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The order of a reaction is independent of temperature, but the value of the rate constant varies with temperature. Why?

Short Answer

Expert verified
Short Answer: The reaction order is independent of temperature because it is determined by the reaction mechanism, which is generally constant at any temperature. However, the rate constant's value changes with temperature due to its relation to activation energy and the molecular motion of reactants, both of which are temperature-dependent.

Step by step solution

01

Define reaction order and rate constant

Reaction order refers to the relationship between the reactant's concentration and the reaction rate. In other words, it shows how the change in concentration of the reactants affects the reaction's speed. The order of a reaction is usually expressed as an integer or a sum of integers corresponding to the stoichiometric coefficients of the reactants in the rate equation. The rate constant, denoted by k, is a proportionality factor that indicates the reaction's inherent speed under a specific set of conditions. The value of the rate constant depends on factors such as temperature, pressure, and the nature of the reactants involved.
02

Explain the independence of reaction order from temperature

Reaction order is a result of the underlying molecularity of a reaction and is determined by the mechanism of the reaction, i.e., the sequence of elementary steps that make up the reaction. Since the reaction mechanism is generally independent of temperature, the reaction order will remain the same at any temperature. For example, consider a reaction with an order of 2. This order means that doubling the concentration of the reactant will result in a four-fold increase in the reaction rate (since 2² = 4). This relationship between the reactant's concentration and the reaction rate is solely based on the reaction's molecularity and doesn't depend on the temperature.
03

Describe the variation of the rate constant with temperature

While the reaction order remains the same at different temperatures, the rate constant's value can change significantly. This variation is due to the temperature's effect on the reaction's kinetics, especially the activation energy (Ea), which is the minimum energy required for a reaction to occur. According to the Arrhenius equation, the rate constant k of a reaction is related to temperature T and activation energy Ea as follows: k = A * e^{(-Ea / RT)} where A is the pre-exponential factor, R is the universal gas constant, and T is the temperature in Kelvin. From the equation, we can see that the value of k increases with increasing temperature. This increase in the rate constant indicates that the reaction rate is higher at higher temperatures, which is consistent with experimental observations. In conclusion, the reaction order remains constant at different temperatures because it depends on the reaction's mechanism, which is usually independent of temperature. In contrast, the rate constant varies with temperature because it is related to the activation energy and the reactants' molecular motion, both of which are temperature-dependent.

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Most popular questions from this chapter

Does a substance that increases the rate of a reaction also increase the rate of the reverse reaction?

The following is an important reaction in the formation of photochemical smog: $$\mathrm{NO}(g)+\mathrm{O}_{3}(g) \rightarrow \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g)$$ The reaction is first order in \(\mathrm{NO}\) and \(\mathrm{O}_{3} .\) The rate constant of the reaction is \(80 M^{-1} \mathrm{s}^{-1}\) at \(25^{\circ} \mathrm{C}\) and \(3000 M^{-1} \mathrm{s}^{-1}\) at \(75^{\circ} \mathrm{C}\) a. If this reaction were to occur in a single step, would the rate law be consistent with the observed order of the reaction for \(\mathrm{NO}\) and \(\mathrm{O}_{3} ?\) b. What is the value of the activation energy of the reaction? c. What is the rate of the reaction at \(25^{\circ} \mathrm{C}\) when \([\mathrm{NO}]=3 \times 10^{-6} \mathrm{Mand}\left[\mathrm{O}_{3}\right]=5 \times 10^{-9} \mathrm{MP}\) d. Predict the values of the rate constant at \(10^{\circ} \mathrm{C}\) and \(35^{\circ} \mathrm{C}\).

A proposed mechanism for the gas phase decomposition of hydrogen peroxide at an elevated temperature consists of three elementary steps: $$\begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}(g) & \rightarrow 2 \mathrm{OH}(g) \\ \mathrm{H}_{2} \mathrm{O}_{2}(g)+\mathrm{OH}(g) & \rightarrow \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{HO}_{2}(g) \\ \mathrm{HO}_{2}(g)+\mathrm{OH}(g) & \rightarrow \mathrm{H}_{2} \mathrm{O}(g)+\mathrm{O}_{2}(g) \end{aligned}$$ If the rate law for the reaction is first order in \(\mathrm{H}_{2} \mathrm{O}_{2},\) which step in the mechanism is the rate-determining step?

Determine the overall order of the following rate laws and the order with respect to each reactant. a. Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}]^{1 / 2}\) b. Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}][\mathrm{C}]\) c. Rate \(=k[\mathrm{A}][\mathrm{B}]^{3}[\mathrm{C}]^{1 / 2}\)

Nitrous acid slowly decomposes to \(\mathrm{NO}, \mathrm{NO}_{2},\) and water in the following second-order reaction: $$2 \mathrm{HNO}_{2}(a q) \rightarrow \mathrm{NO}(g)+\mathrm{NO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(\ell)$$ a. Use the following data to determine the rate constant for this reaction at \(298 \mathrm{K}:\) $$\begin{array}{cc} \text { Time (min) } & {\left[\mathrm{HNO}_{2}\right](\mu M)} \\\0 & 0.1560 \\\\\hline 1000 & 0.1466 \\\\\hline 1500 & 0.1424 \\\\\hline 2000 & 0.1383 \\\\\hline 2500 & 0.1345 \\\\\hline 3000 & 0.1309 \\\\\hline\end{array}$$ b. Determine the half-life for the decomposition of \(\mathrm{HNO}_{2}\). c. If the experiment that yielded the results in the preceding table had been continued for 3000 minutes more, what would the concentration of HNO \(_{2}\) have been?

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