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True or false? In general, a large atom has a smaller electronegativity. Explain.

Short Answer

Expert verified
True. In general, a large atom has a smaller electronegativity due to the greater distance between the nucleus and valence electrons, which reduces its ability to attract electrons towards itself in a chemical bond.

Step by step solution

01

Definition of Electronegativity

Electronegativity is the tendency of an atom to attract a bonding pair of electrons. It is a measure of how strongly an atom can attract electrons towards itself in a chemical bond. Electronegativity values can be found on the periodic table, with higher values indicating a higher electronegativity.
02

Periodic Trend of Electronegativity

Electronegativity generally increases from left to right across a period and decreases as we move down a group on the periodic table. This is because as we go across a period, the number of protons in the nucleus increases, resulting in a stronger positive charge that attracts electrons more effectively. When we move down a group, atoms have more energy levels which leads to a greater distance between the nucleus and valence electrons, reducing the attractive force.
03

Atom Size and Electronegativity

A larger atom has more energy levels and a greater distance between the nucleus and its valence electrons. This makes it more difficult for the atom to attract electrons, resulting in a lower electronegativity value. Conversely, smaller atoms have fewer energy levels and a shorter distance between the nucleus and valence electrons, making it easier for the atom to attract electrons and resulting in a higher electronegativity value.
04

Conclusion

The statement "In general, a large atom has a smaller electronegativity" is true. As the size of an atom increases, its electronegativity tends to decrease due to the greater distance between the nucleus and valence electrons, leading to a decreased ability to attract electrons towards the atom in a chemical bond.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Trends
Periodic trends refer to patterns or recurring characteristics observed in the elements of the periodic table. One notable trend relates to electronegativity, where its values increase from left to right across a period. This pattern is due to the increase in the nuclear charge—the number of protons in the nucleus—leading to a stronger pull on the valence electrons. As an element gains more protons moving across a period, its ability to attract electrons rises. On the other hand, as we move down a group, the electronegativity decreases. With each advancing row, the atoms have more electron shells. This additional shielding makes it harder for the nucleus to attract valence electrons effectively. Understanding these trends helps in predicting how different elements behave in various chemical reactions.
Atomic Size
Atomic size, or atomic radius, is the distance from the nucleus of an atom to the outermost shell of electrons. This characteristic changes as you move across the periodic table. When moving from left to right across a period, the atomic size decreases. This occurs because the increasing number of protons draws the electron cloud closer to the nucleus, thus reducing the radius. In contrast, as you move down a group, the atomic size increases. Each new row adds another electron shell, expanding the space that the electrons occupy and thus increasing the atom's overall size. The atomic size is crucial in determining various other properties, including electronegativity, as larger atoms generally have a weaker attraction to their valence electrons because the nuclear charge is more "shielded" by the inner electrons.
Chemical Bonding
Chemical bonding involves the joining of atoms to form molecules or compounds. At the heart of bonding is the concept of electronegativity, which influences how atoms share or transfer electrons. Atoms strive for stability, often achieved by having a complete outer electron shell, commonly known as the octet rule. To gain or lose valence electrons, atoms form different types of bonds: covalent, ionic, or metallic.
  • Covalent bonds: Here, atoms share electron pairs. If the sharing is equal, the bond is nonpolar; if not, it is polar.
  • Ionic bonds: Involves the transfer of electrons from one atom to another, creating ions that attract each other due to opposite charges.
  • Metallic bonds: Involves electrons flowing freely among a lattice of atoms, often seen in metals.
Electronegativity plays a pivotal role in determining the type of bond formed and its characteristics, affecting properties like bond strength and molecule polarity.

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Most popular questions from this chapter

Which member of the following pairs would you expect to be more energetically stable? Justify each choice. a. \(\mathrm{NaBr}\) or \(\mathrm{NaBr}_{2}\) b. \(\mathrm{ClO}_{4}\) or \(\mathrm{ClO}_{4}^{-}\) c. \(\mathrm{SO}_{4}\) or \(\mathrm{XeO}_{4}\) d. \(\mathrm{OF}_{4}\) or \(\mathrm{SeF}_{4}\)

In general, the higher the charge on the ions in an ionic compound, the more favorable the lattice energy. Why do some stable ionic compounds have \(+1\) charged ions even though \(+4,+5,\) and \(+6\) charged ions would have a more favorable lattice energy?

List the bonds \(\mathrm{P}-\mathrm{Cl}, \mathrm{P}-\mathrm{F}, \mathrm{O}-\mathrm{F},\) and \(\mathrm{Si}-\mathrm{F}\) from least polar to most polar.

Think of forming an ionic compound as three steps (this is a simplification, as with all models): (1) removing an electron from the metal; (2) adding an electron to the nonmetal; and (3) allowing the metal cation and nonmetal anion to come together. a. What is the sign of the energy change for each of these three processes? b. In general, what is the sign of the sum of the first two processes? Use examples to support your answer. c. What must be the sign of the sum of the three processes? d. Given your answer to part c, why do ionic bonds occur? e. Given your above explanations, why is NaCl stable but not \(\mathrm{Na}_{2} \mathrm{Cl} ? \mathrm{NaCl}_{2} ?\) What about MgO compared to \(\mathrm{MgO}_{2} ? \mathrm{Mg}_{2} \mathrm{O} ?\)

Predict the molecular structure for each of the following. (See Exercises 115 and 116.) a. \(\mathrm{BrFI}_{2} \quad\) b. \(\mathrm{XeO}_{2} \mathrm{F}_{2} \quad\) c. \(\mathrm{TeF}_{2} \mathrm{Cl}_{3}^{-}\) For each formula there are at least two different structures that can be drawn using the same central atom. Draw all possible structures for each formula.

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