/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 109 One bit of evidence that the qua... [FREE SOLUTION] | 91影视

91影视

One bit of evidence that the quantum mechanical model is 鈥渃orrect鈥 lies in the magnetic properties of matter. Atoms with unpaired electrons are attracted by magnetic fields and thus are said to exhibit paramagnetism. The degree to which this effect is observed is directly related to the number of unpaired electrons present in the atom. Consider the ground-state electron configurations for Li, N, Ni, Te, Ba, and Hg. Which of these atoms would be expected to be paramagnetic, and how many unpaired electrons are present in each paramagnetic atom?

Short Answer

Expert verified
The paramagnetic atoms among the given elements are: - Lithium (Li) with 1 unpaired electron - Nitrogen (N) with 3 unpaired electrons - Nickel (Ni) with 2 unpaired electrons - Tellurium (Te) with 2 unpaired electrons Barium (Ba) and Mercury (Hg) are not expected to be paramagnetic due to the absence of unpaired electrons.

Step by step solution

01

Electron Configurations

To determine the ground-state electron configurations, we must follow the Aufbau principle and organize the electrons according to the increasing energy levels and arrows (鈫, 鈫) representing the electrons and their spins. - Lithium (Li) - Atomic number 3: Electron configuration is 1s虏 2s鹿 - Nitrogen (N) - Atomic number 7: Electron configuration is 1s虏 2s虏 2p鲁 - Nickel (Ni) - Atomic number 28: Electron configuration is 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鈦 - Tellurium (Te) - Atomic number 52: Electron configuration is 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 - Barium (Ba) - Atomic number 56: Electron configuration is 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 - Mercury (Hg) - Atomic number 80: Electron configuration is 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鹿鈦
02

Identifying Unpaired Electrons

We can now examine the electron configurations to find the presence of unpaired electrons, responsible for the paramagnetism: - Lithium (Li): 1s虏 2s鹿 - 1 unpaired electron - Nitrogen (N): 1s虏 2s虏 2p鲁 - 3 unpaired electrons - Nickel (Ni): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鈦 - 2 unpaired electrons - Tellurium (Te): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 - 2 unpaired electrons - Barium (Ba): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 - 0 unpaired electrons - Mercury (Hg): 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p鈦 5s虏 4d鹿鈦 5p鈦 6s虏 4f鹿鈦 5d鹿鈦 - 0 unpaired electrons
03

