91Ó°ÊÓ

We have to find the molar mass of${\mathrm{C}}_3{\mathrm{H}}_8\mathrm{O}$

We know that,

Molar mass of one $\mathrm{C}$atom =localid="1653487052666" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653487061325" $1.00\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653487069726" $15.99\mathrm{g}$

So, the molar mass of${\mathrm{C}}_3{\mathrm{H}}_8\mathrm{O}$=$3\left(12.01\right)+8\left(1.00\right)+15.99$=localid="1653487079264" $60.02\mathrm{g}$

We have to find the molar mass of${\left({\mathrm{NH}}_4\right)}_{2}C{O}_3$

We know that,

Molar mass of one $\mathrm{N}$atom = localid="1653487090989" $14.00\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653487100053" $1.00\mathrm{g}$

Molar mass of one $\mathrm{C}$atom =localid="1653487108345" $12.01\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653487116912" $15.99\mathrm{g}$

So, the molar mass of${\left({\mathrm{NH}}_4\right)}_{2}C{O}_3$=$2\left(14.00\right)+8\left(1.00\right)+12.01+3\left(15.99\right)$=localid="1653487125862" $95.98\mathrm{g}$

We have to find the molar mass of$\mathrm{Zn}{\left({\mathrm{C}}_2{\mathrm{H}}_3{\mathrm{O}}_2\right)}_2$

We know that,

Molar mass of one $\mathrm{Zn}$atom =localid="1653487137821" $65.38\mathrm{g}$

Molar mass of one $\mathrm{C}$atom =localid="1653487146243" $12.01\mathrm{g}$

Molar mass of one $\mathrm{H}$atom =localid="1653487154655" $1.00\mathrm{g}$

Molar mass of one $\mathrm{O}$atom =localid="1653487163038" $15.99\mathrm{g}$

So, the molar mass of$\mathrm{Zn}{\left({\mathrm{C}}_2{\mathrm{H}}_3{\mathrm{O}}_2\right)}_2$=$65.38+4\left(12.01\right)+6\left(1.00\right)+4\left(15.99\right)$=localid="1653487173603" $183.38\mathrm{g}$