Chapter 5: Problem 41
Explain the difference between a polar bond and a polar molecule.
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Chapter 5: Problem 41
Explain the difference between a polar bond and a polar molecule.
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For many years, it was believed that the noble gases could not form covalently bonded compounds. However, xenon does react with fluorine. One of the products is the pentafluoroxenate anion, \(\mathrm{XeF}_{5}^{-} .\) Draw the Lewis structure of \(\mathrm{XeF}_{5}^{-}\) and predict its geometry.
Determine the molecular geometries of the following molecules: (a) \(\mathrm{ClO}_{2} ;\) (b)\(\mathrm{ClO}_{3} ;(c) \mathrm{IF}_{3}\); (d) \(\mathrm{SF}_{4}\)
Azides such as sodium azide, NaN \(_{3}\) are used in automobile air bags as a source of nitrogen gas. Another compound with three nitrogen atoms bonded together is \(\mathrm{N}_{3} \mathrm{F}\). What differences are there between the arrangements of the electrons around the nitrogen atoms in the azide ion \(\left(\mathrm{N}_{3}^{-}\right)\) and in \(\mathrm{N}_{3} \mathrm{F}\) ? Is there a difference in the hybridization of the central nitrogen atom?
Are s atomic orbitals with different principal quantum numbers \((n)\) as likely to overlap and form MOs as s atomic orbitals with the same value of \(n ?\)
Why do \(\mathrm{CF}_{4}, \mathrm{SF}_{4},\) and \(\mathrm{XeF}_{4}\) have different molecular geometries, even though they all consist of a central atom bonded to four fluorine atoms?
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