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Assign the oxidation state for nitrogen in each of the following. a. \(\mathrm{Li}_{3} \mathrm{~N} \quad\) f. \(\mathrm{NO}_{2}\) b. \(\mathrm{NH}_{3} \quad\) g. \(\mathrm{NO}_{2}^{-}\) c. \(\mathrm{N}_{2} \mathrm{H}_{4} \quad\) h. \(\mathrm{NO}_{3}\) d. NO i. \(\mathrm{N}_{2}\) e. \(\mathrm{N}_{3} \mathrm{O}\)

Short Answer

Expert verified
The oxidation states of nitrogen in the given compounds are as follows: a. 尝颈鈧僋: N = -3 b. 狈贬鈧: N = -3 c. 狈鈧侣鈧: N = -2 d. NO: N = +2 e. 狈鈧僌: N = +2/3 f. 狈翱鈧: N = +4 g. 狈翱鈧傗伝: N = +3 h. 狈翱鈧: N = +6 i. 狈鈧: N = 0

Step by step solution

01

Assign oxidation states for each compound

Use the rules for assigning oxidation states to find the oxidation state of nitrogen in each compound. a. Li鈧僋
02

Rule 1 (Alkali metals)

Alkali metals have an oxidation state of +1. Each Li atom has an oxidation state of +1.
03

Rule 3 (Sum of oxidation states)

The sum of oxidation states in a neutral compound should be 0. There are three Li atoms, resulting in a total of +3. To balance the compound, N must have an oxidation state of -3. b. NH鈧
04

Rule 2 (Hydrogen)

Hydrogen has an oxidation state of +1 when bonded to non-metal elements. There are three H atoms, resulting in a total of +3.
05

Rule 3 (Sum of oxidation states)

N must have an oxidation state of -3 to balance the compound. c. N鈧侶鈧
06

Rule 2 (Hydrogen)

There are four H atoms, resulting in a total of +4.
07

Rule 3 (Sum of oxidation states)

Since the compound is neutral and there are two N atoms, each N must have an oxidation state of -2. d. NO
08

Rule 4 (Oxygen)

Oxygen has an oxidation state of -2.
09

Rule 3 (Sum of oxidation states)

To balance the compound, N must have an oxidation state of +2. e. N鈧僌
10

Rule 4 (Oxygen)

Oxygen has an oxidation state of -2.
11

Rule 3 (Sum of oxidation states)

Since there are three N atoms, each N must have an oxidation state of +2/3 to balance the compound. f. NO鈧
12

Rule 4 (Oxygen)

There are two O atoms, resulting in a total of -4.
13

Rule 3 (Sum of oxidation states)

N must have an oxidation state of +4 to balance the compound. g. NO鈧傗伝
14

Rule 4 (Oxygen)

There are two O atoms, resulting in a total of -4.
15

Rule 3 (Sum of oxidation states)

Since the compound has a charge of -1, N must have an oxidation state of +3 to balance the compound. h. NO鈧
16

Rule 4 (Oxygen)

There are three O atoms, resulting in a total of -6.
17

Rule 3 (Sum of oxidation states)

N must have an oxidation state of +6 to balance the compound. i. N鈧
18

Rule 5 (Same element)

Diatomic molecules of the same element have an oxidation state of 0. N鈧 has two N atoms, each with an oxidation state of 0.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nitrogen Compounds
Nitrogen compounds are diverse and found in various chemical forms. They are used in many applications, from fertilizers to explosives. In chemistry, understanding the oxidation states of nitrogen in these compounds helps determine their reactivity and properties.
  • 尝颈鈧僋: A compound where lithium is bound to nitrogen.
  • 狈贬鈧: Known as ammonia, a common nitrogen compound.
  • 狈鈧侣鈧: Hydrazine, used as a rocket propellant.
  • NO: Nitric oxide, involved in various biological processes.
  • 狈鈧僌: Azide oxide, less common but still important in chemistry.
  • 狈翱鈧: Nitrogen dioxide, a significant air pollutant.
  • 狈翱鈧傗伝: Nitrite, found in various biological systems.
  • 狈翱鈧: Nitrate, commonly found in fertilizers.
  • 狈鈧: Molecular nitrogen, making up most of Earth's atmosphere.
Recognizing the structure and composition of these compounds is crucial for assigning the correct oxidation states.
Rules for Assigning Oxidation States
Assigning oxidation states involves following specific rules that simplify the electron accounting in compounds. These rules allow chemists to understand how electrons are distributed in molecules.
  • Alkali Metals: Always have an oxidation state of +1.
  • Hydrogen: Typically, +1 when bonded to non-metals.
  • Oxygen: Generally, -2 in compounds.
  • Sum of Oxidation States: The total must equal the overall charge of the compound.
  • Same Element: In diatomic molecules like N鈧, the oxidation state is 0.
These guidelines are essential for systematically determining unknown oxidation states in chemical compounds.
Oxidation State Calculations
Calculating oxidation states requires applying the rules to balance the charges in a compound. Let's explore some calculations:

