Chapter 23: Problem 48
How many unpaired electrons are in the following transition metal ions in an octahedral crystal field? High-spin \(\mathrm{Fe}^{3+}, \mathrm{Rh}^{+}, \mathrm{V}^{3+},\) and low-spin \(\mathrm{Mn}^{3+}\).
Short Answer
Expert verified
Answer: High-spin Fe鲁鈦 has 5 unpaired electrons, high-spin Rh鹿鈦 has 4 unpaired electrons, V鲁鈦 has 2 unpaired electrons, and low-spin Mn鲁鈦 has 0 unpaired electrons.
Step by step solution
01
Determine electronic configuration of the neutral atoms
Start by finding the electronic configuration of the neutral atoms (Fe, Rh, V, and Mn) using the periodic table. These configurations are:
Fe: [Ar] 3d^6 4s^2
Rh: [Kr] 4d^8 5s^1
V: [Ar] 3d^3 4s^2
Mn: [Ar] 3d^5 4s^2
02
Calculate the electron configuration of the ions
Remove electrons from the highest energy orbitals in each atom to get the electron configuration of the given ions:
Fe鲁鈦: [Ar] 3d^5 (remove 2 electrons from 4s, then 1 electron from 3d)
Rh鹿鈦: [Kr] 4d^8 (remove 1 electron from 5s)
V鲁鈦: [Ar] 3d^2 (remove 2 electrons from 4s, then 1 electron from 3d)
Mn鲁鈦: [Ar] 3d^4 (remove 2 electrons from 4s, then 1 electron from 3d)
03
Determine unpaired electrons for high-spin ions
For high-spin Fe鲁鈦 and Rh鹿鈦, use Hund's rule to fill the d-orbitals:
High-spin Fe鲁鈦: (鈫 _ _ _ _) 鈫 5 unpaired electrons
High-spin Rh鹿鈦: (鈫 鈫 鈫 鈫 _ _) 鈫 4 unpaired electrons
04
Determine unpaired electrons for V鲁鈦
V鲁鈦 has a 3d虏 configuration. In an octahedral crystal field, it will have one electron in two of the three lower energy d-orbitals:
V鲁鈦: (鈫 _ _) 鈫 2 unpaired electrons
05
Determine unpaired electrons for low-spin Mn鲁鈦
For low-spin Mn鲁鈦, the electrons will be paired in the lower energy orbitals to minimize energy in the crystal field:
Low-spin Mn鲁鈦: (鈫戔啌 鈫戔啌 _ _) 鈫 0 unpaired electrons
06
Final Result
The number of unpaired electrons in the given transition metal ions in an octahedral crystal field are:
High-spin Fe鲁鈦: 5 unpaired electrons
High-spin Rh鹿鈦: 4 unpaired electrons
V鲁鈦: 2 unpaired electrons
Low-spin Mn鲁鈦: 0 unpaired electrons
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electronic Configuration
Understanding electronic configuration is essential in chemistry, especially for transition metal ions. Each element has a unique distribution of electrons among its energy levels and sublevels. This distribution is the electronic configuration.
For example, if we look at the element iron (Fe), its electronic configuration is \[ \text{[Ar]} \, 3d^6 \, 4s^2 \]. This notation means that iron has the same inner structure as Argon (Ar) plus additional electrons filling the 3d and 4s sublevels.
To determine the electronic configuration of ions, electrons are removed starting from the highest energy level orbitals. This differs slightly from the filling order used to determine the ground state of neutral atoms:
For example, if we look at the element iron (Fe), its electronic configuration is \[ \text{[Ar]} \, 3d^6 \, 4s^2 \]. This notation means that iron has the same inner structure as Argon (Ar) plus additional electrons filling the 3d and 4s sublevels.
To determine the electronic configuration of ions, electrons are removed starting from the highest energy level orbitals. This differs slightly from the filling order used to determine the ground state of neutral atoms:
- Electrons are removed from the highest principal quantum number first, typically the s-orbital.
- After the s-electrons are removed, d-orbitals lose electrons next as needed.
Octahedral Crystal Field
The octahedral crystal field is a model that explains how the d-orbitals of a transition metal ion split in energy when surrounded by six ligands. The ligands donate electron pairs to the metal ion, creating an electrostatic field.
This field causes the five d-orbitals to split into two sets with different energies:
This splitting is important because it influences how electrons occupy the d-orbitals, affecting the number of unpaired electrons and, consequently, the ion's magnetic properties.
This field causes the five d-orbitals to split into two sets with different energies:
- The \( t_{2g} \) set includes three orbitals, which are lower in energy.
- The \( e_g \) set includes two orbitals, which are higher in energy.
This splitting is important because it influences how electrons occupy the d-orbitals, affecting the number of unpaired electrons and, consequently, the ion's magnetic properties.
High-Spin and Low-Spin States
High-spin and low-spin configurations describe how electrons are distributed among the d-orbitals in a split crystal field.
In high-spin states, the electrons tend to maximize spin multiplicity, meaning more electrons remain unpaired. This happens because the energy difference between the \( t_{2g} \) and \( e_g \) orbitals is small, making it easier for electrons to occupy higher energy orbitals with parallel spins:
In high-spin states, the electrons tend to maximize spin multiplicity, meaning more electrons remain unpaired. This happens because the energy difference between the \( t_{2g} \) and \( e_g \) orbitals is small, making it easier for electrons to occupy higher energy orbitals with parallel spins:
- High-spin example: \[ \text{Fe}^{3+} \text{ has 5 unpaired electrons in a high-spin state.} \]
- Low-spin example: \[ \text{Mn}^{3+} \text{ has 0 unpaired electrons in a low-spin state.} \]
Transition Metal Ions
Transition metal ions are fascinating due to their partially filled d-orbitals. These ions often display unique chemical and physical properties as a result of these d-orbitals.
Key traits of transition metal ions include:
Studying transition metal ions in environments such as octahedral crystal fields helps chemists predict and manipulate their behaviors for applications across numerous scientific fields.
Key traits of transition metal ions include:
- Variable oxidation states: They can lose different numbers of electrons, leading to multiple possible ion forms.
- Colored compounds: The d-electron transitions absorb specific wavelengths of light, giving these ions vibrant colors.
- Magnetism: Unpaired d-electrons often lead to magnetic properties, making these ions important in materials science.
Studying transition metal ions in environments such as octahedral crystal fields helps chemists predict and manipulate their behaviors for applications across numerous scientific fields.