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A fast-food restaurant serves hamburgers, cheeseburgers, and chicken sandwiches. The restaurant counts a cheeseburger as equivalent to 1.25 hamburgers and chicken sandwiches as 0.8 hamburger. Current employment is five full-time employees who each work a 40-hour week. If the restaurant sold 700 hamburgers, 900 cheeseburgers, and 500 chicken sandwiches in one week, what is its productivity? What would its productivity have been if it had sold the same number of sandwiches (2,100), but the mix was 700 of each type?

Short Answer

Expert verified

The productivity of the restaurant, when it sells 700 hamburgers, 900 cheeseburgers, and 500 chicken sandwiches, is 10.225.

The productivity of the restaurant, when it sells 700 hamburgers, 700 cheeseburgers, and 700 chicken sandwiches, is 10.675

Step by step solution

01

Step 1:Given information

Number of hamburgers sold= 700

Number of cheeseburgers sold= 900

Number of chicken sandwiches sold= 500

Total workforce= 5

In addition, it is also stated that one cheeseburger is equal to 1.25 hamburgers, and one chicken sandwich is equal to 0.80 hamburger.

02

Calculation of total output and input for scenario 1 

Based on the given information,

Hamburgers = 700

1 Cheeseburger = 1.25 hamburgers

900 cheeseburgers = 720 hamburgers

1 Chicken sandwich = 0.8 hamburger

500 chicken sandwiches = 500÷0.8= 625 hamburgers

Therefore, the total output =700+720+625=2,045

Total workforce = 5

Total hours worked in a week = 40

Total input =5×40=200

03

Calculation of the productivity for scenario 1 

Productivity=OutputInput=2,045200=10.225

04

Calculation of total output and input for scenario 2 

Based on the given information,

Hamburgers = 700

1 Cheeseburger= 1.25 hamburgers

700 cheeseburgers =700÷1.25=560hamburgers

1 Chicken sandwich= 0.8 hamburger

700 chicken sandwiches =700÷0.8=875hamburgers

Total output =700+560+875=2,135

For this scenario, the input is the same, which is 200

05

Calculation of the productivity for scenario 2

Productivity=OutputInput=2,135200=10.675

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