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Show how each of the following strong electrolytes "breaks up" into its component ions upon dissolving in water by drawing molecular-level pictures. a. NaBr b. \(\mathrm{MgCl}_{2}\) c. \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) d. \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) e, \(\mathrm{NaOH}\) f. \(\mathrm{FeSO}_{4}\) g. \(\mathrm{KMnO}_{4}\) h. \(\mathrm{HClO}_{4}\) i. \(\mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\)

Short Answer

Expert verified
a. NaBr (s) 鉄 Na鈦 (aq) + Br鈦 (aq) b. \(\mathrm{MgCl}_{2}\) (s) 鉄 Mg虏鈦 (aq) + 2Cl鈦 (aq) c. \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) (s) 鉄 Al鲁鈦 (aq) + 3NO鈧冣伝 (aq) d. \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) (s) 鉄 2NH鈧勨伜 (aq) + SO鈧劼测伝 (aq) e. \(\mathrm{NaOH}\) (s) 鉄 Na鈦 (aq) + OH鈦 (aq) f. \(\mathrm{FeSO}_{4}\) (s) 鉄 Fe虏鈦 (aq) + SO鈧劼测伝 (aq) g. \(\mathrm{KMnO}_{4}\) (s) 鉄 K鈦 (aq) + MnO鈧勨伝 (aq) h. \(\mathrm{HClO}_{4}\) (s) 鉄 H鈦 (aq) + ClO鈧勨伝 (aq) i. \(\mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) (s) 鉄 NH鈧勨伜 (aq) + C鈧侶鈧僌鈧傗伝 (aq)

Step by step solution

01

a. NaBr

When NaBr dissolves in water, it breaks up into its individual ions: sodium ion (Na鈦) and bromide ion (Br鈦). Therefore, the molecular-level picture is: NaBr (s) 鉄 Na鈦 (aq) + Br鈦 (aq)
02

b. \(\mathrm{MgCl}_{2}\)

When \(\mathrm{MgCl}_{2}\) dissolves in water, it breaks up into its individual ions: magnesium ion (Mg虏鈦) and two chloride ions (2Cl鈦). Therefore, the molecular-level picture is: \(\mathrm{MgCl}_{2}\) (s) 鉄 Mg虏鈦 (aq) + 2Cl鈦 (aq)
03

c. \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\)

When \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) dissolves in water, it breaks up into its individual ions: aluminum ion (Al鲁鈦) and three nitrate ions (3NO鈧冣伝). Therefore, the molecular-level picture is: \(\mathrm{Al}\left(\mathrm{NO}_{3}\right)_{3}\) (s) 鉄 Al鲁鈦 (aq) + 3NO鈧冣伝 (aq)
04

d. \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\)

When \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) dissolves in water, it breaks up into its individual ions: two ammonium ions (2NH鈧勨伜) and one sulfate ion (SO鈧劼测伝). Therefore, the molecular-level picture is: \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) (s) 鉄 2NH鈧勨伜 (aq) + SO鈧劼测伝 (aq)
05

e. \(\mathrm{NaOH}\)

When \(\mathrm{NaOH}\) dissolves in water, it breaks up into its individual ions: sodium ion (Na鈦) and hydroxide ion (OH鈦). Therefore, the molecular-level picture is: \(\mathrm{NaOH}\) (s) 鉄 Na鈦 (aq) + OH鈦 (aq)
06

f. \(\mathrm{FeSO}_{4}\)

When \(\mathrm{FeSO}_{4}\) dissolves in water, it breaks up into its individual ions: iron (II) ion (Fe虏鈦) and sulfate ion (SO鈧劼测伝). Therefore, the molecular-level picture is: \(\mathrm{FeSO}_{4}\) (s) 鉄 Fe虏鈦 (aq) + SO鈧劼测伝 (aq)
07

g. \(\mathrm{KMnO}_{4}\)

When \(\mathrm{KMnO}_{4}\) dissolves in water, it breaks up into its individual ions: potassium ion (K鈦) and permanganate ion (MnO鈧勨伝). Therefore, the molecular-level picture is: \(\mathrm{KMnO}_{4}\) (s) 鉄 K鈦 (aq) + MnO鈧勨伝 (aq)
08

h. \(\mathrm{HClO}_{4}\)

When \(\mathrm{HClO}_{4}\) dissolves in water, it breaks up into its individual ions: hydrogen ion (H鈦) and perchlorate ion (ClO鈧勨伝). Therefore, the molecular-level picture is: \(\mathrm{HClO}_{4}\) (s) 鉄 H鈦 (aq) + ClO鈧勨伝 (aq)
09

i. \(\mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\)

