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Draw all geometrical and linkage isomers of \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\).

Short Answer

Expert verified
The complex \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\) can have a total of four possible isomers: cis-NN, cis-NO, trans-NN, and trans-NO. These isomers arise from the different arrangements of the \(\mathrm{NH}_3\) and \(\mathrm{NO}_2\) ligands around the cobalt ion (cis and trans geometrical isomers) as well as the different ways the \(\mathrm{NO}_2\) ligand can bind to the cobalt ion (through either nitrogen or oxygen, leading to linkage isomers).

Step by step solution

01

Identifying possible geometrical isomers

In an octahedral complex with the general formula \(\mathrm{MA_4B_2}\), there are two possibilities for geometrical isomers: cis and trans arrangements. The cis isomer has the two B ligands adjacent to each other, whereas the trans isomer has the two B ligands opposite each other.
02

Drawing cis and trans isomers

Now, let's draw the cis and trans isomer of the complex \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\). Cis isomer: In this arrangement, the two \(\mathrm{NO}_2\) ligands are adjacent to each other. \( \require{AMScd} \begin{CD} \ @. \mathrm{NO}_2 @. \mathrm{NO}_2 \\ @. \ | \\ \mathrm{NH}_3 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \end{CD} \) Trans isomer: In this arrangement, the two \(\mathrm{NO}_2\) ligands are opposite to each other. \( \require{AMScd} \begin{CD} \ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \\ @. \ | \\ \mathrm{NO}_2 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{NO}_2 \end{CD} \)
03

Identifying possible linkage isomers

In the given complex, only the \(\mathrm{NO}_2\) ligand can exhibit linkage isomerism, as it can bind to the cobalt ion through either the nitrogen (N) or the oxygen (O) atom.
04

Drawing linkage isomers with \(\mathrm{NO}_2\) bonding through nitrogen and oxygen

Now, let's draw the linkage isomers for each geometrical isomer. Cis isomers: 1. Both \(\mathrm{NO}_2\) ligands bind through nitrogen (cis-NN isomer) 2. One \(\mathrm{NO}_2\) ligand binds through nitrogen, and the other binds through oxygen (cis-NO isomer) \( \require{AMScd} \begin{CD} \ @. \mathrm{N}<- \mathrm{O}_2 @. \mathrm{N}<- \mathrm{O}_2 \\ @. \ | \\ \mathrm{NH}_3 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \end{CD} \qquad \require{AMScd} \begin{CD} \ @. \mathrm{N}<- \mathrm{O}_2 @. \mathrm{O}-> \mathrm{N}<- \mathrm{O} \\ @. \ | \\ \mathrm{NH}_3 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \end{CD} \) Trans isomers: 1. Both \(\mathrm{NO}_2\) ligands bind through nitrogen (trans-NN isomer) 2. One \(\mathrm{NO}_2\) ligand binds through nitrogen, and the other binds through oxygen (trans-NO isomer) \( \require{AMScd} \begin{CD} \ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \\ @. \ | \\ \mathrm{N}<- \mathrm{O}_2 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{N}<- \mathrm{O}_2 \end{CD} \qquad \require{AMScd} \begin{CD} \ @. \mathrm{NH}_3 @. \mathrm{NH}_3 \\ @. \ | \\ \mathrm{N}<- \mathrm{O}_2 - \mathrm{Co} @{-}@ _{- \mathrm{NH}_3} \\ @. \ | \\ @. \mathrm{NH}_3 @. \mathrm{O}-> \mathrm{N}<- \mathrm{O} \end{CD} \) In total, there are four possible isomers for the complex \(\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4}\left(\mathrm{NO}_{2}\right)_{2}\): cis-NN, cis-NO, trans-NN, and trans-NO.

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Most popular questions from this chapter

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