Chapter 22: Problem 53
What are the likely signs of \(\Delta S\) and \(\Delta G\) for the dissolution of tooth enamel?
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 22: Problem 53
What are the likely signs of \(\Delta S\) and \(\Delta G\) for the dissolution of tooth enamel?
All the tools & learning materials you need for study success - in one app.
Get started for free
The concentrations of very dilute solutions are sometimes expressed as parts per million. Express the concentration of each of the following trace and ultratrace essential elements in parts per million: a. Fluorine, \(110 \mathrm{mg}\) in \(70 \mathrm{kg}\) b. Silicon, \(525 \mathrm{mg} / \mathrm{kg}\) c. Iodine, \(0.043 \mathrm{g}\) in \(100 \mathrm{kg}\)
Several isotopes of arsenic are used in medical imaging. Which isotope, \(^{72}\) As or \(^{77}\) As, is more likely to be useful for PET imaging?
The \(K_{\mathrm{sp}}\) of actual tooth enamel is reported to be \(1 \times 10^{-58}.\) a. Does this mean that tooth enamel is more soluble than pure hydroxyapatite \(\left(K_{\mathrm{sp}}=2.3 \times 10^{-59}\right) ?\) b. Does the measured value of \(K_{\mathrm{sp}}\) for tooth enamel support the idea that tooth enamel is a mixture of hydroxyapatite, \(\mathrm{Ca}_{5}\left(\mathrm{PO}_{4}\right)_{3}(\mathrm{OH}),\) and a calcium phosphate \(\mathrm{Ca}_{8}\left(\mathrm{HPO}_{4}\right)_{2}\left(\mathrm{PO}_{4}\right)_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}\left(K_{\mathrm{sp}}=1.1 \times 10^{-47}\right) ?\) c. Calculate the solubility in moles per liter of \(\mathrm{Ca}_{8}\left(\mathrm{HPO}_{4}\right)_{2}\left(\mathrm{PO}_{4}\right)_{4} \cdot 6 \mathrm{H}_{2} \mathrm{O}\left(K_{\mathrm{sp}}=1.1 \times 10^{-47}\right) \mathrm{in}\) water at \(25^{\circ} \mathrm{C}\)
Algae in the genus Closterium contain structures built from barium sulfate (barite). Calculate the solubility in moles per liter of \(\mathrm{BaSO}_{4}\) in water at \(25^{\circ} \mathrm{C}\) given that \(K_{\mathrm{sp}}=1.08 \times 10^{-10}.\)
Why do we classify the main group elements by group rather than period?
What do you think about this solution?
We value your feedback to improve our textbook solutions.