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Methanoic acid, the first member of carboxylic acid series, when warmed with concentrated sulphuric acid decompose in the following way and evolve carbon monoxide The driving force for this reaction lies in the fact that the \(\mathrm{HC} \equiv \mathrm{O}^{+}\) ion is very unstable acid and thus easily loses \(\mathrm{H}^{+}\). Formic acid on heating with conc. \(\mathrm{H}_{2} \mathrm{SO}_{4}\) gives (a) \(\mathrm{CO}_{2}+\mathrm{H}_{2}\) (b) \(\mathrm{CO}+\mathrm{H}_{2} \mathrm{O}\) (c) \(\mathrm{CO}\) (d) \(\mathrm{H}_{2} \mathrm{O}\)

Short Answer

Expert verified
Formic acid on heating with conc. H_2SO_4 gives (b) CO + H_2O.

Step by step solution

01

Understanding the Reaction

Formic acid (CHOOH) undergoes dehydration in the presence of concentrated sulfuric acid (H_2SO_4). This process typically evolves carbon monoxide (CO) because the unstable HCo^+ ion readily loses H^+.
02

Determining the Products

When formic acid dehydrates, the reaction simplifies to: HCOOH ightarrow CO + H_2O. Sulfuric acid acts as a dehydrating agent and strips away water (H_2O), leaving carbon monoxide as one of the primary products.
03

Analyzing the Answer Options

Given the reaction HCOOH ightarrow CO + H_2O, examine the provided options: (a) CO_2 + H_2, (b) CO + H_2O, (c) CO, (d) H_2O. The correct options should reflect the products of this dehydration.
04

Choosing the Correct Answer

Option (b) CO + H_2O matches the process since formic acid treated with concentrated H_2SO_4 evolves CO and produces water as a byproduct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Methanoic Acid Decomposition
Methanoic acid, also known as formic acid, is an organic compound with the chemical formula \( ext{HCOOH}\). It is the simplest form of carboxylic acid and plays a significant role in various chemical reactions. When methanoic acid is warmed with concentrated sulfuric acid, it decomposes, releasing carbon monoxide (CO) gas.
This process occurs due to the unstable nature of the \(HC^+\) ion present in formic acid. This ion easily releases a proton, leading to the formation of carbon monoxide.
The decomposition of methanoic acid can be written as:
  • \( ext{HCOOH} \rightarrow \text{CO} + \text{H}_2 ext{O}\)

This reaction demonstrates how formic acid can undergo decomposition, highlighting its reactive nature, especially in the presence of strong acids like sulfuric acid.
Carboxylic Acid Series
Carboxylic acids are a class of organic acids characterized by the presence of a carboxyl group (
  • \(-COOH\)
). Methanoic acid is the first and simplest member of this series.
Carboxylic acids have diverse applications ranging from the synthesis of organic compounds to being active participants in biochemical reactions. The series starts with methanoic acid and extends as the carbon chain length increases.
Understanding the carboxylic acid series is crucial because:
  • It provides insights into the properties and reactions of organic acids.
  • The length of the carbon chain affects the acid's physical and chemical properties.
  • It informs the reactivity patterns when these acids are subjected to various reagents.
Each member of the series has distinct properties, but they share the common feature of containing the \(\text{-COOH}\) functional group, making them versatile in chemical reactions.
Sulfuric Acid Dehydration
Sulfuric acid (
  • \(\text{H}_2\text{SO}_4\)
) is a powerful dehydrating agent, which means it can effectively remove water molecules from other compounds.
When used with methanoic acid, sulfuric acid facilitates the removal of a water molecule during the decomposition process.
This strong acid doesn’t just act as a catalyst in the reaction; it plays an active role in driving the reaction forward by stripping away water. The presence of sulfuric acid ensures that the decomposition proceeds efficiently, leading to the formation of carbon monoxide.
  • In the reaction \(\text{HCOOH} \rightarrow \text{CO} + \text{H}_2\text{O}\), sulfuric acid performs the dehydration.
  • This showcases its ability to accelerate and guide the decomposition of organic molecules.
Sulfuric acid's strong dehydrating properties are widely utilized in organic synthesis, making it a vital component in many chemical reactions.
Formic Acid Reaction with H2SO4
Formic acid reacts with sulfuric acid in a manner that demonstrates the principles of organic chemistry effectively. This reaction is popular in demonstrating the concept of dehydration.
As methanoic acid undergoes the reaction:
  • It forms carbon monoxide.
  • Water is produced as a byproduct.
The reaction that occurs is a classic example of how reactive organic acids can be with strong acids.
  • The loss of \(H^+\) from the unstable \(HC^+\) ion confirms the reaction’s feasibility and mechanism.
  • This mechanism highlights the acid's instability and reactive nature under acidic conditions.
Understanding this reaction is crucial because it exemplifies the decomposition potential of carboxylic acids and underlines the importance of methodology in organic synthesis.

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Most popular questions from this chapter

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Grignard reagents \((\mathrm{RMg} X)\) are prepared by the reaction of an organic halide and magnesium metal is in ether solvent. $$\mathrm{R}-\mathrm{X}+\mathrm{Mg} \stackrel{\mathrm{R}-\mathrm{O}-\mathrm{R}}{\longrightarrow} \mathrm{R}-\mathrm{Mg} \mathrm{X}=$$ The solvent (usually diethyl ether or tetrahydrofuran) plays a crucial role in the formation of a Grignard reagent. Alkyl halides are more reactive than aryl and vinyl halides. Indeed, aryl and vinyl chlorides do not form Grignard reagent in diethyl ether. However, an alkyl halide containing an alcoholic -OH group can be converted to Grignard reagent by first protecting the -OH group to tert-butyldimethylsilyl ether which is inert to Grignard reagent. The protecting group is finally liberated by treatment with fluoride ion. Grignard reactions generally occur in dry ether because (a) The stronger acid diethyl ether will displace the weaker \(\mathrm{RH}\) acid from its salt. (b) The stronger acid \(\mathrm{H}_{2} \mathrm{O}\) will displace the weaker acid \(\mathrm{RH}\) from its salt. (c) Water slows down the reaction. (d) Water mixes with ether preventing ether to perform its function.

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