/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Classify each of the following s... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Classify each of the following substances as an element or a compound: (a) hydrogen, (b) water, (c) gold, (d) sugar.

Short Answer

Expert verified
Hydrogen and gold are elements, while water and sugar are compounds.

Step by step solution

01

Identify hydrogen

Hydrogen is an element as it only consists of hydrogen atoms.
02

Identify water

Water, or H2O, is a compound because it is composed of two different elements - hydrogen and oxygen that are chemically bonded.
03

Identify gold

Gold, often denoted as Au, is an element because it is only made up of gold atoms.
04

Identify sugar

Sugar, or C12H22O11, is a compound as it is composed of carbon (C), hydrogen (H), and oxygen (O) atoms that are chemically bonded.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Substances Classification
Understanding the classification of chemical substances is pivotal for grasping the basic concepts of chemistry.
Simplifying it, substances can be broadly identified as elements or compounds. Elements are pure substances which consist of a single type of atom, meaning they cannot be broken down into simpler substances by chemical means. Examples of elements include hydrogen (H) and gold (Au), as mentioned in the exercise.

On the flip side, compounds are substances that are made up of two or more different types of atoms chemically bonded together. Water (H2O) and sugar (C12H22O11) are prime examples of compounds. They emerge from a chemical reaction where elements combine to form a new substance with distinct properties from those of the individual elements. Identifying whether a substance is an element or a compound is crucial in the study of chemistry and has practical implications in fields such as material science, pharmacology, and environmental science.
Chemical Bonding
At the core of understanding compounds, like water and sugar from our exercise, is chemical bonding. Chemical bonds are the attractive forces holding atoms together to form compounds. These can be ionic, covalent, or metallic bonds, each with unique properties.

Ionic bonding occurs when electrons are transferred from one atom to another, leading to the formation of ions that attract each other. This type of bond is typically found between metals and non-metals. Covalent bonding involves the sharing of electron pairs between atoms. This bond is common in organic compounds and is the reason why the atoms in a water molecule (H2O) stick together. Metallic bonding is characterized by a 'sea of electrons' that freely flow around a lattice of metal cations. Each type of bonding gives rise to different properties in substances, which explains why elements and compounds behave differently in various conditions.
Atomic Composition
The atomic composition of a substance tells us the types and ratios of atoms present within that substance. It’s the defining feature that differentiates between elements and compounds.

For elements, atomic composition is comparatively straightforward; all atoms in a pure element are identical. For instance, a piece of gold jewelry contains only gold atoms. In contrast, compounds, such as sugar, have a more complex atomic composition involving a set ratio of atoms. In the formula C12H22O11, used to represent sugar, the numbers tell us not only the types of atoms (carbon, hydrogen, and oxygen) but also the specific ratio of these atoms, which is crucial for the compound's structure and properties. Understanding atomic composition allows chemists to predict how a substance will react chemically and is fundamental in areas like stoichiometry, where chemical equations must be balanced based on the number of atoms involved in reactions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A student is given a crucible and asked to prove whether it is made of pure platinum. She first weighs the crucible in air and then weighs it suspended in water (density \(=0.9986 \mathrm{~g} / \mathrm{mL}\) ). The readings are \(860.2 \mathrm{~g}\) and \(820.2 \mathrm{~g},\) respectively. Based on these measurements and given that the density of platinum is \(21.45 \mathrm{~g} / \mathrm{cm}^{3},\) what should her conclusion be? (Hint: An object suspended in a fluid is buoyed up by the mass of the fluid displaced by the object. Neglect the buoyance of air.)

Lithium is the least dense metal known (density: \(0.53 \mathrm{~g} / \mathrm{cm}^{3}\) ). What is the volume occupied by \(1.20 \times 10^{3} \mathrm{~g}\) of lithium?

Do the following statements describe chemical or physical properties? (a) Oxygen gas supports combustion. (b) Fertilizers help to increase agricultural production. (c) Water boils below \(100^{\circ} \mathrm{C}\) on top of \(\mathrm{a}\) mountain. (d) Lead is more dense than aluminum. (e) Uranium is a radioactive element.

Express the wing numbers as decimals: (a) \(1.52 \times 10^{-2},\) (b) \(7.78 \times 10^{-8}\)

A graduated cylinder is tilled to the \(40.00-\mathrm{mL}\) mark with a mineral oil. The masses of the cylinder before and after the addition of the mineral oil are \(124.966 \mathrm{~g}\) and \(159.446 \mathrm{~g},\) respectively. In a separate experiment, a metal ball bearing of mass \(18.713 \mathrm{~g}\) is placed in the cylinder and the cylinder is again filled to the 40.00 -mL mark with the mineral oil. The combined mass of the ball bearing and mineral oil is 50.952 g. Calculate the density and radius of the ball bearing. [The volume of a sphere of radius \(r\) is $\left.(4 / 3) \pi r^{3} .\right].

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.