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What is the sum of the oxidation numbers of all the atoms in each of the following polyatomic ions? (a) \(\mathrm{OH}^{-}\) (b) \(\mathrm{NH}_{4}^{+} ;\) (c) \(\mathrm{SO}_{4}^{2-} ;\) (d) \(\mathrm{PO}_{4}^{3-}\)

Short Answer

Expert verified
(a) OH鈦 (b) NH鈧勨伜 (c) SO鈧劼测伝 (d) PO鈧劼斥伝 Answer: (a) The sum of the oxidation numbers of the atoms in OH鈦 is -1. (b) The sum of the oxidation numbers of the atoms in NH鈧勨伜 is +1. (c) The sum of the oxidation numbers of the atoms in SO鈧劼测伝 is -2. (d) The sum of the oxidation numbers of the atoms in PO鈧劼斥伝 is -3.

Step by step solution

01

(a) Assign oxidation numbers to atoms in OH鈦

To assign oxidation numbers to the atoms in OH鈦: 1. Oxygen usually has an oxidation number of -2. 2. Hydrogen usually has an oxidation number of +1. The sum of the oxidation numbers of the atoms in OH鈦 = -2 + 1 = -1, which agrees with the charge of the ion.
02

(b) Assign oxidation numbers to atoms in NH鈧勨伜

To assign oxidation numbers to the atoms in NH鈧勨伜: 1. Hydrogen usually has an oxidation number of +1. 2. Nitrogen usually has an oxidation number of -3. However, in this case, it must have an oxidation number of -3 + 4 = +1 to agree with the charge of the ion. The sum of the oxidation numbers for the atoms in NH鈧勨伜 = 1 + (4 脳 1) = +1, which agrees with the charge of the ion.
03

(c) Assign oxidation numbers to atoms in SO鈧劼测伝

To assign oxidation numbers to the atoms in SO鈧劼测伝: 1. Oxygen usually has an oxidation number of -2. 2. Sulfur usually has an oxidation number of +4 or +6. In this case, sulfur must have an oxidation number of -8 + 6 = +6 to agree with the charge of the ion. The sum of the oxidation numbers for the atoms in SO鈧劼测伝 = 6 + (4 脳 -2) = -2, which agrees with the charge of the ion.
04

(d) Assign oxidation numbers to atoms in PO鈧劼斥伝

To assign oxidation numbers to the atoms in PO鈧劼斥伝: 1. Oxygen usually has an oxidation number of -2. 2. Phosphorus usually has an oxidation number of +3 or +5. In this case, phosphorus must have an oxidation number of -8 + 5 = +5 to agree with the charge of the ion. The sum of the oxidation numbers for the atoms in PO鈧劼斥伝 = 5 + (4 脳 -2) = -3, which agrees with the charge of the ion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polyatomic Ions
Polyatomic ions are charged particles composed of two or more atoms covalently bonded together. These atoms act as a single charged unit. Each ion carries a charge that is the result of the collective oxidation states of its constituent atoms. Understanding polyatomic ions is crucial in chemistry because they frequently participate in chemical reactions, much like single atom ions. Examples of polyatomic ions include hydroxide (OH鈦), ammonium (NH鈧勨伜), sulfate (SO鈧劼测伝), and phosphate (PO鈧劼斥伝).

In each of these examples, the overall charge of the ion is determined by the sum of the oxidation numbers of its atoms, which balances out to match the ion's net charge. The structure of polyatomic ions is such that the atoms share electrons, leading to the formation of stable ions with distinct charges.
Chemical Reactions
Chemical reactions involve the transformation of substances through the breaking and forming of chemical bonds. When polyatomic ions participate in chemical reactions, they often preserve their structure by moving as a single unit. This is because the atoms within a polyatomic ion are covalently bonded, making these ions act like individual entities.

In a chemical reaction, the rearrangement of atoms and redistribution of electrons can affect the oxidation states of the atoms involved. Understanding how polyatomic ions interact during reactions is key to predicting the outcome of these processes. Chemical reactions often involve the transfer of electrons, especially in redox reactions, where oxidation states are key to balancing equations and identifying which atoms are oxidized or reduced.
Oxidation States
Oxidation states, also known as oxidation numbers, are a way of keeping track of electrons in chemical compounds, particularly during redox reactions. An oxidation number is assigned to each atom in a molecule or polyatomic ion, signifying the number of electrons lost or gained by the atom relative to its elemental state.

