/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 15 A certain buffer is made by diss... [FREE SOLUTION] | 91影视

91影视

A certain buffer is made by dissolving \(\mathrm{NaHCO}_{3}\) and \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) in some water. Write equations to show how this buffer neutralizes added \(\mathrm{H}^{+}\) and \(\overline{\mathrm{OH}}^{-}\).

Short Answer

Expert verified
The buffer neutralizes added H鈦 and OH鈦 ions through the reactions: \[ HCO_3^- + H^+ \rightarrow H_2CO_3 \] and \[ CO_3^{2-} + OH^- \rightarrow HCO_3^- \]

Step by step solution

01

Write the dissociation equations for NaHCO鈧 and Na鈧侰O鈧.

When dissolved in water, NaHCO鈧 and Na鈧侰O鈧 dissociate as follows: For NaHCO鈧: \[ NaHCO_3 \rightarrow Na^+ + HCO_3^- \] For Na鈧侰O鈧: \[ Na_2CO_3 \rightarrow 2Na^+ + CO_3^{2-} \]
02

Identify the acidic and basic species in the buffer.

In the buffer solution, HCO鈧冣伝 acts as the acidic species, and CO鈧兟测伝 acts as the basic species.
03

Write the equation for neutralization of H鈦 ions by HCO鈧冣伝.

When H鈦 ions are added to the buffer solution, HCO鈧冣伝 will react with them to neutralize the H鈦 ions. The reaction can be represented as follows: \[ HCO_3^- + H^+ \rightarrow H_2CO_3 \]
04

Write the equation for the neutralization of OH鈦 ions by CO鈧兟测伝.

When OH鈦 ions are added to the buffer solution, CO鈧兟测伝 will react with them to neutralize the OH鈦 ions. The reaction can be represented as follows: \[ CO_3^{2-} + OH^- \rightarrow HCO_3^- \] With these equations, we have found how the buffer solution neutralizes both H鈦 and OH鈦 ions added to it.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Buffer Capacity
Buffer capacity refers to a buffer solution鈥檚 ability to resist changes in pH when small amounts of an acid or a base are added. Think of it like a sponge, soaking up excess hydrogen ions (\(H^+\)) or hydroxide ions (\(OH^-\)) without allowing significant changes in pH.
The greater the buffer capacity, the larger the amount of acid or base that can be added before a notable change in pH occurs.
Buffer solutions have two main components: a weak acid and its conjugate base (or a weak base and its conjugate acid). These components work together to neutralize any added acids or bases, maintaining the pH.
  • When \(H^+\) is added, it's neutralized by the buffer鈥檚 weak base component.
  • When \(OH^-\) is added, the buffer鈥檚 weak acid component can neutralize it.

Choosing a buffer with high capacity is key when you need to stabilize the pH in a solution. This capability is crucial for many biological and chemical processes, helping to maintain conditions necessary for life and accurate reactions.
The Process of Acid-Base Neutralization
Acid-base neutralization is a chemical reaction in which an acid and a base react to form water and a salt, typically resulting in a neutral, or pH-balanced, solution. This is essentially what happens in a buffer solution when it "neutralizes" added acids or bases.
Neutralizing an acid (\(H^+\)) in a buffer means the base component reacts to form water: \(HCO_3^- + H^+ \rightarrow H_2CO_3\). Here, bicarbonate ion (\(HCO_3^-\)) reacts with hydrogen ions to form carbonic acid (\(H_2CO_3\)), preventing the pH from dropping.
Similarly, neutralizing a base (\(OH^-\)) involves the acid component reacting to buffer the solution: \(CO_3^{2-} + OH^- \rightarrow HCO_3^-\). Carbonate ion (\(CO_3^{2-}\)) reacts with hydroxide ions to produce bicarbonate ion, preventing pH from rising.
Such reactions ensure the pH remains stable, making the buffer solution vital in experiments and life processes where controlled pH is essential.
Exploring the Bicarbonate-Carbonate Buffer System
The bicarbonate-carbonate buffer system is a perfect example of how buffers work to maintain pH balance. This buffer, formed from sodium bicarbonate (\(NaHCO_3\)) and sodium carbonate (\(Na_2CO_3\)), is particularly effective at managing shifts in pH.
The equilibrium between bicarbonate ions (\(HCO_3^-\)) and carbonate ions (\(CO_3^{2-}\)) allows the buffer to neutralize both acids and bases.
  • Bicarbonate ion acts as a weak acid, neutralizing added base (\(OH^-\)).
  • Carbonate ion serves as a weak base, neutralizing added acid (\(H^+\)).

