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Estimate the relative sizes of the following species: \(\mathrm{Li}, \mathrm{Li}^{+}, \mathrm{Li}^{-}\)

Short Answer

Expert verified
The relative sizes of the lithium species are \( \mathrm{Li}^{+} < \mathrm{Li} < \mathrm{Li}^{-} \).

Step by step solution

01

Understand atomic size

The atomic size or atomic radius is determined by the distance between the nucleus and the electron cloud around it. It depends on the number of electrons, the charge of the nucleus and the energy level. In a neutral atom, number of protons in the nucleus equals the number of electrons. In ions, the number of electrons increases or decreases, but the number of protons stays the same.
02

Consider Lithium atom

In a neutral Lithium atom (\( \mathrm{Li} \)), there are three protons in its nucleus and three electrons in its electron cloud.
03

Consider Lithium ions

In a Lithium cation (\( \mathrm{Li}^{+} \)), one electron is lost. So, there are more protons than electrons and therefore, more attraction from the nucleus, making the size smaller. In a Lithium anion (\( \mathrm{Li}^{-} \)), one electron is gained. This additional electron adds to the repulsion in the electron cloud, hence, the size of the ion becomes larger than the neutral atom.
04

Order by size

Thus, the sizes of these species can be ordered as: \( \mathrm{Li}^{+} < \mathrm{Li} < \mathrm{Li}^{-} \). The Lithium cation is the smallest due to the removal of an electron and strongest attraction from the nucleus, the neutral Lithium atom is larger, and the Lithium anion is the largest due to additional repulsion in the electron cloud.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lithium Atom
The lithium atom (\( \mathrm{Li} \)) is a fascinating example in studying atomic structures. In its neutral state, lithium hosts three protons in its nucleus and three electrons that orbit this nucleus. This stable setup means each positive charge (proton) is matched with a negative charge (electron), balancing the atom.
Lithium belongs to the alkali metal group and is found on the far left of the periodic table, making it a prime subject when analyzing atomic radii trends. The electrons of lithium configure themselves into the shells around the nucleus, where the inner shell can hold two electrons and the outer shell holds one.
  • The distance from the nucleus to the outer electrons determines lithium's atomic radius.
  • Along with these electron placements, the energy levels and the nuclear charge significantly influence how confined or dispersed an electron cloud will be.
Lithium Ions
Lithium ions emerge when lithium atoms either lose or gain electrons. A lithium cation (\( \mathrm{Li}^{+} \)) forms when the lithium atom loses an electron. With two electrons and a remaining configuration similar to that of helium, the lithium ion's electronic structure becomes \( 1s^2 \). This removal of an electron generates a stronger nuclear pull on the reduced electron cloud, making the cation smaller.
On the flip side, the lithium anion (\( \mathrm{Li}^{-} \)) results from the gain of an electron, adding to the electron cloud. This additional electron weakens the nuclear attraction and increases electron-electron repulsion, expanding the anion's size beyond that of the neutral lithium atom.
  • In \( \mathrm{Li}^{+} \), the electron cloud becomes contracted as nuclear attraction overcomes electron repulsion due to fewer electrons.
  • In \( \mathrm{Li}^{-} \), added electrons lead to a larger ion due to increased electron repulsion.
Cation and Anion Size Comparison
When discussing ion size comparisons, especially for lithium, understanding the difference between cations and anions is crucial. The rule of thumb is that cations are typically smaller than their neutral counterparts, whereas anions are larger.
For lithium:
  • The cation \( \mathrm{Li}^{+} \) is smaller than the neutral lithium (\( \mathrm{Li} \)) due to the loss of an electron, enhancing the nucleus's attraction over the remaining electrons.
  • The neutral lithium atomic size falls in between the cation and anion because it maintains equilibrium between protons and electrons.
  • The anion \( \mathrm{Li}^{-} \), the largest, results from added electron repulsion that stretches out the electron cloud.
Thus, the size order for these species can be noted as \( \mathrm{Li}^{+} < \mathrm{Li} < \mathrm{Li}^{-} \). This demonstrates the clear size variation based on electron arrangement, helping students grasp the fundamental ideas in atomic and ionic size assessments.

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Most popular questions from this chapter

Consult a handbook of chemical and physical data (ask your instructor where you can locate a copy of the handbook) to find (a) two metals less dense than water, (b) two metals more dense than mercury, (c) the densest known solid metallic element, (d) the densest known solid nonmetallic element.

Give two examples of each of the following: (a) a diatomic molecule containing atoms of the same element, (b) a diatomic molecule containing atoms of different elements, (c) a polyatomic molecule containing atoms of the same element, (d) a polyatomic molecule containing atoms of different elements.

Describe the contributions of the following scientists to our knowledge of atomic structure: J. J. Thomson, R. A. Millikan, Ernest Rutherford, James Chadwick.

Which of the following compounds are likely to be ionic? Which are likely to be molecular? \(\mathrm{CH}_{4}\), \(\mathrm{NaBr}, \mathrm{BaF}_{2}, \mathrm{CCl}_{4}, \mathrm{ICl}, \mathrm{CsCl}, \mathrm{NF}_{3}\)

In Section 2.1 it was pointed out that mass and energy are alternate aspects of a single entity called mass-energy. The relationship between these two physical quantities is Einstein's famous equation, \(E=m c^{2},\) where \(E\) is energy, \(m\) is mass, and \(c\) is the speed of light. In a combustion experiment, it was found that \(12.096 \mathrm{~g}\) of hydrogen molecules combined with \(96.000 \mathrm{~g}\) of oxygen molecules to form water and released \(1.715 \times 10^{3} \mathrm{~kJ}\) of heat. Calculate the corresponding mass change in this process and comment on whether the law of conservation of mass holds for ordinary chemical processes. (Hint: The Einstein equation can be used to calculate the change in mass as a result of the change in energy. \(1 \mathrm{~J}=1 \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s}^{2}\) and \(\left.c=3.00 \times 10^{8} \mathrm{~m} / \mathrm{s} .\right)\)

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