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We need to find the yield of ATP in the given reaction i.e.$\mathrm{NADH}→{\mathrm{NAD}}^{+}$

We know that

The energy produced by NADH's oxidation when it reaches electron transport complex I is used to make $3\mathrm{ATP}$. The equation of NADH is

data-custom-editor="chemistry" $\mathrm{NADH}+{\mathrm{H}}^{+}+\frac{1}{2}{\mathrm{O}}_2+3\mathrm{ADP}+3{\mathrm{P}}_{\mathrm{i}}→{\mathrm{NAD}}^{+}+{\mathrm{H}}_2\mathrm{O}+3\mathrm{ATP}$

We need to find the yield of ATP in the given reaction i.e.$\mathrm{glucose}→2\mathrm{pyruvate}$

We know that

Energy is stored in two NADH molecules and two ATP molecules as a result of glucose oxidation. The hydrogen ions and electrons from NADH are shuttled from the cytoplasm to the mitochondria, resulting in ${\mathrm{FADH}}_2$. As a result, only two ATP are produced when electrons are transferred from NADH in the cytoplasm to ${\mathrm{FADH}}_2$.

Six ATP are created in glycolysis: four from the two NADH and two from phosphorylation.

We need to find the yield of ATP in the given reaction i.e.$2\mathrm{pyruvate}→2\mathrm{acetyl}\mathrm{CoA}+2{\mathrm{CO}}_2$

We know that

Under anaerobic conditions, pyruvate reaches to the mitochondria. Their pyruvate is oxidized to produce $\mathrm{acetyl}-\mathrm{CoA},{\mathrm{CO}}_2,\mathrm{NADH}$. And as we all know $1\mathrm{NADH}$produces three ATP.

Therefore, a total of six ATP are produced

We need to find the yield of ATP in the given reaction i.e.$\mathrm{acetyl}\mathrm{CoA}→2{\mathrm{CO}}_2$

We know that

In one turn of the citric acid cycle, two ${\mathrm{CO}}_2$, three NADH, one ${\mathrm{FADH}}_2$, and one ATP are created via direct phosphate transfer. As a result, one cycle of the citric acid cycle yields twelve ATP.