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You mix 30.0 mL of 0.15 M NaOH with \(30.0 \mathrm{mL}\) of \(0.15 \mathrm{M}\) acetic acid. What molecules and ions exist in this solution? List them in order of decreasing concentration.

Short Answer

Expert verified
H鈧侽, Na鈦, CH鈧僀OO鈦, trace CH鈧僀OOH.

Step by step solution

01

Determine the reaction

The reaction that occurs when NaOH is mixed with acetic acid (CH鈧僀OOH) is a neutralization reaction:\[ \text{NaOH} + \text{CH}_3\text{COOH} \rightarrow \text{Na}^+ + \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \]This equation shows that sodium acetate (NaCH鈧僀OO) and water (H鈧侽) are formed.
02

Calculate moles of each reactant

Calculate the moles of NaOH and CH鈧僀OOH. Both are 0.15 M solutions, and each has a volume of 0.03 L (30.0 mL):Moles of NaOH = \(0.15 \text{ M} \times 0.03 \text{ L} = 0.0045 \text{ moles} \)Moles of \(\text{CH}_3\text{COOH} = 0.15 \text{ M} \times 0.03 \text{ L} = 0.0045 \text{ moles}\)
03

Analyze the complete neutralization

Since the moles of NaOH equals the moles of CH鈧僀OOH, complete neutralization occurs forming an equal amount of CH鈧僀OO鈦 and Na鈦 ions with water. No NaOH or CH鈧僀OOH will remain unreacted. The reaction produces 0.0045 moles of CH鈧僀OO鈦 and Na鈦.
04

Calculate total volume and concentration

The total volume of the solution is 60.0 mL or 0.060 L (30.0 mL NaOH + 30.0 mL CH鈧僀OOH).Concentration of \( \text{CH}_3\text{COO}^- \) = Concentration of \( \text{Na}^+ \) = \( \frac{0.0045 \text{ moles}}{0.060 \text{ L}} = 0.075 \text{ M}\).
05

Determine additional species in solution

Since water (H鈧侽) is the solvent, it is present in large amounts. Acetic acid is a weak acid, thus there's a slight presence of undissociated CH鈧僀OOH, but it is not significant compared to ions from the neutralization.
06

List species in order of concentration

1. Water (H鈧侽) - It is the solvent and present in the highest concentration.2. \(\text{Na}^+\) and \(\text{CH}_3\text{COO}^-\) - Each at 0.075 M.3. Trace amounts of undissociated acetic acid \(\text{CH}_3\text{COOH}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Reaction
An acid-base reaction is a type of chemical reaction characterized by the exchange of one or more hydrogen ions (H鈦) between species that can donate protons (acids) and species that can accept protons (bases). When studying such reactions, a neutralization process becomes essential to understand. In this process, an acid reacts with a base to form water and a salt.

For instance, in the reaction between sodium hydroxide (NaOH), a strong base, and acetic acid (CH鈧僀OOH), a weak acid, we see such a neutralization taking place. The equation representing this reaction is: \[\text{NaOH} + \text{CH}_3\text{COOH} \rightarrow \text{Na}^+ + \text{CH}_3\text{COO}^- + \text{H}_2\text{O} \\] This results in sodium acetate (NaCH鈧僀OO) and water (H鈧侽), demonstrating a classic acid-base reaction where the strong base neutralizes the weak acid. Understanding how these types of reactions work is vital for deciphering the behavior of different chemical species in a solution.
Ionic Equations
Ionic equations are simplified versions of chemical equations that show the ions present in a reaction, making them particularly useful for understanding acid-base reactions. In these equations, compounds that exist as ions in a solution are written in ionic form, while non-ionic compounds are written in molecular form.

Consider the neutralization reaction of NaOH and CH鈧僀OOH. In aqueous solutions, NaOH dissociates into \(\text{Na}^+\text{ and }\text{OH}^-\), and CH鈧僀OOH remains mostly as molecules but partially dissociates into \(\text{CH}_3\text{COO}^-\text{ and H}^+\). The net ionic equation for the neutralization is:
  • \(\text{OH}^- + \text{H}^+ \rightarrow \text{H}_2\text{O}\) - shows the core neutralization process.
The ions \\(\text{Na}^+\)\text{ and }\(\text{CH}_3\text{COO}^-\) remain in solution and balance the equation, ensuring both mass and charge are conserved.
Solution Concentration
Solution concentration is the amount of a substance (solute) present in a given quantity of solvent or solution. It's a crucial parameter in chemistry, expressed usually in molarity (M), which is moles of solute per liter of solution.

In the reaction of 30.0 mL of 0.15 M NaOH with 30.0 mL of 0.15 M CH鈧僀OOH, both substances initially have equal concentrations. After the neutralization reaction completes, the volume of the solution becomes 60.0 mL, and the resulting concentrations change.
  • The concentration of each product, \(\text{Na}^+\) and \(\text{CH}_3\text{COO}^-\), can be calculated: \[\frac{0.0045 \text{ moles}}{0.060 \text{ L}} = 0.075 \text{ M}\]
Thus, both ions are present in equal concentrations, illustrating how the mixing and reaction of solutions can alter concentration values.
Weak Acids
Weak acids are those that do not completely dissociate in water. Unlike strong acids, which fully release their hydrogen ions, weak acids only partially ionize. This partial dissociation means that weak acids maintain an equilibrium between their ionized and non-ionized forms in solution.

Acetic acid (CH鈧僀OOH) is a classic example of a weak acid. In aqueous solution, only a small portion of acetic acid molecules release hydrogen ions to form acetate ions (CH鈧僀OO鈦). This reflects the primary behavior that distinguishes weak acids from their stronger counterparts.
  • In the neutralization reaction with NaOH, this characteristic results in the complete consumption of the weak acid with no significant leftover hydrogen ions present.
  • The reaction reaches completion primarily due to the base being strong enough to drive the equilibrium towards products entirely.
Thus, understanding the behavior of weak acids helps predict the extent and products of reactions they participate in.

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