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Calculate the \(\mathrm{pH}\) of an aqueous solution at \(25^{\circ} \mathrm{C}\) that is (a) \(0.12 \mathrm{M}\) in \(\mathrm{HCl}\), (b) \(2.4 \mathrm{M}\) in \(\mathrm{HNO}_{3}\), and (c) \(3.2 \times 10^{-4} \mathrm{M}\) in \(\mathrm{HClO}_{4}\).

Short Answer

Expert verified
(a) pH 鈮 0.92; (b) pH 鈮 -0.38; (c) pH 鈮 3.5.

Step by step solution

01

Understanding Strong Acids

Hydrochloric acid (HCl), nitric acid (HNO鈧), and perchloric acid (HClO鈧) are all strong acids. This means they dissociate completely in water. For strong acids, the concentration of hydrogen ions [H鈦篯 is equal to the concentration of the acid.
02

Calculating pH for 0.12 M HCl

Since HCl is a strong acid and dissociates completely, [H鈦篯 = [HCl] = 0.12 M. The pH is calculated using the formula: \[\text{pH} = -\log [\text{H}^+]\]Substitute [H鈦篯 with 0.12:\[\text{pH} = -\log(0.12) \approx 0.92\]
03

Calculating pH for 2.4 M HNO鈧

Similarly, for HNO鈧, [H鈦篯 = [HNO鈧僝 = 2.4 M. Calculate the pH:\[\text{pH} = -\log(2.4) \approx -0.38\]Since negative pH values are possible with strong concentrations, this result is reasonable.
04

Calculating pH for 3.2 x 10鈦烩伌 M HClO鈧

For HClO鈧, [H鈦篯 = [HClO鈧刔 = 3.2 \times 10^{-4} M. Calculate the pH:\[\text{pH} = -\log(3.2 \times 10^{-4}) \approx 3.5\]
05

Interpreting Results

For a strong acid, the lower the concentration, the higher the pH. Even for strong acids, at very low concentrations, pH can be greater than zero. This is reflected in the fact that 3.2 x 10鈦烩伌 M HClO鈧 results in a pH of about 3.5.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Strong Acids
When we talk about strong acids, we refer to acids that completely dissociate in water, releasing all their hydrogen ions. Three prominent strong acids that often appear in chemistry studies are hydrochloric acid (HCl), nitric acid (HNO鈧), and perchloric acid (HClO鈧).
These acids are characterized by their ability to completely ionize in an aqueous solution. This means that when you dissolve a strong acid in water, you can assume that its concentration is equal to the concentration of hydrogen ions \([\text{H}^+]\).
Understanding this property simplifies the calculation of pH, making it straightforward: we use the initial concentration of the acid to determine that of the hydrogen ions directly.
Hydrogen Ion Concentration
Hydrogen ion concentration, represented as \([\text{H}^+]\), is a crucial factor in determining the acidity of a solution. For strong acids, calculating \([\text{H}^+]\) becomes a simple task since the acid dissociates completely.
This means the concentration of hydrogen ions is equal to the concentration of the acid itself. For example, if you have a 0.12 M solution of HCl, the hydrogen ion concentration is also 0.12 M.
Measuring \([\text{H}^+]\) lets us calculate the pH by using the formula \(\text{pH} = -\log [\text{H}^+]\). This logarithmic measure gives us an easy-to-understand scale of acidity.
HCl Dissociation
Hydrochloric acid (HCl) is a prototypical strong acid, demonstrating the concept of complete dissociation. When HCl dissolves in water, it splits entirely into hydrogen ions and chloride ions.
The chemical equation for this process is:
  • \(\text{HCl} \rightarrow \text{H}^+ + \text{Cl}^-\)
This characteristic of HCl as a strong acid means that, in a 0.12 M solution of HCl, the concentration of \([\text{H}^+]\) is also 0.12 M.
Thus, the pH can be calculated as:
  • \(\text{pH} = -\log(0.12) \approx 0.92\)
The pH value is less than 1, highlighting its high acidity.
HNO鈧 Dissociation
Nitric acid (HNO鈧) shares the behavior of strong acids by also fully dissociating in water. In this scenario, it separates into hydrogen and nitrate ions.
The dissociation equation is:
  • \(\text{HNO}_3 \rightarrow \text{H}^+ + \text{NO}_3^-\)
Therefore, in a 2.4 M solution of HNO鈧, the concentration of \([\text{H}^+]\) equals 2.4 M.
The calculation of the pH follows:
  • \(\text{pH} = -\log(2.4) \approx -0.38\)
While a negative pH might seem unusual, it's possible and plausible in solutions with very high hydrogen ion concentrations.
HClO鈧 Dissociation
Perchloric acid (HClO鈧) is another example of a strong acid, dissociating entirely in aqueous solutions into hydrogen ions and perchlorate ions.
The dissociation process can be represented by the equation:
  • \(\text{HClO}_4 \rightarrow \text{H}^+ + \text{ClO}_4^-\)
For a 3.2 \(\times 10^{-4}\) M HClO鈧 solution, the hydrogen ion concentration is the same, 3.2 \(\times 10^{-4}\) M.
This results in a pH calculation:
  • \(\text{pH} = -\log(3.2 \times 10^{-4}) \approx 3.5\)
This higher pH indicates a lower but still acidic solution, emphasizing how concentration affects pH even among strong acids.

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Most popular questions from this chapter

Identify the Lewis acid and the Lewis base in the following reactions: (a) \(5 \mathrm{CO}(g)+\mathrm{Fe}(s) \longrightarrow \mathrm{Fe}(\mathrm{CO})_{5}(l)\) (b) \(\mathrm{NH}_{3}(g)+\mathrm{BCl}_{3}(g) \longrightarrow \mathrm{Cl}_{3} \mathrm{BNH}_{3}(s)\) (c) \(\mathrm{Hg}^{2+}(a q)+4 \mathrm{I}^{-}(a q) \longrightarrow \mathrm{HgI}_{4}^{2-}(a q)\)

When the concentration of a strong acid is not substantially higher than \(1.0 \times 10^{-7} M\), the ionization of water must be taken into account in the calculation of the solution's \(\mathrm{pH}\). (a) Derive an expression for the \(\mathrm{pH}\) of a strong acid solution, including the contribution to \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) from \(\mathrm{H}_{2} \mathrm{O}\). (b) Calculate the pH of a \(1.0 \times 10^{-7} M \mathrm{HCl}\) solution.

\(\mathrm{HF}\) is a weak acid, but its strength increases with concentration. Explain. (Hint: \(\mathrm{F}^{-}\) reacts with \(\mathrm{HF}\) to form \(\mathrm{HF}_{2}^{-}\). The equilibrium constant for this reaction is 5.2 at \(25^{\circ} \mathrm{C} .\) )

The ion product of \(\mathrm{D}_{2} \mathrm{O}\) is \(1.35 \times 10^{-15}\) at \(25^{\circ} \mathrm{C}\). (b) For (a) Calculate \(\mathrm{pD}\) where \(\mathrm{pD}=-\log \left[\mathrm{D}_{3} \mathrm{O}^{+}\right]\). what values of \(\mathrm{pD}\) will a solution be acidic in \(\mathrm{D}_{2} \mathrm{O} ?\) (c) Derive a relation between \(\mathrm{pD}\) and \(\mathrm{pOD}\).

The \(\mathrm{pH}\) of a \(0.30-\mathrm{M}\) solution of a weak base is 10.66 at \(25^{\circ} \mathrm{C}\). What is the \(K_{\mathrm{b}}\) of the base?

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