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Write the electron configuration of the cyanide ion \(\left(\mathrm{CN}^{-}\right)\) Name a stable molecule that is isoelectronic with the ion.

Short Answer

Expert verified
The electron configuration of CN鈦 is 1s虏 2s虏 2p鈦 3s虏. A stable isoelectronic molecule is O鈧.

Step by step solution

01

Understand the Cyanide Ion Composition

The cyanide ion (CN鈦) is composed of a carbon (C) and a nitrogen (N) atom. The charge of -1 indicates that the ion has gained one additional electron compared to the neutral atoms.
02

Determine the Total Number of Electrons

Calculate the total electrons: Carbon has 6 electrons, Nitrogen has 7 electrons, and the extra -1 charge adds 1 more electron. Therefore, CN鈦 has a total of 6 + 7 + 1 = 14 electrons.
03

Write the Electron Configuration

The electron configuration for an atom or ion with 14 electrons is derived from the filling order of orbitals: 1. Fill the 1s orbital with 2 electrons: 1s虏 2. Fill the 2s orbital with 2 electrons: 2s虏 3. Fill the 2p orbital with 6 electrons: 2p鈦 4. Fill the 3s orbital with the remaining 2 electrons: 3s虏 Thus, the electron configuration of CN鈦 is: 1s虏 2s虏 2p鈦 3s虏.
04

Identify an Isoelectronic Molecule

A molecule is isoelectronic with another if both have the same number of electrons. The oxygen molecule (O鈧) is isoelectronic with CN鈦 since it also has 16 electrons with the configuration 1s虏 2s虏 2p鈦 3s虏, considering two oxygen atoms without additional charges.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cyanide Ion
The cyanide ion, represented as CN鈦, is a negatively charged ion that plays a crucial role in both organic and inorganic chemistry. It consists of a carbon atom and a nitrogen atom that are bonded together. The ion bears a -1 charge due to the presence of an extra electron. This additional electron impacts both the chemical properties and the structure of the ion.

Understanding the composition of the cyanide ion is essential. Carbon typically has six electrons, while nitrogen has seven. The negative charge indicates that there is one more electron added, making it a total of 14 electrons. This electron configuration bestows CN鈦 certain chemical characteristics, such as its strong binding properties in metal complexes.

The unique structure of the cyanide ion allows it to readily donate electrons to transition metals, forming coordination compounds. It's worth noting that while cyanide is toxic, it holds significant value in various industrial applications such as the extraction of gold.
Isoelectronic
The term "isoelectronic" refers to different species - be they ions, atoms, or molecules - that possess the same number of electrons. This similarity in electron count often leads to comparable electron configurations and similar chemical properties. Understanding this concept is valuable in predicting the behavior of unknown substances based on known ones.

In the context of the cyanide ion, it is isoelectronic with the nitrogen molecule, N鈧, as both contain 14 electrons. This means that CN鈦 and N鈧 will have similar electron configurations and potentially overlapping chemical attributes, despite differences in elemental composition.
  • Similar electron count: CN鈦 (14 electrons) and N鈧 (14 electrons).
  • Leads to analogous electron configurations and bonding characteristics.
  • Beneficial for understanding and predicting molecular behavior in chemistry.
By recognizing isoelectronic relationships, chemists can make informed predictions about molecular stability, reactivity, and electronic arrangements.
Molecular Structure
Molecular structure is central to the properties and functions of molecules. In cyanide ion, CN鈦, the linear structure plays a significant role in its reactive characteristics. This arrangement is a direct consequence of electronic configuration and the bond between carbon and nitrogen.

The carbon-nitrogen bond is a triple bond. This is strong and stable, yet it is also reactive, particularly in the context of coordination chemistry. Given the electron sharing between the two atoms, the structure is compensated electronically, achieving a stable formation despite the negative charge.

This linear structure facilitates electron donation, making CN鈦 a robust ligand in metal complexes.
  • Straight-line arrangement: strong, triple-bonded structure.
  • Stable yet reactive due to potential electron sharing.
  • Functional as an important ligand for metal ion complexes.
Understanding the molecular structure of CN鈦 gives insights into how it interacts with other substances and why it is significant across different chemical domains.
Carbon and Nitrogen Atoms
Carbon and nitrogen are both part of Group 14 and Group 15 of the periodic table, respectively. These elements, fundamental to life, exhibit interesting chemistry particularly when combined as in the cyanide ion. In CN鈦, the carbon and nitrogen atoms form a strong covalent bond.

Carbon, with its four valency electrons, and nitrogen, with five, jointly establish a triple bond in CN鈦. This kind of bonding involves sharing of electrons, which stabilizes the overall structure of the cyanide ion.

The carbon and nitrogen atoms also work together to achieve a full octet, complying with the octet rule that states atoms tend to combine in ways that they have eight electrons in their valence shell.
  • Four electrons from carbon, five from nitrogen, and the shared electrons complete this octet.
  • The additional electron from the negative charge is integrated into the overall configuration.
  • The arrangement of electrons and the resulting bond energy account for the high stability and reactivity of CN鈦.
Learning about carbon and nitrogen in the cyanide ion not only illuminates aspects of CN鈦 itself but also provides a foundation that is applicable to organic chemistry at large.

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Most popular questions from this chapter

The bonds in beryllium hydride \(\left(\mathrm{BeH}_{2}\right)\) molecules are polar, and yet the dipole moment of the molecule is zero. Explain.

How does a delocalized molecular orbital differ from a molecular orbital such as that found in \(\mathrm{H}_{2}\) or \(\mathrm{C}_{2} \mathrm{H}_{4}\) ? What do you think are the minimum conditions (e.g. number of atoms and types of orbitals) for forming a delocalized molecular orbital?

Determine whether (a) \(\mathrm{PCl}_{5}\) and (b) \(\mathrm{H}_{2} \mathrm{CO}\) (C double bonded to \(\mathrm{O}\) ) are polar.

Consider an \(\mathrm{N}_{2}\) molecule in its first excited electronic state, that is, when an electron in the highest occupied molecular orbital is promoted to the lowest empty molecular orbital. (a) Identify the molecular orbitals involved, and sketch a diagram to show the transition. (b) Compare the bond order and bond length of \(\mathrm{N}_{2}^{*}\) with \(\mathrm{N}_{2}\), where the asterisk denotes the excited molecule. (c) Is \(\mathrm{N}_{2}^{*}\) diamagnetic or paramagnetic? (d) When \(\mathrm{N}_{2}^{*}\) loses its excess energy and converts to the ground state \(\mathrm{N}_{2}\), it emits a photon of wavelength \(470 \mathrm{nm}\), which makes up part of the auroras' lights. Calculate the energy difference between these levels.

Both ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\) and benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) contain the \(\mathrm{C}=\mathrm{C}\) bond. The reactivity of ethylene is greater than that of benzene. For example, ethylene readily reacts with molecular bromine, whereas benzene is normally quite inert toward molecular bromine and many other compounds. Explain this difference in reactivity.

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