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A 3.664 -g sample of a monoprotic acid was dissolved in water. It took \(20.27 \mathrm{~mL}\) of a \(0.1578 \mathrm{M}\) \(\mathrm{NaOH}\) solution to neutralize the acid. Calculate the molar mass of the acid.

Short Answer

Expert verified
The molar mass of the acid is approximately 1145 g/mol

Step by step solution

01

Calculate the moles of NaOH

To calculate the number of moles of NaOH use the formula: \(n = c \times V\). Here, \(c = 0.1578 \ M\), and \(V = 20.27 \ mL = 0.02027 \ L\). Then \(n_{NaOH} = 0.1578 \times 0.02027 = 0.0032 \ mol\)
02

Calculate the moles of the acid

Given that the sample is monoprotic, it means that one mole of acid will neutralize one mole of NaOH. So, the moles of the acid are also \(0.0032 \ mol\)
03

Calculate the molar mass

With the moles of acid and the mass, the molar mass can be calculated using the formula: \(Molar \ mass = mass \div moles\). Given that mass = 3.664 g and moles = \(0.0032 \ mol\), the molar mass is \( \frac{3.664}{0.0032} = 1145 \ g/mol\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Neutralization Reaction
In a neutralization reaction, an acid reacts with a base to form water and a salt. This type of reaction is fundamental in chemistry, especially when it comes to titration experiments. A typical neutralization reaction can be simply represented as:
  • Acid + Base 鈫 Salt + Water
The specific reaction depends on the acid and base involved. For example, when sulfuric acid (a common acid) reacts with sodium hydroxide (NaOH, a base), the result is sodium sulfate (a salt) and water:
  • \[H_2SO_4 + 2NaOH 鈫 Na_2SO_4 + 2H_2O\]
In the context of the given exercise, the neutralization reaction involves a monoprotic acid. This means that for every molecule of acid, only one molecule of NaOH is needed to achieve neutralization. Understanding whether an acid is monoprotic or polyprotic is essential as it dictates the stoichiometry鈥攖he mole ratio in the reaction.Neutralization reactions are not only pivotal in understanding chemical reactions but also in practical applications such as determining the concentration of unknown solutions during titrations. They provide a clear-cut method for measuring the exact point at which an acid has completely reacted with a base, often using an indicator or pH meter.
Monoprotic Acid
A monoprotic acid is an acid that can donate one hydrogen ion (H鈦) per molecule to a base in a chemical reaction. Some common examples of monoprotic acids include hydrochloric acid (HCl), nitric acid (HNO鈧), and acetic acid (CH鈧僀OOH). This single proton donating property simplifies their reactions and calculations in titrations. Characteristics of monoprotic acids include:
  • Simple reaction mechanisms as each acid molecule donates one H鈦 ion.
  • Straightforward stoichiometry, making calculations simpler, especially in acid-base titrations.
  • Useful in calculating molar mass because the number of moles of the acid will be equivalent to the number of moles of the base in a neutralization reaction.
In the original exercise, the monoprotic nature of the acid meant that the moles of acid were directly equal to the moles of NaOH used. This direct relationship allows for quick calculation of the acid's molar mass once you know the amount of NaOH it reacted with and the initial mass of the acid used in the experiment.
Acid-Base Titration
Acid-base titration is a laboratory method used to determine the concentration of an unknown acid or base by reacting it with a base or acid of known concentration. It involves the careful addition of one solution to another while measuring the pH change until the reaction reaches the equivalence point, where neutralization is complete. Steps involved in an acid-base titration include:
  • Prepare a solution of the acid whose concentration is to be determined.
  • Gradually add a base of known concentration (the titrant) using a burette.
  • Use an appropriate indicator to detect the endpoint, which signals a near-neutral pH.
The equivalence point is not always at pH 7, especially if the acid or base is weak, but careful calibration and calculation will allow an accurate determination of concentration. In the provided example, an acid of unknown concentration was neutralized using NaOH, a strong base. The reaction's stoichiometry, verified by the fact that the acid is monoprotic, allowed for straightforward calculation. Titration is widely used not just in educational settings but also in industries like pharmaceuticals and food production, where precise measurements of solution concentration are crucial.

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Most popular questions from this chapter

The concentration of lead ions \(\left(\mathrm{Pb}^{2+}\right)\) in a sample of polluted water that also contains nitrate ions \(\left(\mathrm{NO}_{3}^{-}\right)\) is determined by adding solid sodium sulfate \(\left(\mathrm{Na}_{2} \mathrm{SO}_{4}\right)\) to exactly \(500 \mathrm{~mL}\) of the water. (a) Write the molecular and net ionic equations for the reaction. (b) Calculate the molar concentration of \(\mathrm{Pb}^{2+}\) if \(0.00450 \mathrm{~g}\) of \(\mathrm{Na}_{2} \mathrm{SO}_{4}\). was needed for the complete precipitation of \(\mathrm{Pb}^{2+}\) ions as \(\mathrm{PbSO}_{4}\).

The \(\mathrm{SO}_{2}\) present in air is mainly responsible for the acid rain phenomenon. Its concentration can be determined by titrating against a standard permanganate solution as follows: \(5 \mathrm{SO}_{2}+2 \mathrm{MnO}_{4}^{-}+2 \mathrm{H}_{2} \mathrm{O} \longrightarrow\) \(5 \mathrm{SO}_{4}^{2-}+2 \mathrm{Mn}^{2+}+4 \mathrm{H}^{+}\) Calculate the number of grams of \(\mathrm{SO}_{2}\) in a sample of air if \(7.37 \mathrm{~mL}\) of \(0.00800 \mathrm{M} \mathrm{KMnO}_{4}\) solution are required for the titration.

Can the following decomposition reaction be characterized as an acid-base reaction? Explain. \(\mathrm{NH}_{4} \mathrm{Cl}(s) \longrightarrow \mathrm{NH}_{3}(g)+\mathrm{HCl}(g)\)

Carbon dioxide in air can be removed by an aqueous metal hydroxide solution such as \(\mathrm{LiOH}\) and \(\mathrm{Ba}(\mathrm{OH})_{2} .\) (a) Write equations for the reactions. (Carbon dioxide reacts with water to form carbonic acid.) (b) Calculate the mass of \(\mathrm{CO}_{2}\) that can be removed by \(5.00 \times 10^{2} \mathrm{~mL}\) of a \(0.800 \mathrm{M} \mathrm{LiOH}\) and a \(0.800 M \mathrm{Ba}(\mathrm{OH})_{2}\) solution. (c) Which solution would you choose for use in a space capsule and which for use in a submarine?

Oxalic acid \(\left(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\right)\) is present in many plants and vegetables. If \(24.0 \mathrm{~mL}\) of \(0.0100 \mathrm{M} \mathrm{KMnO}_{4}\) solution is needed to titrate \(1.00 \mathrm{~g}\) of a sample of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) to the equivalence point, what is the percent by mass of \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) in the sample? The net ionic equation is \(2 \mathrm{MnO}_{4}^{-}+16 \mathrm{H}^{+}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow\) \(2 \mathrm{Mn}^{2+}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O}\)

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