Chapter 16: Problem 114
Why does adding \(\mathrm{CaCl}_{2}\) to a \(\mathrm{HPO}_{4}^{2-} / \mathrm{PO}_{4}^{3-}\) buffer increase the ratio of \(\mathrm{HPO}_{4}^{2-}\) ions to \(\mathrm{PO}_{4}^{3-}\) ions?
Short Answer
Expert verified
Answer: Adding CaCl2 to a HPO4虏鈦/PO4鲁鈦 buffer causes the ratio of HPO4虏鈦 ions to PO4鲁鈦 ions to increase.
Step by step solution
01
Identify the important ions in the buffer and the added salt
In the given buffer, we have the HPO4虏鈦 and PO4鲁鈦 ions. When we add CaCl2 to the buffer, it dissociates into Ca虏鈦 and Cl鈦 ions. The Cl鈦 ions will not interact with the buffer, so we will focus on how Ca虏鈦 ions interact with HPO4虏鈦 and PO4鲁鈦 ions.
02
Understand the interactions between the ions
Ca虏鈦 ions have a strong affinity for negative charges due to their positive charge. Therefore, they tend to form complexes with negatively charged ions, such as HPO4虏鈦 and PO4鲁鈦 ions. The Ca虏鈦 ions will form more stable complexes with PO4鲁鈦 ions than with HPO4虏鈦 ions, since PO4鲁鈦 ions have a higher negative charge.
03
Write the reaction of Ca虏鈦 ions with the buffer components
The complex formation between Ca虏鈦 ions and the buffer components can be represented by the following reactions:
1. \[Ca^{2+} + HPO_{4}^{2-} \rightleftharpoons CaHPO_{4}(s)\]
2. \[Ca^{2+} + PO_{4}^{3-} \rightleftharpoons CaPO_{4}(s)\]
In both reactions, the complexes formed (CaHPO4 and CaPO4) are solid and will precipitate out of the solution.
04
Determine the effects of adding Ca虏鈦 ions on the buffer components
When the Ca虏鈦 ions are added to the buffer, they will preferentially bind to PO4鲁鈦 ions to form the CaPO4 complex due to the higher negative charge on PO4鲁鈦 ions. As a result, the concentration of PO4鲁鈦 ions in the buffer will decrease. The complex formation between Ca虏鈦 and HPO4虏鈦 ions will also occur, but to a lesser extent than with PO4鲁鈦 ions.
The decrease in PO4鲁鈦 ions concentration will cause a shift in the equilibrium of the following reaction, which represents the buffering action:
\[HPO_{4}^{2-} \rightleftharpoons H^{+} + PO_{4}^{3-}\]
According to Le Chatelier's principle, the equilibrium will shift to the right to counter the decrease in PO4鲁鈦 ions concentration. This shift will result in an increase in HPO4虏鈦 ions concentration as well as an increase in H鈦 ions concentration.
05
Conclude the effect on the ratio of HPO4虏鈦 ions to PO4鲁鈦 ions
As a result of adding CaCl2 to the buffer and the subsequent interactions between Ca虏鈦 ions and the buffer components, the concentration of PO4鲁鈦 ions will decrease while the concentration of HPO4虏鈦 ions will increase. Thus, the ratio of HPO4虏鈦 ions to PO4鲁鈦 ions will increase.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ions Interaction
In the realm of chemistry, ions interaction plays a crucial role, especially when it comes to buffer systems. When \(\text{CaCl}_{2} \)is added to a \(\mathrm{HPO}_{4}^{2-} / \mathrm{PO}_{4}^{3-} \)buffer, the \(\text{CaCl}_{2} \)quickly dissociates into \(\text{Ca}^{2+} \)and \(\text{Cl}^- \)ions in the solution. Among these, the \(\text{Cl}^- \)ions do not actively interact with the phosphate buffer ions due to their lower reactivity and the fact that the main interactions involved stem from the positively charged \(\text{Ca}^{2+} \)ions.
These \(\text{Ca}^{2+} \)ions, being positively charged, are naturally inclined to interact with negatively charged ions in the solution. Both \(\text{HPO}_{4}^{2-} \)and \(\text{PO}_{4}^{3-} \)ions in the buffer are negatively charged, but the interaction is not uniform across these ions. It tends to be more pronounced with \(\text{PO}_{4}^{3-} \)because it has a higher negative charge. The preferential binding occurs because the strength of interaction becomes greater as the charge disparity between the ions increases. This interaction heavily impacts the availability and concentration of the ions in the solution.
