/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 Determine the density ( \(\mathr... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the density ( \(\mathrm{g} / \mathrm{mL}\) ) for each of the following: a. The fluid in a car battery has a volume of \(125 \mathrm{~mL}\) and a mass of \(155 \mathrm{~g}\). b. A plastic material weighs \(2.68 \mathrm{lb}\) and has a volume of \(3.5 \mathrm{~L}\) c. A \(5.00-\mathrm{mL}\) urine sample from a person suffering from diabetes mellitus has a mass of \(5.025 \mathrm{~g}\). d. A solid object with a mass of \(1.65 \mathrm{lb}\) and a volume of \(170 \mathrm{~mL}\)

Short Answer

Expert verified
Densities: (a) 1.24 g/mL, (b) 0.347 g/mL, (c) 1.005 g/mL, (d) 4.40 g/mL.

Step by step solution

01

Understand the formula for density

Density is defined as mass divided by volume. The formula for density is \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \).
02

Calculate density for the fluid in a car battery (part a)

Given: mass = 155 g, volume = 125 mL. Using the formula, \[ \text{Density} = \frac{155 \text{ g}}{125 \text{ mL}} = 1.24 \text{ g/mL} \].
03

Convert units for plastic material (part b)

Mass is given in pounds \(2.68 \text { lb} \) and volume in liters \(3.5 \text{ L} \). Convert the mass to grams: \[ 2.68 \text{ lb} \times 453.59237 \, \text{g/lb} = 1215.49 \text{ g} \] Convert volume to milliliters: \[ 3.5 \text {L} \times 1000 \text{ mL/L} = 3500 \text{ mL} \].
04

Calculate density for the plastic material (part b)

Now, use the converted values in the density formula: \[ \text{Density} = \frac{1215.49 \text{ g}}{3500 \text{ mL}} = 0.347 \text{ g/mL} \].
05

Calculate density for the urine sample (part c)

Given: mass = 5.025 g, volume = 5.00 mL. Using the formula: \[ \text{Density} = \frac{5.025 \text{ g}}{5.00 \text{ mL}} = 1.005 \text{ g/mL} \].
06

Convert units for the solid object (part d)

Mass is given in pounds \(1.65 \text{ lb} \) and volume in milliliters \(170 \text{ mL} \). Convert the mass to grams: \[ 1.65 \text{ lb} \times 453.59237 \, \text{g/lb} = 748.43 \text{ g} \].
07

Calculate density for the solid object (part d)

Now, use the converted mass in the density formula: \[ \text{Density} = \frac{748.43 \text{ g}}{170 \text{ mL}} = 4.40 \text{ g/mL} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

density formula
Density is a fundamental concept in chemistry that helps us understand how mass is distributed in a given volume. The density formula is: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). This simple formula tells us that density is the ratio of mass to volume. For example, if you have a mass of 10 grams and a volume of 2 milliliters, the density would be \( \frac{10 \text{ g}}{2 \text{ mL}} = 5 \text{ g/mL} \). Understanding this formula is crucial because it allows you to calculate how compact or sparse the material is, which can tell you a lot about its properties.
unit conversion
Unit conversion is essential when dealing with different measurement systems. In chemistry problems, you often need to convert units to ensure that they are compatible. For example, in our exercise, we convert pounds to grams and liters to milliliters. To convert pounds to grams, we use the factor: 1 pound = 453.59237 grams. So, for 2.68 pounds, you multiply: \( 2.68 \text{ lb} \times 453.59237 \text{ g/lb} = 1215.49 \text{ g} \). Similarly, to convert liters to milliliters, use the factor: 1 liter = 1000 milliliters. For 3.5 liters, you multiply: \( 3.5 \text{ L} \times 1000 \text{ mL/L} = 3500 \text{ mL} \). Mastering unit conversion helps in problem-solving by ensuring consistency in measurements.
mass and volume relationship
The relationship between mass and volume is central to understanding density. Mass is the amount of matter in an object, typically measured in grams or pounds. Volume is the space that the object occupies, measured in milliliters or liters. Density bridges these two concepts by telling us how much mass is packed into a given volume. For example, if a car battery fluid has a mass of 155 grams and a volume of 125 milliliters, its density is \( \frac{155 \text{ g}}{125 \text{ mL}} = 1.24 \text{ g/mL} \). Higher density means more mass in less volume, while lower density means less mass in more volume.
problem-solving in chemistry
Problem-solving in chemistry often involves applying formulas and performing calculations to find unknown values. Here's a step-by-step approach:
1. Identify the given information. For example, in part a of our exercise, we're given mass = 155 grams and volume = 125 milliliters.
2. Convert units if necessary. Like converting pounds to grams or liters to milliliters.
3. Use the appropriate formula. In our case, the density formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \).
4. Substitute the given values into the formula and perform the calculation.
5. Check your work for consistency and accuracy. Practice makes perfect. The more problems you solve, the better you get at it.

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Most popular questions from this chapter

Solve each of the following problems: a. A urine sample has a density of \(1.030 \mathrm{~g} / \mathrm{mL}\). What is the specific gravity of the sample? b. A \(20.0-\mathrm{mL}\) sample of a glucose IV solution that has a mass of \(20.6 \mathrm{~g}\). What is the density of the glucose solution? c. The specific gravity of a vegetable oil is \(0.92\). What is the mass, in grams, of \(750 \mathrm{~mL}\) of vegetable oil? d. A bottle containing \(325 \mathrm{~g}\) of cleaning solution is used to clean hospital equipment. If the cleaning solution has a specific gravity of \(0.850\), what volume, in milliliters, of solution was used?

21 Write each of the following in scientific notation with two significant figures: a. \(5000 \mathrm{~L}\) b. \(30000 \mathrm{~g}\) c. \(100000 \mathrm{~m}\) d. \(0.00025 \mathrm{~cm}\)

On Greg's last visit to his doctor, he complained of feeling tired. His doctor orders a blood test for iron. Sandra, the registered nurse, does a venipuncture and withdraws \(8.0 \mathrm{~mL}\) of blood. About \(70 \%\) of the iron in the body is used to form hemoglobin, which is a protein in the red blood cells that carries oxygen to the cells of the body. About \(30 \%\) is stored in ferritin, bone marrow, and the liver. When the iron level is low, a person may have fatigue and decreased immunity. The normal range for serum iron in men is 80 to \(160 \mathrm{mcg} / \mathrm{dL}\). Greg's iron test showed a blood serum iron level of \(42 \mathrm{mcg} / \mathrm{dL}\), which indicates that Greg has iron deficiency anemia. His doctor orders an iron supplement to be taken twice daily. One tablet of the iron supplement contains \(65 \mathrm{mg}\) of iron. $ a. Write an equality and two conversion factors for one tablet of the iron supplement. b. How many grams of iron will Greg consume in one week?

Round off each of the following measurements to three significant figures: a. \(1.854 \mathrm{~kg}\) b. \(88.2038 \mathrm{~L}\) c. \(0.004738265 \mathrm{~cm}\) d. \(8807 \mathrm{~m}\) e. \(1.832 \times 10^{5} \mathrm{~s}\)

Write the equality and two conversion factors, and identify the numbers as exact or give the number of significant figures for each of the following: a. The label on a bottle reads \(10 \mathrm{mg}\) of furosemide per \(1 \mathrm{~mL}\). b. The Daily Value (DV) for selenium is \(70 . \mathrm{mcg}\). c. An IV of normal saline solution has a flow rate of \(85 \mathrm{~mL}\) per hour. d. One capsule of fish oil contains \(360 \mathrm{mg}\) of omega-3 fatty acids.

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