91Ó°ÊÓ

We have been given that,

Moles=$0.500$

We need to find the number of $C$atoms.

Let's calculate the number of carbon atoms in moles.

As we know,

$Numberofatoms=0.500×\frac{6.02×{10}^{23}}{1moleofC}=3.01×{10}^{23}atoms.$

Therefore, the number of carbon atoms in mole of carbon atoms is $3.01×{10}^{23}$atoms.

We have been given that,

Moles=$1.28$

We need to find the number of $S{O}_2$molecules.

We know,

Therefore the number of molecules =$7.71×{10}^{23}$.

We have been given that,

number of atoms =$5.22×{10}^{22}$

We need to find number of moles.

We are given that no of molecules = $5.22×{10}^{22}$

We know that $N_A=6×{10}^{23}$

And we know that,

$moles=\frac{no.ofmolecules}{N_A}$

$$\begin{gathered} moles=\frac{5.22×{10}^{22}}{6×{10}^{23}} \\ moles=0.0867 \end{gathered}$$

The number of moles of $Fe$in $5.22×{10}^{22}$molecules of $Fe$is $0.0867$moles.

We have been given that,

Number of molecules=$8.50×{10}^{24}$

We need to find the moles.

We are given that no. of molecules = $8.50×{10}^{24}$

We know that $N_A=6×{10}^{23}$

And we know that:

$moles=\frac{no.ofmolecules}{N_A}$

$$\begin{gathered} moles=\frac{8.50×{10}^{24}}{6×{10}^{23}} \\ moles=14.1 \end{gathered}$$

Number of moles of $C_2{H}_{6}O$in localid="1652857798859" $8.50×{10}^{24}$molecules is $14.1$moles.