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What is the pH of a buffer that is \(0.110 M \mathrm{HPO}_{4}^{2-}\) and \(0.220 \mathrm{M} \mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) at \(25^{\circ} \mathrm{C} ?\)

Short Answer

Expert verified
Answer: The pH of the buffer solution is 6.91.

Step by step solution

01

Write down the Henderson-Hasselbalch equation

The Henderson-Hasselbalch equation is given by: $$ \text{pH} = \text{pKa} + \log \frac{[\text{conjugate base}]}{[\text{acid}]} $$ In our case, the conjugate base is \(\mathrm{HPO}_{4}^{2-}\), and the acid is \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\).
02

Determine the pKa value

We need to find the pKa value for the acid \(\mathrm{H}_{2}\mathrm{PO}_{4}^{-}\). From the list of dissociation constants of phosphoric acid, we can obtain the pKa value for the second dissociation constant, which corresponds to our given acid. $$ \text{pKa} = 7.21 $$
03

Calculate the pH using the Henderson-Hasselbalch equation

Now, we have all the values needed to calculate the pH of the buffer solution. Substituting the values into the Henderson-Hasselbalch equation: $$ \text{pH}=7.21 + \log \frac{[\mathrm{HPO}_{4}^{2-}]}{[\mathrm{H}_{2} \mathrm{PO}_{4}^{-}]} = 7.21 + \log \frac{0.110}{0.220} $$
04

Solve for the pH value

Finally, we can evaluate the equation to find the pH value: $$ \text{pH} = 7.21 + \log 0.5 = 7.21 - 0.30 = 6.91 $$ The pH of the buffer solution is 6.91.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henderson-Hasselbalch equation
The Henderson-Hasselbalch equation is an important tool in chemistry that helps us understand the relationship between the pH of a buffer solution and its components. This formula is given by:\[ \text{pH} = \text{pKa} + \log \frac{[\text{conjugate base}]}{[\text{acid}]} \]This equation is particularly useful for calculating the pH of buffer solutions, which are solutions that resist changes in pH upon the addition of small amounts of acid or base. By knowing the ratio of the concentrations of the conjugate base and the acid in a buffer solution, you can predict how the pH will change.
In our exercise, the conjugate base is \(\text{HPO}_4^{2-}\) and the acid is \(\text{H}_2\text{PO}_4^{-}\). By plugging the concentrations of these into the equation, we can determine the pH of the buffer at equilibrium.
pKa value
The \(\text{pKa}\) value is a measure of the strength of an acid. It represents the negative logarithm of the acid dissociation constant \(K_a\), which tells us how well an acid can donate a proton (H\(^+\)) in a solution. The lower the \(\text{pKa}\), the stronger the acid, because it dissociates more to form \(H\(^+\)\) ions.
For phosphoric acid, the \(\text{pKa}\) value is a key component because each dissociation step has its own \(\text{pKa}\). When setting up a buffer involving \(\text{H}_2\text{PO}_4^{-}\), the relevant \(\text{pKa}\) is for its second dissociation, which is 7.21. Knowing this helps us in plugging the correct value into the Henderson-Hasselbalch equation to calculate the pH of the buffer.
Calculating the \(\text{pKa}\) accurately is crucial for designing buffer solutions with precise pH levels.
conjugate acid-base pair
A conjugate acid-base pair consists of two species that transform into each other by the gain or loss of a proton. In any given buffer solution, you will typically find a weak acid paired with its conjugate base, or a weak base with its conjugate acid.
In this particular problem, \(\text{H}_2\text{PO}_4^{-}\) is the acid, and \(\text{HPO}_4^{2-}\) is its conjugate base. When the acid donates a proton, it becomes its conjugate base. Conversely, this conjugate base can accept a proton to become the conjugate acid again. This equilibrium between donating and accepting protons is what gives buffer solutions their ability to withstand pH changes.
Understanding the concept of conjugate acid-base pairs is essential for seeing how buffers can maintain a relatively constant pH even when external conditions attempt to disrupt them.

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Most popular questions from this chapter

Buffer A contains nearly equal concentrations of its conjugate acid-base pair. Buffer \(\mathrm{B}\) contains the same total concentration of acidic and basic components as buffer \(\mathrm{A}\) but B has twice as much of its weak acid as its conjugate base. Which buffer experiences a smaller change in \(\mathrm{pH}\) when a. the same small quantity of strong base is added to both? b. the same small quantity of strong acid is added to both?

Do all titrations of samples of strong monoprotic acids with solutions of strong bases have the same pH at their equivalence points? Explain why or why not.

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Draw Lewis structures that show how electron pairs move and bonds form and break in the following reaction, and identify the Lewis acid and Lewis base. $$ \mathrm{SbF}_{5}(s)+\mathrm{HF}(g) \rightarrow \mathrm{HSbF}_{6}(s) $$

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