Chapter 7: Problem 138
The ionization energy of a certain element is \(412 \mathrm{~kJ} / \mathrm{mol}\). When the atoms of this element are in the first excited state, however, the ionization energy is only \(126 \mathrm{~kJ} / \mathrm{mol}\). Based on this information, calculate the wavelength of light emitted in a transition from the first excited state to the ground state.
Short Answer
Step by step solution
Understand the Problem
Calculate Energy Difference
Convert Energy to Joules
Use Energy-Wavelength Relationship
Substitute the Values
Calculate Wavelength
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Wavelength Calculation
- E is the energy in joules (J).
- h is Planck's constant, approximately \(6.626 \times 10^{-34} \, \mathrm{J\cdot s}\).
- c is the speed of light, about \(3.00 \times 10^8 \, \mathrm{m/s}\).
- \lambda (lambda) is the wavelength in meters (converted to nanometers when needed).