For example, oxygen often carries an oxidation state of -2, while hydrogen typically has a +1 oxidation state. The sum of the oxidation numbers in a molecule or polyatomic ion equals the overall charge on the compound. Understanding oxidation states enables chemists to predict reactivity and the transfer of electrons in reactions. It also helps in deducing the structure of complex molecules and determining how different elements are bonded within chemical compounds.
Ion Charge Balance
Ion charge balance refers to the equilibrium of charges in a compound, ensuring that the overall charge equals the sum of the charges of the ions it contains. In the context of polyatomic ions, the oxidation numbers of the individual atoms must sum up to the ion's total charge.

Take the sulfate ion (SO鈧劼测伝) for example. Sulfur and oxygen's oxidation numbers must collectively equal the -2 charge of the ion, which is achieved when sulfur has an oxidation number of +6 and each oxygen has an oxidation number of -2. Balancing these numbers is essential for understanding how ions behave in chemical bonding and reactions.

The concept of ion charge balance is key in writing balanced chemical equations. It ensures conservation of mass and charge, principles that are fundamental to accurately describing chemical processes.

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Most popular questions from this chapter

The stalactites and stalagmites in most caves are made of calcium carbonate (see Figure 8.10 ). In the Lower Kane Cave in Wyoming, however, they are made of gypsum (calcium sulfate). The presence of \(\mathrm{CaSO}_{4}\) is explained by the following sequence of reactions: $$ \begin{array}{c} \mathrm{H}_{2} \mathrm{S}(a q)+2 \mathrm{O}_{2}(g) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \\ \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaSO}_{4}(s)+\mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{CO}_{2}(g) \end{array} $$ a. Which (if either) of these reactions is a redox reaction? b. Write a net ionic equation for the reaction of \(\mathrm{H}_{2} \mathrm{SO}_{4}\) with \(\mathrm{CaCO}_{3}\) c. How would the net ionic equation be different if the reaction were written as follows? $$ \mathrm{H}_{2} \mathrm{SO}_{4}(a q)+\mathrm{CaCO}_{3}(s) \rightarrow \mathrm{CaSO}_{4}(s)+\mathrm{H}_{2} \mathrm{CO}_{3}(a q) $$

Give the formulas of two strong bases and two weak bases.

The water-soluble gas \(\mathrm{ClO}_{2}\) is known as an oxidative biocide. It destroys bacteria by oxidizing their cell walls and viruses by attacking their viral envelopes. \(\mathrm{ClO}_{2}\) may be prepared for use as a decontaminating agent from several different starting materials in slightly acidic solutions. Complete and balance the following chemical reactions for the synthesis of \(\mathrm{ClO}_{2}\) a. \(\mathrm{ClO}_{3}^{-}(a q)+\mathrm{SO}_{2}(g) \rightarrow \mathrm{ClO}_{2}(g)+\mathrm{SO}_{4}^{2-}(a q)\) b. \(\mathrm{ClO}_{3}^{-}(a q)+\mathrm{Cl}^{-}(a q) \rightarrow \mathrm{ClO}_{2}(g)+\mathrm{Cl}_{2}(g)\) c. \(\mathrm{ClO}_{3}^{-}(a q)+\mathrm{Cl}_{2}(g) \rightarrow \mathrm{ClO}_{2}(g)+\mathrm{O}_{2}(g)\)

Eutrophication, the rapid growth of algae and the death of fish, may be caused by the presence of an excess of phosphates in water. Treatment plants that process sewage may add \(\mathrm{Ca}(\mathrm{OH})_{2}\) (slaked lime) to water to remove phosphates before returning the water to the environment. Although the phosphates may be present in several forms, we can use HPO \(_{4}^{-}\) as a representative phosphate in the net ionic equation: \(5 \mathrm{Ca}^{2+}(a q)+3 \mathrm{HPO}_{4}^{-}(a q)+4 \mathrm{OH}^{-}(a q) \rightarrow\) $$ \mathrm{Ca}_{5} \mathrm{OH}\left(\mathrm{PO}_{4}\right)_{3}(s)+3 \mathrm{H}_{2} \mathrm{O}(\ell) $$ If phosphates (as HPO \(_{4}^{-}\) ) are present at a level of \(15.7 \mathrm{mg} / \mathrm{L}\) in wastewater, how much \(\mathrm{Ca}(\mathrm{OH})_{2}\) would need to be added to \(1.00 \times 10^{5} \mathrm{L}\) of water to precipitate \(95 \%\) of the phosphate ion present?

What is the molarity of each ion in a \(0.035 M\) aqueous solution of (a) \(\mathrm{NH}_{4} \mathrm{Cl} ;\) (b) \(\mathrm{Li}_{2} \mathrm{SO}_{4} ;\) (c) \(\mathrm{MgBr}_{2} ?\)

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