This buffering action is crucial in natural systems, such as the human bloodstream, where it helps maintain a stable pH, ensuring optimal conditions for enzymes and chemical reactions necessary for life.
Without this system, slight changes in metabolic processes could lead to severe pH swings, demonstrating the system鈥檚 importance in homeostasis.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Malonic acid \(\left(\mathrm{HO}_{2} \mathrm{CCH}_{2} \mathrm{CO}_{2} \mathrm{H}\right)\) is a diprotic acid. In the titration of malonic acid with \(\mathrm{NaOH}\), stoichiometric points occur at \(\mathrm{pH}=3.9\) and 8.8. A 25.00-mL sample of malonic acid of unknown concentration is titrated with \(0.0984 M \mathrm{NaOH}\), requiring \(31.50 \mathrm{~mL}\) of the \(\mathrm{NaOH}\) solution to reach the phenolphthalein end point. Calculate the concentration of malonic acid in the unknown solution. (See Exercise \(103 .\) )

Amino acids are the building blocks for all proteins in our bodies. A structure for the amino acid alanine is All amino acids have at least two functional groups with acidic or basic properties. In alanine, the carboxylic acid group has \(K_{\mathrm{a}}=4.5 \times 10^{-3}\) and the amino group has \(K_{\mathrm{b}}=7.4 \times 10^{-5} .\) Because of the two groups with acidic or basic properties, three different charged ions of alanine are possible when alanine is dissolved in water. Which of these ions would predominate in a solution with \(\left[\mathrm{H}^{+}\right]=1.0 M ?\) In a solution with \(\left[\mathrm{OH}^{-}\right]=\) \(1.0 M ?\)

A buffer is made using \(45.0 \mathrm{~mL}\) of \(0.750 \mathrm{M} \mathrm{HC}_{3} \mathrm{H}_{5} \mathrm{O}_{2}\left(K_{a}=1.3 \times\right.\) \(10^{-5}\) ) and \(55.0 \mathrm{~mL}\) of \(0.700 \mathrm{M} \mathrm{NaC}_{3} \mathrm{H}_{5} \mathrm{O}_{2} .\) What volume of \(0.10 M\) NaOH must be added to change the \(\mathrm{pH}\) of the original buffer solution by \(2.5 \% ?\)

A certain acetic acid solution has \(\mathrm{pH}=2.68\). Calculate the volume of \(0.0975 M \mathrm{KOH}\) required to reach the equivalence point in the titration of \(25.0 \mathrm{~mL}\) of the acetic acid solution.

Consider the following four titrations. i. \(100.0 \mathrm{~mL}\) of \(0.10 M \mathrm{HCl}\) titrated by \(0.10 \mathrm{M} \mathrm{NaOH}\) ii. \(100.0 \mathrm{~mL}\) of \(0.10 \mathrm{M} \mathrm{NaOH}\) titrated by \(0.10 \mathrm{M} \mathrm{HCl}\) iii. \(100.0 \mathrm{~mL}\) of \(0.10 \mathrm{M} \mathrm{CH}_{3} \mathrm{NH}_{2}\) titrated by \(0.10 \mathrm{M} \mathrm{HCl}\) iv. \(100.0 \mathrm{~mL}\) of \(0.10 M\) HF titrated by \(0.10 \mathrm{M} \mathrm{NaOH}\) Rank the titrations in order of: a. increasing volume of titrant added to reach the equivalence point. b. increasing pH initially before any titrant has been added. c. increasing \(\mathrm{pH}\) at the halfway point in equivalence. d. increasing \(\mathrm{pH}\) at the equivalence point. How would the rankings change if \(\mathrm{C}_{5} \mathrm{H}_{3} \mathrm{~N}\) replaced \(\mathrm{CH}_{3} \mathrm{NH}_{2}\) and if \(\mathrm{HOC}_{6} \mathrm{H}_{5}\) replaced \(\mathrm{HF}\) ?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.