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Which of the following statement is true regarding aspirin, a commonly used antipyretic and analgesic? Given \(\mathrm{pK}_{\mathrm{a}}\) for aspirin \(=3.5 ; \mathrm{pH}\) in stomach and small intestine is \(2.5\) and 8 , respectively. (a) It is completely ionized in the stomach and almost un-ionized in the small intestine. (b) It is ionized in the small intestine and almost un-ionized in the stomach. (c) It is ionized in the stomach and almost un-ionized in the small intestine. (d) It is neither ionized in stomach nor in intestine.

Short Answer

Expert verified
Answer: b) It is ionized in the small intestine and almost un-ionized in the stomach.

Step by step solution

01

Understanding Acid-Base Equilibrium

Aspirin is a weak acid (with pKa = 3.5) and its ionization in solution depends on the pH of the environment. The degree of ionization is dictated by the Henderson-Hasselbalch equation, which is generally used to find the ratio of ionized to unionized forms of a weak acid, given by \( \text{pH} = \text{pKa} + \log \left( \frac{[A^-]}{[HA]} \right) \).
02

Ionization in Stomach

In the stomach, where the pH is 2.5, we apply the Henderson-Hasselbalch equation: \( 2.5 = 3.5 + \log \left( \frac{[A^-]}{[HA]} \right) \). Solving gives \( -1 = \log \left( \frac{[A^-]}{[HA]} \right) \), indicating that \( \frac{[A^-]}{[HA]} = 0.1 \), meaning it is mostly un-ionized in the stomach.
03

Ionization in Small Intestine

In the small intestine, where the pH is 8, we use the Henderson-Hasselbalch equation again: \( 8 = 3.5 + \log \left( \frac{[A^-]}{[HA]} \right) \). This results in \( 4.5 = \log \left( \frac{[A^-]}{[HA]} \right) \), suggesting \( \frac{[A^-]}{[HA]} = 10^{4.5} \), meaning it is mostly ionized in the small intestine.
04

Conclusion

From steps 2 and 3, we determine that aspirin is mostly unionized in the stomach (pH 2.5) and mostly ionized in the small intestine (pH 8). Therefore, statement b) "It is ionized in the small intestine and almost un-ionized in the stomach" is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Henderson-Hasselbalch equation
The Henderson-Hasselbalch equation is a fundamental tool in understanding how weak acids and bases behave in different environments. This equation elegantly relates the pH of a solution to the pKa of the acid, providing insight into the acid's ionization state. The formula is expressed as follows:

\[\text{pH} = \text{pKa} + \log \left( \frac{[A^-]}{[HA]} \right) \]
* **pH**: This is the measure of acidity or alkalinity of a solution.
* **pKa**: The acid dissociation constant, which indicates the strength of the weak acid.
* **[A^-]** and **[HA]**: These represent the concentrations of the ionized (A^-) and unionized (HA) forms of the acid.

When applying this equation, you can accurately determine the proportion of a weak acid that is ionized or unionized by substituting the environment's pH and the weak acid's pKa. This explains whether a substance like aspirin will be ionized more in the stomach or small intestine, influencing its absorption and effectiveness.
pKa and pH relationship
The relationship between pKa and pH is crucial for predicting the ionization of weak acids. The pKa is essentially a measure of the strength of an acid, indicating how easily it donates protons. When the pKa of an acid equals the pH of the solution it's in, the acid is half-ionized.
To better understand:
  • If the pH is lower than the pKa, there are more free protons in the solution, leading to the weak acid being mostly in its protonated, or unionized, form.

  • If the pH is higher than the pKa, the environment has fewer free protons, resulting in the acid being mostly in its unprotonated, or ionized, form.

In the context of aspirin, with a pKa of 3.5, its behavior in the stomach and small intestine provides a good example:
* **Stomach pH (2.5)**: Since the pH is below the pKa, aspirin is mostly unionized. * **Small intestine pH (8)**: With a pH above the pKa, aspirin is mostly ionized.
This relationship guides us in predicting where a drug will be more active or absorbed based on the pH of different parts of the body.
Ionization of weak acids
Ionization refers to the process of an acid losing a proton, forming its conjugate base. For weak acids like aspirin, ionization depends heavily on the surrounding pH, influenced by the concentration of hydronium ions present.

Key points about the ionization of weak acids:
  • Weak acids do not completely ionize in solution, unlike strong acids.
  • The extent of ionization is increased in basic environments where pH is higher than the acid's pKa.
  • In acidic environments where the pH is lower, weak acids tend to remain mostly unionized.

For example, in a highly acidic stomach environment with a pH of 2.5, aspirin remains largely in its unionized form. Conversely, in the more alkaline small intestine, where the pH is 8, aspirin becomes mostly ionized. This shift is vital for its transport across cell membranes and its therapeutic effectiveness, as absorption is greatly affected by whether the drug is ionized or not. Understanding these nuances helps in optimizing drug formulation and administration.

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Most popular questions from this chapter

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