When \(\mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) dissolves in water, it breaks up into its individual ions: ammonium ion (NH鈧勨伜) and acetate ion (C鈧侶鈧僌鈧傗伝). Therefore, the molecular-level picture is: \(\mathrm{NH}_{4} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) (s) 鉄 NH鈧勨伜 (aq) + C鈧侶鈧僌鈧傗伝 (aq)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular-Level Representation
Understanding dissolution at a molecular level is like peeking into a hidden world. Imagine starting with a solid piece of a compound, such as sodium bromide (NaBr), and watching as it vanishes into water. What happens in this "molecular-level" view is that water molecules begin interacting with the NaBr. They surround the individual ions in the solid.
  • The solid breaks apart into ions: Na鈦 and Br鈦.
  • These ions become dispersed within the water. This results in an aqueous solution.

Picture this process as individual dancers leaving a tightly packed group to dance freely around the room. Each dancer (ion) is still distinguishable within the broader flow (solution). So, a molecular-level representation captures these details, showing how each unit of the solid separates into distinct ions as it dissolves.
Ionic Dissociation
Ionic dissociation is the term used to describe this separation process. It involves the breaking of ionic bonds in a compound when dissolved in water, forming charged particles or ions. For example, when magnesium chloride (MgCl鈧) is introduced into water:
  • MgCl鈧 splits into one magnesium ion (Mg虏鈦) and two chloride ions (Cl鈦).
  • Water molecules stabilize these ions, preventing them from immediately recombining.

This transformation is crucial because ions are essential to carrying electrical current through the solution. Unlike non-dissociating molecules, these charged entities make strong electrolytes conductive. Each must be accounted for in solutions, as the number and types of ions can affect properties like acidity, basicity, and conductivity.
Aqueous Solution Chemistry
Aqueous solution chemistry revolves around the interactions in water-based solutions. It focuses on how substances dissolve and behave when submerged in water. In these solutions, water acts as a solvent, dissolving solid, liquid, or gaseous solutes to form a mixture. For example, when a substance like aluminum nitrate (Al(NO鈧)鈧) goes into water:
  • The compound dissociates into aluminum ions (Al鲁鈦) and nitrate ions (NO鈧冣伝).
  • These ions intermingle uniformly throughout the solution, forming an ionic mixture.

Aqueous solutions are prevalent in nature and industry. They enable vital biological functions and industrial processes. Thus, understanding how solutes behave in water is important for applications ranging from medicine to environmental science. The principles governing these solutions explain vital phenomena, like why salts dissolve in water yet not in oils.

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Most popular questions from this chapter

A \(100.0\) -mLaliquot of \(0.200 M\) aqueous potassium hydroxide is mixed with \(100.0 \mathrm{~mL}\) of \(0.200 \mathrm{M}\) aqueous magnesium nitrate. a. Write a balanced chemical equation for any reaction that occurs. b. What precipitate forms? c. What mass of precipitate is produced? d. Calculate the concentration of each ion remaining in solution after precipitation is complete.

Acetylsalicylic acid is the active ingredient in aspirin. It took \(35.17 \mathrm{~mL}\) of \(0.5065 M\) sodium hydroxide to react completely with \(3.210 \mathrm{~g}\) of acetylsalicylic acid. Acetylsalicylic acid has one acidic hydrogen. What is the molar mass of acetylsalicylic acid?

A mixture contains only \(\mathrm{NaCl}\) and \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3} .\) A \(0.456-\mathrm{g}\) sample of the mixture is dissolved in water, and an excess of \(\mathrm{NaOH}\) is added, producing a precipitate of \(\mathrm{Fe}(\mathrm{OH})_{3} .\) The precipitate is filtered, dried, and weighed. Its mass is \(0.107\) g. Calculate the following. a. the mass of iron in the sample b. the mass of \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) in the sample c. the mass percent of \(\mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{3}\) in the sample

What mass of barium sulfate can be produced when \(100.0 \mathrm{~mL}\) of a \(0.100-M\) solution of barium chloride is mixed with \(100.0 \mathrm{~mL}\) of a \(0.100-M\) solution of iron(III) sulfate?

What volume of \(0.100 \mathrm{M} \mathrm{Na}_{3} \mathrm{PO}_{4}\) is required to precipitate all the lead(II) ions from \(150.0 \mathrm{~mL}\) of \(0.250 \mathrm{M} \mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}\) ?

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