The resulting change in ion concentration from such interactions sets off a cascade of chemical responses in the solution, fundamentally altering the dynamics of the buffer system.
These \(\text{Ca}^{2+} \)ions, being positively charged, are naturally inclined to interact with negatively charged ions in the solution. Both \(\text{HPO}_{4}^{2-} \)and \(\text{PO}_{4}^{3-} \)ions in the buffer are negatively charged, but the interaction is not uniform across these ions. It tends to be more pronounced with \(\text{PO}_{4}^{3-} \)because it has a higher negative charge. The preferential binding occurs because the strength of interaction becomes greater as the charge disparity between the ions increases. This interaction heavily impacts the availability and concentration of the ions in the solution.
The resulting change in ion concentration from such interactions sets off a cascade of chemical responses in the solution, fundamentally altering the dynamics of the buffer system.
Le Chatelier's Principle
Le Chatelier's Principle provides insight into how a chemical equilibrium reacts to external changes, structuring itself to counterbalance disturbances effectively. When we introduce \(\text{Ca}^{2+} \)ions into the \(\text{HPO}_{4}^{2-} / \text{PO}_{4}^{3-} \)buffer, these ions bind significantly with \(\text{PO}_{4}^{3-} \)to form \(\text{CaPO}_{4} \)solid. This precipitate decreases the \(\text{PO}_{4}^{3-} \)ions' concentration available in solution.
According to Le Chatelier's Principle, the system strives to counteract this decrease in \(\text{PO}_{4}^{3-} \)ions concentration by shifting the equilibrium towards the production of more \(\text{PO}_{4}^{3-} \)ions. Consequently, the reaction \(\text{HPO}_{4}^{2-} \rightleftharpoons \text{H}^{+} + \text{PO}_{4}^{3-} \)accommodates this shift by converting more \(\text{HPO}_{4}^{2-} \)into \(\text{PO}_{4}^{3-} \)and \(\text{H}^{+} \)ions.
According to Le Chatelier's Principle, the system strives to counteract this decrease in \(\text{PO}_{4}^{3-} \)ions concentration by shifting the equilibrium towards the production of more \(\text{PO}_{4}^{3-} \)ions. Consequently, the reaction \(\text{HPO}_{4}^{2-} \rightleftharpoons \text{H}^{+} + \text{PO}_{4}^{3-} \)accommodates this shift by converting more \(\text{HPO}_{4}^{2-} \)into \(\text{PO}_{4}^{3-} \)and \(\text{H}^{+} \)ions.
- Increase in \(\text{HPO}_{4}^{2-} \)in the equilibrium as \(\text{PO}_{4}^{3-} \)levels are restored.
- Higher \(\text{H}^{+} \)ions concentration makes the solution slightly more acidic.
Complex Formation
Complex formation in chemistry involves the stable association of a central metal ion, such as \(\text{Ca}^{2+} \), with ligands that donate electron pairs. In the scenario of a \(\text{HPO}_{4}^{2-} / \text{PO}_{4}^{3-} \)buffer, \(\text{Ca}^{2+} \)ions introduced into the solution tend to form complexes with \(\text{PO}_{4}^{3-} \)ions because of their stronger negative charge, forming a solid complex like \(\text{CaPO}_{4} \).
The stability of these complexes relies on the bonds formed between the \(\text{Ca}^{2+} \)and the phosphate ions. The more negatively charged the phosphate, the greater the likelihood of forming a stable complex. This is fundamental to understand as complex formation reduces the free ions in the solution significantly, thus shifting chemical equilibria.
The stability of these complexes relies on the bonds formed between the \(\text{Ca}^{2+} \)and the phosphate ions. The more negatively charged the phosphate, the greater the likelihood of forming a stable complex. This is fundamental to understand as complex formation reduces the free ions in the solution significantly, thus shifting chemical equilibria.
- Complex formation can lead to precipitation, where new solid forms are established, such as \(\text{CaPO}_{4} \)
- Lessens free ion availability in solution, impacting the solution's chemical behavior.