rightarrow 4 \mathrm{PH}_{3}(\mathrm{g}) \), we begin with a solid and gases and generate more molecules of gas, increasing disorder (\( \Delta S > 0 \)). This reaction is entropy-favored. Increasing temperature will likely decrease \( \Delta_r G^{\circ} \) (more negative) because of the positive \( T\Delta S \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gibbs Free Energy
Gibbs Free Energy, represented as \( \Delta G \), is a crucial concept in chemistry used to predict whether a chemical reaction will occur spontaneously. It combines enthalpy (\( H \)) and entropy (\( S \)) into a single value, defined by the equation \( \Delta G = \Delta H - T \Delta S \), where \( T \) is the temperature in Kelvin.

A reaction is spontaneous if \( \Delta G \) is negative. Under standard conditions, the term \( T \Delta S \) plays a significant role. An increase in temperature can impact \( \Delta G \) significantly by altering this term. If the change in entropy (\( \Delta S \)) is positive, a higher temperature makes \( T \Delta S \) more positive, possibly decreasing \( \Delta G \) further into the negative range, favoring the reaction.

In contrast, if \( \Delta S \) is negative, increasing the temperature may lead to a positive increase in \( T \Delta S \), pushing \( \Delta G \) towards positive values, which can inhibit spontaneity. So, by examining \( \Delta H \) and \( \Delta S \), you can predict reaction behavior at various temperatures.
Thermodynamics
Thermodynamics is a branch of science that examines heat, energy, and work, focusing on how energy transforms in chemical reactions. It offers laws and principles that help predict reaction spontaneity and feasibility.

There are three main laws of thermodynamics:
  • The First Law: Energy cannot be created or destroyed, only transformed. It helps track energy changes in a reaction.
  • The Second Law: Entropy of an isolated system always increases. It indicates that disorder is favored, which aids in understanding reactions where \( \Delta S > 0 \).
  • The Third Law: As temperature approaches absolute zero, the entropy of a perfect crystal approaches zero.
Thermodynamics provides a framework to calculate key properties like entropy and enthalpy changes, utilizing them to determine \( \Delta G \). This helps predict if and how a reaction will occur under different conditions, offering insight into energy requirements and efficiency.
Predicting Reaction Spontaneity
Predicting reaction spontaneity involves assessing the signs and magnitudes of \( \Delta H \), \( \Delta S \), and temperature. These factors come together in the Gibbs Free Energy equation to determine if a reaction is favorable or not.

Here's a step-by-step guide to predicting spontaneity:
  • Calculate \( \Delta H \): Determine if the reaction is exothermic (releases heat, \( \Delta H < 0 \)) or endothermic (absorbs heat, \( \Delta H > 0 \)).
  • Assess \( \Delta S \): Decide if the reaction leads to more disorder (\( \Delta S > 0 \)) or less (\( \Delta S < 0 \)).
  • Evaluate Temperature Impact: Consider how temperature changes will affect \( T \Delta S \).
A negative \( \Delta G \) indicates a spontaneous reaction. For example, if \( \Delta H \) is negative and \( \Delta S \) is positive, the reaction is generally spontaneous at all temperatures. However, if both \( \Delta H \) and \( \Delta S \) are negative, increasing temperature may make the reaction non-spontaneous.

Understanding these relationships helps chemists and students predict how external conditions influence chemical processes, ensuring they harness reactions effectively for applications like energy production and synthesis.

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Most popular questions from this chapter

The ionization constant, \(K_{\mathrm{a}},\) for acetic acid is \(1.8 \times\) \(10^{-5}\) at \(25^{\circ} \mathrm{C} .\) What is the value of \(\Delta_{\mathrm{r}} \mathrm{G}^{\circ}\) for this reaction? Is this reaction product- or reactantfavored at equilibrium?

Predict whether each of the following processes results in an increase in entropy in the system. (Define reactants and products as the system.) (a) Water vapor condenses to liquid water at \(90^{\circ} \mathrm{C}\) and 1 atm pressure. (b) The exothermic reaction of \(\mathrm{Na}(\mathrm{s})\) and \(\mathrm{Cl}_{2}(\mathrm{g})\) forms \(\mathrm{NaCl}(\mathrm{s})\) (c) The endothermic reaction of \(\mathrm{H}_{2}\) and \(\mathrm{I}_{2}\) produces an equilibrium mixture of \(\mathrm{H}_{2}(\mathrm{g})\) \(\mathrm{I}_{2}(\mathrm{g}),\) and \(\mathrm{HI}(\mathrm{g})\) (d) Solid NaCl dissolves in water forming a saturated solution.

The normal melting point of benzene, \(\mathrm{C}_{6} \mathrm{H}_{6},\) is \(5.5^{\circ} \mathrm{C} .\) For the process of melting, what is the sign of each of the following? (a) \(\Delta_{\mathrm{r}} H^{\circ}\) (b) \(\Delta_{\mathrm{r}} S^{\circ}\) (c) \(\Delta_{r} G^{\circ}\) at \(5.5^{\circ} \mathrm{C}\) (d) \(\Delta_{\mathrm{r}} G^{\circ}\) at \(0.0^{\circ} \mathrm{C}\) (e) \(\Delta_{r} G^{\circ}\) at \(25.0^{\circ} \mathrm{C}\)

Estimate the boiling point of water in Denver, Colorado (where the altitude is \(1.60 \mathrm{km}\) and the atmospheric pressure is \(630 \mathrm{mm} \mathrm{Hg} \text { or } 0.840 \mathrm{bar}).\)

Decide whether each of the following statements is true or false. If false, rewrite it to make it true. (a) The entropy of a substance increases on going from the liquid to the vapor state at any temperature. (b) An exothermic reaction will always be spontaneous. (c) Reactions with a positive \(\Delta_{r} H^{\circ}\) and a positive \(\Delta_{\mathrm{r}} S^{\circ}\) can never be product-favored. (d) If \(\Delta_{r} G^{\circ}\) for a reaction is negative, the reaction will have an equilibrium constant greater than 1.

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