Chapter 21: Problem 99
A 1.00 mg sample of \(^{192}\) Ir was inserted into the artery of a heart patient. After 30 days, 0.756 mg remained. What is the half-life of \(^{192} \mathrm{Ir} ?\)
Short Answer
Expert verified
Answer: The half-life of Iridium-192 is approximately 76.36 days.
Step by step solution
01
Understand the radioactive decay formula
The formula for radioactive decay is given by: \(N(t) = N_0 e^{-\lambda t}\), where \(N(t)\) is the remaining mass of the isotope at time \(t\), \(N_0\) is the initial mass, \(\lambda\) is the decay constant, and \(t\) is the time.
02
Write down the given information
We are given the initial mass \(N_0 = 1.00 \thinspace mg\), the remaining mass after 30 days \(N(t) = 0.756 \thinspace mg\), and the time \(t = 30 \thinspace days\).
03
Rearrange the decay formula for the decay constant
Divide both sides of the radioactive decay formula by \(N_0\), then we have:
\(\frac{N(t)}{N_0} = e^{-\lambda t}\)
Now, we want to isolate \(\lambda\), so take the natural logarithm on both sides:
\(ln \left(\frac{N(t)}{N_0}\right) = -\lambda t\)
Finally, solve for the decay constant \(\lambda\) by dividing both sides by \(-t\):
\(\lambda = \frac{ln\left(\frac{N(t)}{N_0}\right)}{-t}\)
04
Calculate the decay constant
Using the values given in the problem, let's substitute them into the decay constant formula:
\(\lambda = \frac{ln\left(\frac{0.756}{1.00}\right)}{-30}\)
\(\lambda \approx 0.009088 \thinspace days^{-1}\)
05
Relate the decay constant to the half-life
The half-life (\(T_{1/2}\)) is related to the decay constant by the formula:
\(T_{1/2} = \frac{ln(2)}{\lambda}\)
06
Calculate the half-life of Iridium-192
Now, substitute the decay constant found in Step 4 into the half-life formula:
\(T_{1/2} = \frac{ln(2)}{0.009088}\)
\(T_{1/2} \approx 76.36 \thinspace days\)
The half-life of Iridium-192 is approximately 76.36 days.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Half-Life Calculation
The half-life of a radioactive substance is the time it takes for half of the initial quantity of the substance to decay. This is a key concept in understanding how radioactive decay works.
To calculate the half-life, we often use the relation between the decay constant and half-life, which is expressed by the formula:
In the context of the problem mentioned, the half-life of Iridium-192 was calculated using the decay constant derived from the data given. Once the decay constant was found to be approximately \(0.009088 \thinspace days^{-1}\), it was plugged into the half-life formula to find that the half-life of Iridium-192 is about 76.36 days.
This calculation shows that even if we start with a different mass, the half-life for Iridium-192 will remain the same, 76.36 days, as long as the environmental conditions remain unchanged.
To calculate the half-life, we often use the relation between the decay constant and half-life, which is expressed by the formula:
- \( T_{1/2} = \frac{\ln(2)}{\lambda} \)
In the context of the problem mentioned, the half-life of Iridium-192 was calculated using the decay constant derived from the data given. Once the decay constant was found to be approximately \(0.009088 \thinspace days^{-1}\), it was plugged into the half-life formula to find that the half-life of Iridium-192 is about 76.36 days.
This calculation shows that even if we start with a different mass, the half-life for Iridium-192 will remain the same, 76.36 days, as long as the environmental conditions remain unchanged.
Decay Constant Formula
The decay constant, denoted as \( \lambda \), is a measure of the probability of decay per unit time for a radioactive substance. It plays a crucial role in the process of determining the rate of decay.
The decay constant can be calculated using the following formula:
The decay constant gives us insight into how quickly or slowly a particular isotope decays. A larger decay constant indicates a faster rate of decay, while a smaller one means the isotope decays more slowly.
The decay constant can be calculated using the following formula:
- \( \lambda = \frac{\ln\left(\frac{N(t)}{N_0}\right)}{-t} \)
- \( N(t) \) is the remaining mass of the radioactive sample after time \( t \)
- \( N_0 \) is the initial mass of the substance
- \( t \) is the time elapsed
- Initial mass, \( N_0 = 1.00 \) mg
- Remaining mass after 30 days, \( N(t) = 0.756 \) mg
- Time, \( t = 30 \) days
The decay constant gives us insight into how quickly or slowly a particular isotope decays. A larger decay constant indicates a faster rate of decay, while a smaller one means the isotope decays more slowly.
Iridium-192 Half-Life
Iridium-192 is a radioactive isotope commonly used in industrial radiography and medical applications for treatment. Understanding its half-life is fundamental to its safe and effective application.
The problem statement you were given allowed the calculation of Iridium-192's half-life using the decay constant. This was found to be approximately 76.36 days.
Here’s why knowing the half-life is important for Iridium-192:
The problem statement you were given allowed the calculation of Iridium-192's half-life using the decay constant. This was found to be approximately 76.36 days.
Here’s why knowing the half-life is important for Iridium-192:
- It helps industries and healthcare providers schedule the replacement of their radioactive sources.
- It provides insights into how long the isotope will remain active and effective for its intended purpose.
- A clear half-life calculation ensures safety and proper usage by anticipating how long the isotope will maintain its radioactive potency.