Example: Li鈧僋

Lithium, being an alkali metal, has +1. With three lithium atoms, the total is +3, so nitrogen must be -3 to balance.

Example: NH鈧

With hydrogen at +1, the three hydrogens total +3. Therefore, nitrogen is -3 to create a neutral molecule.

Example: NO

Oxygen is -2; thus, nitrogen must be +2 for a balanced equation.
Consistently applying these calculations ensures accurate representation of each element's oxidation state.
Redox Chemistry
Redox chemistry involves the transfer of electrons between species, altering their oxidation states. These reactions are central to many biochemical and industrial processes.
  • Reduction: Gain of electrons, decreasing the oxidation state.
  • Oxidation: Loss of electrons, increasing the oxidation state.
  • Balancing Redox Reactions: Requires equalizing both the mass and charge.
Understanding redox chemistry helps in analyzing processes like cellular respiration or metal corrosion. The shift in oxidation states during these reactions provides insight into the pathways and mechanisms involved.

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Most popular questions from this chapter

Balance each of the following oxidation-reduction reactions by using the oxidation states method. a. \(\mathrm{C}_{2} \mathrm{H}_{6}(g)+\mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g)\) b. \(\mathrm{Mg}(s)+\mathrm{HCl}(a q) \rightarrow \mathrm{Mg}^{2+}(a q)+\mathrm{Cl}^{-}(a q)+\mathrm{H}_{2}(g)\) c. \(\mathrm{Co}^{3+}(a q)+\mathrm{Ni}(s) \rightarrow \mathrm{Co}^{2+}(a q)+\mathrm{Ni}^{2+}(a q)\) d. \(\mathrm{Zn}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(a q) \rightarrow \mathrm{ZnSO}_{4}(a q)+\mathrm{H}_{2}(g)\)

When the following solutions are mixed together, what precipitate (if any) will form? a. \(\mathrm{Hg}_{2}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{CuSO}_{4}(a q)\) b. \(\mathrm{Ni}\left(\mathrm{NO}_{3}\right)_{2}(a q)+\mathrm{CaCl}_{2}(a q)\) c. \(\mathrm{K}_{2} \mathrm{CO}_{3}(a q)+\mathrm{MgI}_{2}(a q)\) d. \(\mathrm{Na}_{2} \mathrm{CrO}_{4}(a q)+\mathrm{AlBr}_{3}(a q)\)

Using the general solubility rules given in Table 4.1, name three reagents that would form precipitates with each of the following ions in aqueous solution. Write the net ionic equation for each of your suggestions. a. chloride ion d. sulfate ion b. calcium ion e. mercury(I) ion, \(\mathrm{Hg}_{2}^{2+}\) c. iron(III) ion f. silver ion

Tris(pentafluorophenyl)borane, commonly known by its acronym BARF, is frequently used to initiate polymerization of ethylene or propylene in the presence of a catalytic transition metal compound. It is composed solely of \(\mathrm{C}, \mathrm{F}\), and \(\mathrm{B}\); it is \(42.23 \% \mathrm{C}\) by mass and \(55.66 \% \mathrm{~F}\) by mass. a. What is the empirical formula of BARF? b. A \(2.251-g\) sample of BARF dissolved in \(347.0 \mathrm{~mL}\) of solution produces a \(0.01267 M\) solution. What is the molecular formula of BARF?

Write net ionic equations for the reaction, if any, that occurs when aqueous solutions of the following are mixed. a. chromium(III) chloride and sodium hydroxide b. silver nitrate and ammonium carbonate c. copper(II) sulfate and mercury(I) nitrate d. strontium nitrate and potassium iodide

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