Chapter 12: Problem 43
What does the sign of \(\Delta G\) tell you about the spontaneity of a process?
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Chapter 12: Problem 43
What does the sign of \(\Delta G\) tell you about the spontaneity of a process?
These are the key concepts you need to understand to accurately answer the question.
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Acid Precipitation Aerosols (fine droplets) of sulfuric acid form in the atmosphere as a result of the following combination reaction:$$\mathrm{SO}_{3}(g)+\mathrm{H}_{2} \mathrm{O}(g) \rightarrow \mathrm{H}_{2} \mathrm{SO}_{4}(\ell)$$.Use the appropriate \(\Delta G_{f}^{\circ}\) data in Appendix 4 to calculate \(\Delta G_{\mathrm{rxn}}^{\circ}\) for this reaction.
Diamond and the fullerenes are allotropes of carbon. On the basis of their different structures and properties, predict which has the higher standard molar entropy.
Lime Enormous amounts of lime (CaO) are used in steel industry blast furnaces to remove impurities from iron. Lime is made by heating limestone and other solid forms of \(\mathrm{CaCO}_{3}(s) .\) Why is the standard molar entropy of \(\mathrm{CaCO}_{3}(s)\) higher than that of \(\mathrm{CaO}(s)\) ? At what temperature is the pressure of \(\mathrm{CO}_{2}(g)\) over \(\mathrm{CaCO}_{3}(s)\) equal to 1.0 atm?$$\begin{array}{lcc} & \Delta H_{f}^{\circ}(\mathrm{k} J / \mathrm{mol}) & S^{\circ}[J /(\mathrm{mol} \cdot \mathrm{K})] \\\C a C O_{3}(s) & -1207 & 93 \\\\\hline \mathrm{CaO}(s) & -636 & 40 \\\\\hline \mathrm{CO}_{2}(g) & -394 & 214 \\\\\hline\end{array}$$
Which of the following processes is/are spontaneous? a. A tornado forms. b. A broken cell phone fixes itself. c. You get an \(A\) in this course. d. Hot soup gets cold before it is served.
Calculate the free-energy change for the dissolution in water of one mole of \(\mathrm{NaBr}\) and one mole of \(\mathrm{NaI}\) at \(298 \mathrm{K}\) from the values in the following table. $$\begin{array}{lcc}\hline & \Delta H_{\text {solution }}^{\circ}(\mathrm{k} J / \mathrm{mol}) & \Delta S_{\text {solution }}^{\circ}[J /(\mathrm{mol} \cdot \mathrm{K})] \\\\\text { NaBr } & -0.60 & 57 \\\\\hline \text { Nal } & -7.5 & 74 \\\\\hline\end{array}$$
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