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Suppose that Always Rain Irrigation’s marketing department will undertake an intense ad campaign for the bronze sprinklers, which are more expensive but also more durable than the plastic ones. Forecast demand for the next four years is

Yearly Demand

1 (IN 000s)

2 (IN 000s)

3 (IN 000s)

4 (IN 000s)

Plastic 90

32

44

55

56

Plastic 180

15

16

17

18

Plastic 360

50

55

64

67

Bronze 90

11

15

18

23

Bronze 180

6

5

6

9

Bronze 360

15

16

17

20

What are the capacity implications of the marketing campaign (assume no learning)?

Short Answer

Expert verified

The number of machines required to keep up with the growth of bronze units is still insufficient, and the labour requirements for each machine are greater than the total work of two operators.

Step by step solution

01

Calculation of total capacity of bronze and plastic

As given of plastic machine

Machine requirement (Plastic) = 4

Capacity used (Plastic) = 200,000 sprinklers

Machine (Plastic) = 1

Hence,

Total capacity = Plastic machine x Plastic capacity

= 1 x 200,000

= 200,000

Now of the bronze machine,

Machine requirement (bronze) = 2

Capacity used (bronze) = 12,000 sprinklers

Machine (bronze) = 3

Hence,

Total capacity = Plastic machine x Plastic capacity

= 3 x 12,000

= 36,000

02

The capacity implications of the marketing campaign

For plastic,

Percentage of capacity used:

Potential output in a given period of time = Total capacity / 1000 (as per given)

Where,

Total capacity is 2, 00,000

Potential output in given output = 2, 00, 00 / 1000

= 200

For bronze,

Percentageof capacity used:

Potential output in a given period of time = Total capacity / 1000 (as per given)

Where,

Total capacity = 3 x 12, 000

= 36,000

Potential output in given output = 36,000 / 1000

= 36

Bronze

1 Year

2 Year

3 Year

4 Year

Bronze units demand (000s)

11+6+15 = 42

15+5+16=

36

18+6+17 =

41

23 +9+20 = 52

Capacity used (%)

42 / 36 = 11.6%

36 / 36 = 100%

41 / 36 = 11.4%

52/ 36 =

14.4%

Total requirement (Machine)

3 x 1.16 =

3.48

3 x 1 =

3

3 x 1.14 = 3.42

3 x 1.44= 4.32

Total requirement ( Labour)

2 x 3.48 = 6.96

2 x 3 =

6

2 x 3.42 = 6.84

2 x 4.32 = 8.64

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