Chapter 14: Problem 119
The following expression shows the dependence of the half-life of a reaction \(\left(t_{1 / 2}\right)\) on the initial reactant concentration \([\mathrm{A}]_{0}:\) $$ t_{1 / 2} \propto \frac{1}{[\mathrm{~A}]_{0}^{n-1}} $$ where \(n\) is the order of the reaction. Verify this dependence for zeroth-, first-, and second-order reactions.
Short Answer
Step by step solution
Understand the given expression
Zeroth-order reaction analysis
First-order reaction analysis
Second-order reaction analysis
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Zeroth-Order Reaction
- \([A]_0\) is the initial concentration,
- \(k\) is the rate constant.
First-Order Reaction
- The half-life is independent of the initial concentration \([A]_0\).
- It only depends on the rate constant \(k\).
Second-Order Reaction
- When the initial concentration \([A]_0\) is high, the half-life is short.
- Conversely, if the initial concentration is low, the half-life becomes longer.