91Ó°ÊÓ

We are given that liquid methanol , which is used as a cooking fuel, burns with oxygen gas to produce the gases carbon dioxide and water. The reaction produces $363\mathrm{kJ}$of heat per mole of methanol.

As we know the reaction involved is ${\mathrm{CH}}_3\mathrm{OH}+{\mathrm{O}}_2→{\mathrm{CO}}_2+{\mathrm{H}}_2\mathrm{O}$

Now we can see there are four hydrogen three oxygen and one carbon in left whereas one carbon three oxygen and two hydrogen at right. Therefore, Balanced equation will be ${\mathrm{CH}}_3\mathrm{OH}+\frac{3}{2}{\mathrm{O}}_2→{\mathrm{CO}}_2+2{\mathrm{H}}_2\mathrm{O}$

We are given that liquid methanol , which is used as a cooking fuel, burns with oxygen gas to produce the gases carbon dioxide and water. The reaction produces $363\mathrm{kJ}$of heat per mole of methanol.

The reaction is exothermic, As heat is released in the reaction according to question.

We are given that liquid methanol , which is used as a cooking fuel, burns with oxygen gas to produce the gases carbon dioxide and water. The reaction produces $363\mathrm{kJ}$of heat per mole of methanol.

The reaction is ${\mathrm{CH}}_3\mathrm{OH}+\frac{3}{2}{\mathrm{O}}_2→{\mathrm{CO}}_2+2{\mathrm{H}}_2\mathrm{O}$

Now,

$$\begin{gathered} 1\mathrm{mole}{\mathrm{CH}}_4\mathrm{O}=1.5\mathrm{mole}{\mathrm{O}}_2 \\ 0.45\mathrm{mole}{\mathrm{CH}}_4\mathrm{O}=0.675\mathrm{mole}{\mathrm{O}}_2 \end{gathered}$$

We are given that liquid methanol , which is used as a cooking fuel, burns with oxygen gas to produce the gases carbon dioxide and water. The reaction produces $363\mathrm{kJ}$of heat per mole of methanol.

The reaction is ${\mathrm{CH}}_3\mathrm{OH}+\frac{3}{2}{\mathrm{O}}_2→{\mathrm{CO}}_2+2{\mathrm{H}}_2\mathrm{O}$

Now, according to question

$1\mathrm{mole}{\mathrm{CH}}_4\mathrm{O}=1\mathrm{mole}{\mathrm{CO}}_2$

molar mass of methanol is $32\mathrm{g}$

$$\begin{gathered} 32\mathrm{g}{\mathrm{CH}}_4\mathrm{O}=44\mathrm{g}{\mathrm{CO}}_2 \\ 78.0\mathrm{g}{\mathrm{CH}}_4\mathrm{O}=107.25\mathrm{g}{\mathrm{CO}}_2 \end{gathered}$$