/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 How many grams of solute are nee... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 8: Problem 15

How many grams of solute are needed to prepare each of the following solutions? a. \(1.000 \mathrm{L}\) of \(0.200 M \mathrm{NaCl}\) b. \(250.0 \mathrm{mL}\) of \(0.125 M \mathrm{CuSO}_{4}\) c. \(500.0 \mathrm{mL}\) of \(0.400 M \mathrm{CH}_{3} \mathrm{OH}\)

Short Answer

Expert verified
a. 1.000 L of 0.200 M NaCl solution b. 250.0 mL of 0.125 M CuSO4 solution c. 500.0 mL of 0.400 M CH3OH solution Answer: a. 11.69 g of NaCl b. 4.99 g of CuSO4 c. 6.41 g of CH3OH

Step by step solution

01

Calculate moles of NaCl

To calculate the moles of sodium chloride (NaCl) needed, multiply the volume of the solution in liters by its molarity: moles of NaCl = volume 脳 molarity = 1.000 L 脳 0.200 M = 0.200 mol
02

Calculate mass of NaCl

Now, we need to calculate the mass of 0.200 moles of NaCl. To do this, we multiply the moles of NaCl by its molar mass (58.44 g/mol). mass of NaCl = moles 脳 molar mass = 0.200 mol 脳 58.44 g/mol = 11.69 g Thus, 11.69 grams of NaCl is needed. #b)
03

Calculate moles of CuSO4

Convert the volume of the solution to liters and then multiply it by the molarity to find the moles of copper(II) sulfate (CuSO4) required: volume = 250.0 mL 梅 1000 = 0.250 L moles of CuSO4 = volume 脳 molarity = 0.250 L 脳 0.125 M = 0.03125 mol
04

Calculate mass of CuSO4

To calculate the mass of 0.03125 moles of CuSO4, multiply it by its molar mass (159.62 g/mol): mass of CuSO4 = moles 脳 molar mass = 0.03125 mol 脳 159.62 g/mol = 4.99 g Thus, 4.99 grams of CuSO4 is needed. #c)
05

Calculate moles of CH3OH

Convert the volume of the solution to liters and then multiply it by the molarity to find the moles of methanol (CH3OH) required: volume = 500.0 mL 梅 1000 = 0.500 L moles of CH3OH = volume 脳 molarity = 0.500 L 脳 0.400 M = 0.200 mol
06

Calculate mass of CH3OH

To calculate the mass of 0.200 moles of CH3OH, multiply it by its molar mass (32.04 g/mol): mass of CH3OH = moles 脳 molar mass = 0.200 mol 脳 32.04 g/mol = 6.41 g Thus, 6.41 grams of CH3OH is needed. So, the required grams of solute for each solution are: a. 11.69 g of NaCl b. 4.99 g of CuSO4 c. 6.41 g of CH3OH

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A prototype battery based on iron compounds with large, positive oxidation numbers was developed in \(1999 .\) In the following reactions, assign oxidation numbers to the clements in each compound and balance the redox reactions in basic solution: a. \(\mathrm{FeO}_{4}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{FeOOH}(s)+\mathrm{O}_{2}(g)+\mathrm{OH}^{-}(a q)\) b. \(\mathrm{FeO}_{4}^{2-}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow \mathrm{Fe}_{2} \mathrm{O}_{3}(s)+\mathrm{O}_{2}(g)+\mathrm{OH}^{-}(a q)\)

Uranium is found in Earth's crust as UO, and in an assortment of compounds containing UO \(_{2}^{n+}\) cations. How many moles of electrons are transferred in the conversion of one mole of \(\mathrm{UO}_{2}\) to each of the following species? In which of the conversions is uranium oxidized? (a) \(\mathrm{UO}_{2}\left(\mathrm{CO}_{3}\right)_{3}^{4-}(a q) ;\) (b) \(\mathrm{UO}_{2}\left(\mathrm{HPO}_{4}\right)_{2}^{2-}(a q)\)

Rank the conductivities of \(1 M\) aqueous solutions of each of the following solutes, starting with the most conductive: (a) acetic acid; (b) methanol; (c) sucrose (table sugar); (d) hydrochloric acid.

How many milliliters of \(0.100 M\) NaOH are required to neutralize the following solutions? a. \(10.0 \mathrm{mL}\) of \(0.0500 M \mathrm{HCl}\) b. \(25.0 \mathrm{mL}\) of \(0.126 M \mathrm{HNO}_{3}\) c. \(50.0 \mathrm{mL}\) of \(0.215 M \mathrm{H}_{2} \mathrm{SO}_{4}\)

How many milliliters of \(0.100 M\) HNO \(_{3}\) are needed to neutralize the following solutions? a. \(45.0 \mathrm{mL}\) of \(0.667 M \mathrm{KOH}\) b. \(58.5 \mathrm{mL}\) of \(0.0100 M \mathrm{Al}(\mathrm{OH})_{3}\) c. \(34.7 \mathrm{mL}\) of \(0.775 M \mathrm{NaOH}\)
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Chemical Analysis

Read Explanation

Organic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.