/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 7.3 Allyl sulfide, (C3H5)2S, gives g... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 7: Q. 7.3 (page 226)

Allyl sulfide, (C3H5)2S, gives garlic, onions, and leeks their characteristic odor. The characteristic odor of garlic is due to a sulfur-containing compound.

a. How many moles are in localid="1653464570001" 23.2gof allyl sulfide?

b. How many grams are in 0.75mole of allyl sulfide?

Short Answer

Expert verified

a. 0.203moles are inlocalid="1653464584260" 23.2gof allyl sulfide .

b. 85.65grams are in 0.75mole of allyl sulfide .

Step by step solution

01

Part (a) Step 1: Given information

We need to find that how many moles are in 23.2gof allyl sulfide

02

Part (a) Step 2: Explanation

Number of moles=gram molecular weight/molar mass

Therefore here in this case we get ;

So, number of moles鈬�23.2g114.21g/moles=0.203moles

03

Part (b) Step 1: Given information

We need to find that how many grams are in 0.75 mole of allyl sulfide .

04

Part (b) Step 2: Explanation

To find grams , we will use this formula ,

Number of moles=gram molecular weight/molar mass

Substituting the values we get ;

鈬�0.75moles脳114.21gmoles=85.65g

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A toothpaste contains 0.240%by mass sodium fluoride used to prevent dental caries and 5.0%by mass KNO3, which decreases pain sensitivity. One tube contains119g of toothpaste
role="math" localid="1652503120563" NaFand KNO3 are components found in toothpastes.

  1. How many moles of NaFare in the tube of toothpaste?
  2. How many fluoride ions, F-, are in the tube of toothpaste?
  3. How many grams of sodium ion, Na+, are in 1.50gof toothpaste?
  4. How many KNO3formula units are in the tube of toothpaste?

Determine whether each of the following chemical equations are balanced or not balanced:

a.PCl3(s)+Cl2(g)鈫�PCl5(s)

b.CO(g)+2H2(g)鈫�CH4O(g)

c.2KClO3(s)鈫�2KCl(s)+O2(g)

d.Mg(s)+N2(g)鈫�Mg3N2(s)

When ammonia (NH3) gas reacts with fluorine gas, the gaseous products are dinitrogen tetrafluoride (N2F4) and hydrogen fluoride (HF). (7.4,7.7,7.8)

a. Write the balanced chemical equation.

b. How many moles of each reactant are needed to produce localid="1653469855463" 4.00moleof HF?

c. How many grams of F2are needed to react with localid="1653469902894" 25.5gof NH3?

d. How many grams of N2F4can be produced when localid="1653469925977" 3.40gof NH3reacts?

Balance each of the following chemical equations, and identify the type of reaction: (7.4,7.5)

a.Si3N4(s)鈫�Si(s)+N2(g)

b.Mg(s)+N2(g)鈫�Mg3N2(s)

c.Al(s)+H2PO4(aq)鈫�H2(g)+AIPO4(aq)

d.C3H4(g)+O2(g)鈫�CO2(g)+H2O(g)

e.Cr2O3(s)+H2(g)鈫�Cr(s)+H2O(g)

f.Al(s)+Cl2(g)鈫�AlCl3(s)

g.MgCl2(aq)+AgNO3(aq)鈫�AgCl(s)+Mg(NO3)2(aq)

a. What is measured by the heat of reaction?

b. In an endothermic reaction, is the energy of the products higher or lower than that of the reactants?

c. Draw an energy diagram for an endothermic reaction.
See all solutions

Recommended explanations on Chemistry Textbooks

Making Measurements

Read Explanation

Chemical Reactions

Read Explanation

Physical Chemistry

Read Explanation

Organic Chemistry

Read Explanation

The Earths Atmosphere

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.