91Ó°ÊÓ

We are given mileage of motorcycle with fuel tank capacity.

As we know $1\mathrm{mi}/\mathrm{gal}=0.425\mathrm{Km}/\mathrm{L}$

So, $35\mathrm{mi}/\mathrm{gal}=35×0.425\mathrm{Km}/\mathrm{L}=14.875\mathrm{Km}/\mathrm{L}$

Fuel-tank capacity is $22\mathrm{L}$

Therefore, $14.875\mathrm{Km}/\mathrm{L}$means in $22\mathrm{L}$ motorcycle can cover a trip of $14.875\frac{\mathrm{Km}}{\cancel{\mathrm{L}}}×22\cancel{\mathrm{L}}=327.25\mathrm{Km}$

We are given mileage of motorcycle with fuel tank capacity.

As we know $1\mathrm{gal}=3.875\mathrm{L}$

Therefore, $22\mathrm{L}=4.84\mathrm{gal}$

The price of gasoline is $\$3.82\mathrm{per}\mathrm{gal}$

So, $4.84\mathrm{gal}=4.84\cancel{\mathrm{gal}}×\frac{\$3.82}{\cancel{\mathrm{gal}}}=\$18.5$

We are given mileage of motorcycle with fuel tank capacity.

As we know, $1\mathrm{mi}/\mathrm{h}=1.609\mathrm{Km}/\mathrm{h}$

therefore, $44\mathrm{mi}/\mathrm{h}=44×1.609\frac{\mathrm{Km}}{\mathrm{h}}=70.8\mathrm{Km}/\mathrm{h}$

Average speed is $70.8\mathrm{Km}/\mathrm{h}$

Total distance = $327.5\mathrm{Km}$

so, $\frac{\mathrm{Distance}}{\mathrm{Time}}=\mathrm{average}\mathrm{speed}$

$$\begin{gathered} 70.8\cancel{\mathrm{Km}}/\mathrm{h}=\frac{327.25\cancel{\mathrm{Km}}}{\mathrm{time}} \\ \mathrm{time}=4.622\mathrm{h} \end{gathered}$$

Time taken to complete the trip is $4.622\mathrm{h}$

We are given mileage of motorcycle with fuel tank capacity.

Density of gasoline is $0.74\mathrm{g}/\mathrm{ml}$

Capacity of tank is $22\mathrm{L}=22000\mathrm{mL}$

Density is mass divided by volume,

Therefore mass of fuel is $0.74\frac{\mathrm{g}}{\cancel{\mathrm{mL}}}=\frac{\mathrm{mass}}{22000\cancel{\mathrm{mL}}}=16280\mathrm{g}$

We are given mileage of motorcycle with fuel tank capacity.

As given, Energy produced is $47\mathrm{kJ}/\mathrm{g}$

so, in full fuel tank energy produced will be $$\begin{gathered} 1\mathrm{g}=47\mathrm{kJ} \\ 22000\mathrm{g}=1034000\mathrm{kJ} \end{gathered}$$