/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 84 For each of the following fissio... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 21: Problem 84

For each of the following fission reactions, determine the identity of the unknown nuclide: a. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{147} \mathrm{Pm}+?+2_{0}^{1} \mathrm{n}\) b. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{94} \mathrm{Kr}+?+2_{0}^{1} \mathrm{n}\) c. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{95} \mathrm{Sr}+?+3_{0}^{1} \mathrm{n}\)

Short Answer

Expert verified
+2_{0}^{1} \mathrm{n}\) b. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{94} \mathrm{Kr}+?+2_{0}^{1} \mathrm{n}\) c. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{95} \mathrm{Sr}+?+3_{0}^{1} \mathrm{n}\) Answer: a. The unknown nuclide is \(^{86}\mathrm{Ga}\). b. The unknown nuclide is \(^{139}\mathrm{Ba}\). c. The unknown nuclide is \(^{137}\mathrm{Xe}\).

Step by step solution

01

Balance atomic numbers (protons)

On the left side of the equation, we have 92 protons and on the right side, we have 61 protons in Pm. So, we need to find an element with atomic number 92-61=31, which is Gallium (Ga).
02

Balance mass numbers (nucleons)

On the left side, we have 235 nucleons and on the right side, we have 147 in Pm and 2 in the neutrons. So, we need to find an isotope of Ga with a mass number of 235-147-2=86. The unknown nuclide is \(^{86}\mathrm{Ga}\). b. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{94} \mathrm{Kr}+?+2_{0}^{1} \mathrm{n}\)
03

Balance atomic numbers (protons)

On the left side of the equation, we have 92 protons and on the right side, we have 36 protons in Kr. So, we need to find an element with atomic number 92-36=56, which is Barium (Ba).
04

Balance mass numbers (nucleons)

On the left side, we have 235 nucleons and on the right side, we have 94 in Kr and 2 in the neutrons. So, we need to find an isotope of Ba with a mass number of 235-94-2=139. The unknown nuclide is \(^{139}\mathrm{Ba}\). c. \(^{235} \mathrm{U}+_{0}^{1} \mathrm{n} \rightarrow^{95} \mathrm{Sr}+?+3_{0}^{1} \mathrm{n}\)
05

Balance atomic numbers (protons)

On the left side of the equation, we have 92 protons and on the right side, we have 38 protons in Sr. So, we need to find an element with atomic number 92-38=54, which is Xenon (Xe).
06

Balance mass numbers (nucleons)

On the left side, we have 235 nucleons and on the right side, we have 95 in Sr and 3 in the neutrons. So, we need to find an isotope of Xe with a mass number of 235-95-3=137. The unknown nuclide is \(^{137}\mathrm{Xe}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

There was once a plan to store radioactive waste that contained plutonium- 239 in the reefs of the Marshall Islands. The planners claimed that the plutonium would be "reasonably safe" after 240,000 years. If the half-life is 24,400 years, what percentage of the \(^{239}\) Pu would remain after 240,000 years?

Most of the ions that flow out from the sun in the solar wind are hydrogen ions. The ions of which element should be next most abundant?

The ratio of neutrons to protons in stable nuclei increases with increasing atomic number. Use this trend to explain why multiple \(\alpha\) decay steps in the \(^{238} \mathrm{U}\) decay series are often followed by \(\beta\) decay.

In 1997 anthropologists uncovered three partial skulls of prehistoric humans in the Ethiopian village of Herto. Based on the amount of \(^{40} \mathrm{Ar}\) in the volcanic ash in which the remains were buried, their age was estimated at between 154,000 and 160,000 years old. a. \(^{40} \mathrm{Ar}\) is produced by the decay of \(^{40} \mathrm{K}\left(t_{1 / 2}=1.28 \times\right.\) \(10^{9}\) yr). Propose a decay mechanism for \(^{40} \mathrm{K}\) to \(^{40} \mathrm{Ar}\). b. Why did the researchers choose \(^{40}\) Ar rather than \(^{14} \mathrm{C}\) as the isotope for dating these remains?

Spent fuel removed from nuclear power stations contains plutonium-\(239\left(t_{1 / 2}=2.41 \times 10^{4} years) \right.\) How long will it take a sample of this radionuclide to reach a level of radioactivity that is \(2.5 \%\) of the level it had when it was removed from a reactor?
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Kinetics

Read Explanation

Nuclear Chemistry

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Making Measurements

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.