91Ó°ÊÓ

Hyperthermia patient has a temperature of$106°F$

(a) The temperature of the patient's body is${106}^{∘}\mathrm{F}$
The temperature equationis employed for conversion as:
$T_{\mathrm{K}}=T_{\mathrm{c}}+273$
Here, $T_{\mathrm{c}}$ is that the temperature is Celsius and $T_F$ is that the temperature is Fahrenheit.
Substitutewithin the above equation we have:
$T_{\mathrm{c}}=\frac{T_{\mathrm{F}}−32}{1.8}$

$=\frac{106−32}{1.8}$

$={41}^{∘}\mathrm{C}$

The Child's temperature was$40.0°C$

(b) The temperature of the body of the kid is $103°F$
The temperature equation is employed for conversion as:

$T_{\mathrm{c}}=\frac{T_{\mathrm{F}}−32}{1.8}$

Here, $T_{\mathrm{c}}$is that the temperature is Celsius and $T_F$is that the temperature is Fahrenheit.
Substitute within the above equation we have:

$T_{\mathrm{c}}=\frac{T_{\mathrm{F}}−32}{1.8}$

$=\frac{103−32}{1.8}$

$={39}^{∘}\mathrm{C}$

Thus, the temperature of the body of the kid is $39°C$hence the doctorneedn't be called.