91Ó°ÊÓ

We are given the equation and we have to find the mole-mole factors.

In the given equation, there are ways to find mole factors by considering two compounds every time.

consider,${\mathrm{SO}}_2\mathrm{and}{\mathrm{O}}_2$

$2$mole ${\mathrm{SO}}_2=$$1$mole ${\mathrm{O}}_2$

which gives the $\frac{2moleS{O}_2}{1mole{O}_2}$mole-mole factor.

Now consider $O_{2}andS{O}_3$

$1$mole role="math" localid="1652676267214" ${\mathrm{O}}_2=2$mole ${\mathrm{SO}}_3$

which gives the$\frac{1mole{O}_2}{2moleS{O}_3}$mole-mole factor.

Again, consider $S{O}_{2}andS{O}_3$

$2$mole $S{O}_2=2$mole $S{O}_3$

which gives the $\frac{2moleS{O}_3}{2moleS{O}_2}$mole-mole factor.

Hence, these are the mole-mole factors.

We are given the equation and we have to find the mole-mole factors.

In the given equation, there are ways to find mole factors by considering two compounds every time.

Consider P and ${\mathrm{O}}_2$

$4$mole P=$5$mole ${\mathrm{O}}_2$

which gives the$\frac{4\mathrm{mole}\mathrm{P}}{5\mathrm{mole}{\mathrm{O}}_2}$mole-mole factor.

Now consider,${\mathrm{O}}_2\mathrm{and}{\mathrm{P}}_2{\mathrm{O}}_5$

$5$mole$O_2=2$mole ${\mathrm{P}}_2{\mathrm{O}}_5$

which gives the$\frac{5mole{O}_2}{2mole{P}_2{O}_5}$ mole-mole factor.

Again, consider $Pand{P}_2{O}_5$

$4$mole P=$2$moledata-custom-editor="chemistry" ${\mathrm{P}}_2{\mathrm{O}}_5$

which gives the data-custom-editor="chemistry" $\frac{2\mathrm{mole}{\mathrm{P}}_2{\mathrm{O}}_5}{4\mathrm{mole}\mathrm{P}}$mole-mole factor.

Hence, these are the mole-mole factors.