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Which should be the stronger Bronsted acid, \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) or \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} ?\)

Short Answer

Expert verified
\(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) is the stronger Bronsted acid.

Step by step solution

01

Understand the Concept of Bronsted Acids

Bronsted acids are substances that can donate a proton (H鈦) in a chemical reaction. The more a molecule can release a proton, the stronger it is as a Bronsted acid.
02

Analyze the Given Complexes

The two complexes given are \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) and \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\). In both, vanadium is surrounded by six water molecules, however, the charge on the metal cation differs.
03

Assess the Charge Impact on Acidity

The charge on the metal affects its ability to polarize and weaken the O-H bonds in the water molecules. A higher positive charge on the metal ion leads to greater polarization of water molecules, making it easier for the O-H bond to break and release a proton. Therefore, an ion with a higher positive charge typically makes the complex a stronger acid.
04

Compare the Complexes

Compare \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) and \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\). The latter has a higher positive charge on the vanadium ion (3+ compared to 2+), meaning it can polarize the bound water molecules more effectively, enhancing its ability to donate protons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proton Donation
Proton donation is a fundamental concept when discussing Bronsted acids. Bronsted acids are defined by their ability to donate protons, which are essentially hydrogen ions, denoted as H鈦. When an acid donates a proton, it can participate in various chemical reactions, often increasing the acidity of a solution. In the case of the complexes \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) and \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\), the strength of the acid is determined by how readily the complex can release a proton into the surrounding environment. More proton donation implies a stronger acid, since the presence of more free protons correlates with higher acidity.
Complex Ions
Complex ions are structures formed from a central metal cation surrounded by molecules or ions, often referred to as ligands. In our example, vanadium acts as the central metal ion bonded to six water molecules, forming the complex ions \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) and \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\). These complex structures are integral to many chemical reactions, especially in aqueous environments. The ability of water to coordinate and stabilize metal ions forms the basis of complex ion chemistry. The behavior of these ions, including their acidity, depends greatly on the charge of the central metal ion. Variations in charge influence the surrounding electronic environment and can dramatically alter chemical properties.
Metal Cation Charge
The charge on a metal cation is crucial to understanding how a complex will behave as a Bronsted acid. The metal cation charge refers to how many positive charges are present on the metal ion within the complex. For example, the \[\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\] complex has a higher charge (+3) compared to \[\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\] which has a +2 charge. This increased positive charge leads to stronger attraction between the vanadium ion and the surrounding water molecules. A higher charge results in enhanced effectiveness at pulling electrons from the water鈥檚 oxygen atom, thus facilitating the release of protons from the O-H bond. This results in higher acidity for the \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\) complex.
Water Polarization
Water polarization occurs when the electric field of a cation alters the distribution of electrons in water molecules. When a metal cation is surrounded by water molecules, like in \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \)or\(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\), the positive charge of the metal can distort the electrons around the oxygen atom in water. A cation with a larger charge, such as +3, will cause more pronounced polarization of the surrounding water compared to a +2 charge. This polarization weakens the O-H bond in the water, making it more likely for the bond to break and release a proton into the solution. As a result, the complex becomes more acidic with increasing metal cation charge, as seen in the stronger acidity of \(\left[\mathrm{V}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+}\). Understanding water polarization is essential to grasp why complexes with higher charge metal ions display more significant acidity.

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Most popular questions from this chapter

Which is the stronger of the following two acids? (a) benzoic acid, \(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CO}_{2} \mathrm{H}, \mathrm{p} K_{\mathrm{a}}=4.20\) (b) 2 -chlorobenzoic acid, \(\mathrm{ClC}_{6} \mathrm{H}_{4} \mathrm{CO}_{2} \mathrm{H}, \mathrm{p} K_{3}=2.90\)

Equal molar quantities of ammonia and sodium dihydrogen phosphate \(\left(\mathrm{NaH}_{2} \mathrm{PO}_{4}\right)\) are mixed. (a) Write a balanced, net ionic equation for the acid-base reaction that can, in principle, occur. (b) Does the equilibrium lie to the right or left?

In each of the following acid-base reactions, identify the Bronsted acid and base on the left and their conjugate partners on the right. (a) \(\mathrm{HCO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell) \rightleftharpoons\) \(\mathrm{HCO}_{2}^{-}(\mathrm{aq})+\mathrm{H}_{3} \mathrm{O}^{+}(\mathrm{aq})\) (b) \(\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{S}(\mathrm{aq}) \rightleftarrows\) \(\mathrm{NH}_{4}^{+}(\mathrm{aq})+\mathrm{HS}^{-}(\mathrm{aq})\) (c) \(\mathrm{HSO}_{4}^{-}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \rightleftarrows\) \(\mathrm{SO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)\)

Prove that \(K_{\mathrm{a} 1} \times K_{\mathrm{b} 2}=K_{\mathrm{w}}\) for oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) by adding the chemical equilibrium expressions that correspond to first ionization step of the acid in water with the second step of the reaction of the fully deprotonated base, \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-},\) with water.

The \(\mathrm{pH}\) of a solution of \(\mathrm{Ba}(\mathrm{OH})_{2}\) is 10.66 at \(25^{\circ} \mathrm{C} .\) What is the hydroxide ion concentration in the solution? If the solution volume is \(125 \mathrm{mL}\) what mass of \(\mathrm{Ba}(\mathrm{OH})_{2}\) must have been dissolved?

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