Final Answer

According to the electron configurations identified in Step 2, the following atoms are expected to be paramagnetic: - Lithium (Li) with 1 unpaired electron - Nitrogen (N) with 3 unpaired electrons - Nickel (Ni) with 2 unpaired electrons - Tellurium (Te) with 2 unpaired electrons Barium (Ba) and Mercury (Hg) have no unpaired electrons, therefore they are not expected to exhibit paramagnetism.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quantum Mechanical Model
The quantum mechanical model of the atom is a fundamental theory in chemistry that provides a comprehensive explanation of atomic structure. Unlike earlier models, it does not describe electrons as moving in fixed orbits around the nucleus. Instead, electrons are treated as wave-like entities that occupy regions called atomic orbitals. These orbitals can be visualized as probability clouds where an electron is more likely to be found.
The model uses complex mathematics, incorporating principles from quantum mechanics to account for the behavior of electrons. This model allows us to predict various properties of atoms, including their magnetic behaviors, which are tied to the arrangement and spin of electrons.
Understanding this model is central to explaining how atoms interact with magnetic fields, especially in phenomena like paramagnetism, where an atom exhibits magnetic properties due to the presence of unpaired electrons.
Electron Configuration
Electron configuration is the description of the distribution of electrons in an atom's orbitals. It follows a specific order based on increasing energy levels, often depicted using the notation derived from the Aufbau principle. This principle dictates that electrons fill lower-energy orbitals before occupying higher-energy ones.
For example:
  • Lithium's configuration: 1s虏 2s鹿 indicates electrons in the 1s and 2s orbitals.
  • Nitrogen鈥檚 configuration: 1s虏 2s虏 2p鲁 reflects electrons in the 1s, 2s, and partially filled 2p orbitals.
The electron configuration strongly influences an atom's chemical properties and reactivities. By understanding the electron distributions, we can predict which elements might exhibit paramagnetism, as those with partially filled subshells often have unpaired electrons.
Unpaired Electrons
Unpaired electrons are ones that do not have a corresponding paired electron with the opposite spin in the same orbital. Their presence significantly impacts an atom's magnetic properties, as unpaired electrons contribute to paramagnetism.
An unpaired electron creates a magnetic moment because of its spin. Atoms with one or more unpaired electrons will typically align in a magnetic field, causing the atom to be attracted to the field. For instance:
  • Lithium has 1 unpaired electron, making it paramagnetic.
  • Nitrogen boasts 3 unpaired electrons, resulting in strong paramagnetism.
The counting of unpaired electrons in electron configurations helps predict whether an atom will demonstrate magnetic behavior.
Magnetic Properties
The magnetic properties of an atom or assembly of atoms arise primarily from the behavior of their electrons. Atoms can be classified as paramagnetic or diamagnetic based on the nature of their electron spins.
**Paramagnetic Substances:** These contain one or more unpaired electrons. When exposed to a magnetic field, the unpaired electrons align with the field, making the material weakly attracted to the magnetic source. This attraction is proportionate to the number of unpaired electrons. Examples include nickel and nitrogen, both of which have unpaired electrons.
**Diamagnetic Substances:** Atoms with all paired electrons fall into this category. They are not attracted to magnetic fields and may exhibit slight repulsion. Barium and mercury, which have complete electron pairs, are examples.
Atomic Structure
The atomic structure is the arrangement of fundamental particles 鈥 protons, neutrons, and electrons 鈥 in an atom. This structure is central to understanding how an atom behaves chemically and physically.
Protons and neutrons form the nucleus, which is positively charged due to the protons. Electrons orbit around the nucleus in designated energy levels or shells. The structure of these electron shells and subshells determines an atom's properties and reactivity.
Atoms with complex structures, like mercury which has electrons filling many energy levels, tend to have all its electron spin states paired, leading to diamagnetic behavior. Conversely, simpler structures, like that of lithium, usually have at least one unpaired electron, influencing their paramagnetic characteristics.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The elements Si, Ga, As, Ge, Al, Cd, S, and Se are all used in the manufacture of various semiconductor devices. Write the expected electron configuration for these atoms.

Calculate the wavelength of light emitted when each of the following transitions occur in the hydrogen atom. What type of electromagnetic radiation is emitted in each transition? a. \(n=4 \rightarrow n=3\) b. \(n=5 \rightarrow n=4\) c. \(n=5 \rightarrow n=3\)

Consider the following ionization energies for aluminum: $$\begin{array}{c}{\operatorname{Al}(g) \longrightarrow \mathrm{Al}^{+}(g)+\mathrm{e}^{-} \quad I_{1}=580 \mathrm{kJ} / \mathrm{mol}} \\\ {\mathrm{Al}^{+}(g) \longrightarrow \mathrm{Al}^{2+}(g)+\mathrm{e}^{-} \quad I_{2}=1815 \mathrm{kJ} / \mathrm{mol}} \\ {\mathrm{Al}^{2+}(g) \longrightarrow \mathrm{Al}^{3+}(g)+\mathrm{e}^{-} \quad I_{3}=2740 \mathrm{kJ} / \mathrm{mol}} \\ {\mathrm{Al}^{3+}(g) \longrightarrow \mathrm{Al}^{4+}(g)+\mathrm{e}^{-} \quad I_{4}=11,600 \mathrm{kJ} / \mathrm{mol}}\end{array}$$ a. Account for the trend in the values of the ionization energies. b. Explain the large increase between \(I_{3}\) and \(I_{4}\)

Predict some of the properties of element 117 (the symbol is Uus, following conventions proposed by the International Union of Pure and Applied Chemistry, or IUPAC). a. What will be its electron configuration? b. What element will it most resemble chemically? c. What will be the formula of the neutral binary compounds it forms with sodium, magnesium, carbon, and oxygen? d. What oxyanions would you expect Uus to form?

Element 106 has been named seaborgium, Sg, in honor of Glenn Seaborg, discoverer of the first transuranium element. a. Write the expected electron configuration for element 106. b. What other element would be most like element 106 in its properties? c. Predict the formula for a possible oxide and a possible oxyanion of element 106.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.