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Acetylsalicylic acid is the active ingredient in aspirin. It took \(35.17 \mathrm{~mL}\) of \(0.5065 M\) sodium hydroxide to react completely with \(3.210 \mathrm{~g}\) of acetylsalicylic acid. Acetylsalicylic acid has one acidic hydrogen. What is the molar mass of acetylsalicylic acid?

Short Answer

Expert verified
The molar mass of acetylsalicylic acid is \(180\mathrm{~g/mol}\).

Step by step solution

01

Determine the moles of sodium hydroxide

We are given the volume \((35.17\mathrm{~mL})\) and the concentration \((0.5065 M)\) of the sodium hydroxide solution. We can use these values to find the moles of sodium hydroxide: Moles of sodium hydroxide = Volume (L) × Concentration (M) First, we need to convert the volume from milliliters to liters: Volume (L) = \( \frac{35.17\mathrm{~mL}}{1000\mathrm{~mL/L}} = 0.03517\mathrm{~L} \) Now we can calculate the moles of sodium hydroxide: Moles of sodium hydroxide = \(0.03517\mathrm{~L} \times 0.5065 M = 0.0178\mathrm{~mol} \)
02

Determine the moles of acetylsalicylic acid

Since acetylsalicylic acid has one acidic hydrogen, it means that one mole of acetylsalicylic acid will react with one mole of sodium hydroxide. So, the moles of acetylsalicylic acid will be equal to the moles of sodium hydroxide: Moles of acetylsalicylic acid = Moles of sodium hydroxide = 0.0178 mol
03

Calculate the molar mass of acetylsalicylic acid

Now that we have the moles of acetylsalicylic acid, we can use the given mass of acetylsalicylic acid to find its molar mass. Molar mass of acetylsalicylic acid = \( \frac{Mass}{Moles} \) Molar mass of acetylsalicylic acid = \( \frac{3.210\mathrm{~g}}{0.0178\mathrm{~mol}} \) Molar mass of acetylsalicylic acid = \(180\mathrm{~g/mol} \) The molar mass of acetylsalicylic acid is 180 g/mol.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acetylsalicylic Acid
Acetylsalicylic acid is a well-known compound, commonly found in your medicine cabinet as aspirin. Its chemical formula is C₉H₈O₄. It plays a crucial role in relieving pain, reducing fever, and preventing blood clots. Understanding its structure is essential. It consists of an acetyl group and a salicylic acid group. This is why it is named acetylsalicylic acid.
Acetylsalicylic acid contains one acidic hydrogen atom. This is important because it is the part of the molecule that reacts during an acid-base reaction, such as titration experiments. Knowing its molar mass is also crucial. It helps you understand how much of the substance is involved in chemical reactions, which is essential for determining the dosage in pharmaceuticals.
Chemical Stoichiometry
Chemical stoichiometry is the study of the quantitative relationships in chemical reactions. It's like a recipe in cooking, where you need to mix ingredients in the correct proportions. In chemistry, stoichiometry ensures that reactants are used efficiently, and products are formed as expected. Using stoichiometry, you can predict the amounts of products and reactants required in a chemical reaction.
In the context of acetylsalicylic acid, the stoichiometry is straightforward due to its 1:1 ratio in the reaction with sodium hydroxide. This means that one mole of acetylsalicylic acid will react with one mole of sodium hydroxide to produce a salt and water. Understanding stoichiometry helps you carry out calculations, like finding the molar mass, accurately.
Acid-Base Reaction
An acid-base reaction is a chemical process where an acid and a base react to form a salt and water. These reactions are essential in many areas, including medicine, biology, and chemistry. Acetylsalicylic acid reacts with sodium hydroxide in such a reaction.
In this specific reaction, the acidic hydrogen ion from acetylsalicylic acid combines with a hydroxide ion from sodium hydroxide. This forms water, a neutral compound. The remaining parts of the acid and base combine to form a salt. This process shows how acids and bases neutralize each other, and is crucial for calculating the molar mass of acetylsalicylic acid through titration.
Titration
Titration is an analytical technique used to determine the concentration of an unknown solution. In this exercise, it involves gradually adding a base (sodium hydroxide) to an acid (acetylsalicylic acid) until the reaction is complete. This point is known as the equivalence point, where the amount of base added exactly neutralizes the acid.
During titration, you monitor the pH change to detect the endpoint. It's usually indicated with a color change if an indicator is used. Knowing the concentration and volume of the titrant (sodium hydroxide in this case) allows you to calculate the molar mass of acetylsalicylic acid. Titration is especially useful because it provides accurate and practical ways of understanding reaction dynamics in real-world applications, like pharmaceuticals.

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Most popular questions from this chapter

On the basis of the general solubility rules given in Table 4.1, predict which of the following substances are likely to be soluble in water. a. aluminum nitrate b. magnesium chloride c, rubidium sulfate d. nickel(II) hydroxide e. lead(II) sulfide f. magnesium hydroxide g. iron(III) phosphate

Give an example how each of the following insoluble ionic compounds could be produced using a precipitation reaction. Write the balanced formula equation for each reaction. a. \(\mathrm{Fe}(\mathrm{OH})_{3}(s)\) b. \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}(s)\) c. \(\mathrm{PbSO}_{4}(s)\) d. \(\mathrm{BaCrO}_{4}(s)\)

What volume of each of the following acids will react completely with \(50.00 \mathrm{~mL}\) of \(0.200 \mathrm{M} \mathrm{NaOH}\) ? a. \(0.100 \mathrm{M} \mathrm{HCl}\) b. \(0.150 \mathrm{M} \mathrm{HNO}_{3}\) c. \(0.200 \mathrm{M} \mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\) ( 1 acidic hydrogen)

In the spectroscopic analysis of many substances, a series of standard solutions of known concentration are measured to generate a calibration curve. How would you prepare standard solutions containing \(10.0,25.0,50.0,75.0\), and \(100 . \mathrm{ppm}\) of copper from a commercially produced \(1000.0\) -ppm solution? Assume each solution has a final volume of \(100.0 \mathrm{~mL}\). (See Exercise 121 for definitions.)

A student mixes four reagents together, thinking that the solutions will neutralize each other. The solutions mixed together are \(50.0 \mathrm{~mL}\) of \(0.100 \mathrm{M}\) hydrochloric acid, \(100.0 \mathrm{~mL}\) of \(0.200 \mathrm{M}\) of nitric acid, \(500.0 \mathrm{~mL}\) of \(0.0100 \mathrm{M}\) calcium hydroxide, and \(200.0 \mathrm{~mL}\) of \(0.100 M\) rubidium hydroxide. Did the acids and bases exactly neutralize each other? If not, calculate the concentration of excess \(\mathrm{H}^{+}\) or \(\mathrm{OH}^{-}\) ions left in solution.

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