91Ó°ÊÓ

The given are the bases $S{O}_4^{2-},C{N}^{-},N{H}_3,Cl{O}_2^{-}$. To find the formula for the conjugate acid for each of the given bases

Conjugate acid is formed from the base by a gain of $\mathrm{H}+$ion. ${\mathrm{SO}}_4^{2-}$gain one proton and form $HS{O}_4^{-}$, it is the conjugate acid for${\mathrm{SO}}_4^{2-}$

localid="1652617304806" $$\begin{gathered} H^{+}+S{O}_4^{-2}⇄HS{O}_4^{-} \\ \left(base\right)(conjugateacid) \end{gathered}$$

Conjugate acid is formed from the base by a gain of $\mathrm{H}+$ion. ${\mathrm{CN}}^{-}$gain one proton and form$HCN$, it is the conjugate acid for $C{N}^{-}$.

localid="1652866897437" $$\begin{gathered} H^{+}+C{N}^{-}⇄HCN \\ \left(base\right)(conjugateacid) \end{gathered}$$

Conjugate acid is formed from the base by the gain of $\mathrm{H}+$an ion. $N{H}_3$gain one proton and form $N{H}_4^{+}$, it is the conjugate acid for $N{H}_3$.

localid="1652617496596" $$\begin{gathered} H^{+}+N{H}_3⇄N{H}_4^{+} \\ \left(base\right)(conjugateacid) \end{gathered}$$

Conjugate acid is formed from the base by a gain of $\mathrm{H}+\mathrm{ion}.{\mathrm{ClO}}_2^{-}$gain one proton and forms $HCl{O}_2$, it is the conjugate acid for $Cl{O}_2^{-}$.

localid="1652617564141" $$\begin{gathered} H^{+}+Cl{O}_2^{-}⇄HCl{O}_2 \\ \left(base\right)(conjugateacid) \end{gathered}$$