/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 A gene has three alleles, \(A_{1... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A gene has three alleles, \(A_{1}, A_{2},\) and \(A_{3},\) with frequencies \(0.6,0.3,\) and \(0.1,\) respectively. If mating is random, predict the combined frequency of all the heterozygotes in the population.

Short Answer

Expert verified
The combined frequency of all heterozygotes is 0.54.

Step by step solution

01

Understanding Heterozygotes

Heterozygotes are individuals having two different alleles for a particular gene. For alleles \(A_1, A_2,\) and \(A_3,\) the possible heterozygote combinations are \((A_1, A_2), (A_1, A_3),\) and \((A_2, A_3)\).
02

Calculate Frequency of Each Heterozygote

Using the formula for the frequency of a heterozygote pair \((p_i \cdot p_j) + (p_j \cdot p_i) = 2p_ip_j\), calculate the frequency for each heterozygote:- \( A_1, A_2: 2 \times 0.6 \times 0.3 = 0.36 \)- \( A_1, A_3: 2 \times 0.6 \times 0.1 = 0.12 \)- \( A_2, A_3: 2 \times 0.3 \times 0.1 = 0.06 \)
03

Compute Combined Frequency

Sum the frequencies calculated for each heterozygote to find the total heterozygote frequency: \(0.36 + 0.12 + 0.06 = 0.54\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Allele Frequencies
In the study of population genetics, allele frequencies are fundamental concepts used to describe how common a particular allele is within a given population. An allele is simply a variant form of a gene, and the frequency tells us how often an allele occurs relative to the total number of alleles for that gene in the population.

For example, consider a gene with three alleles: \(A_{1}, A_{2},\) and \(A_{3}\). If the frequencies of these alleles are known to be 0.6, 0.3, and 0.1, respectively, this means:
  • 60% of all alleles in the population are \(A_{1}\),
  • 30% are \(A_{2}\), and
  • 10% are \(A_{3}\).
Understanding allele frequencies is crucial because they are the basis for predicting how traits controlled by these alleles are distributed in a population. The alteration of these frequencies over time can indicate evolutionary changes. Keeping track of these frequencies helps geneticists understand whether certain alleles are becoming more or less common, possibly due to natural selection, mutation, genetic drift, or gene flow.
Heterozygotes
Heterozygotes play a significant role in the genetic makeup of a population. A heterozygote is an individual who possesses two different alleles for a specific gene. This diversity can lead to variability in traits, potentially offering advantages in certain environmental situations.

Given alleles \(A_{1}, A_{2},\) and \(A_{3}\), heterozygote combinations are pairs such as \((A_1, A_2), (A_1, A_3),\) and \((A_2, A_3)\). The formula to calculate the frequency of heterozygotes combines the probabilities of each allele pairing:
  • \((A_1, A_2)\) is calculated as \(2 imes 0.6 imes 0.3 = 0.36\)
  • \((A_1, A_3)\) is \(2 \times 0.6 \times 0.1 = 0.12\)
  • \((A_2, A_3)\) is \(2 \times 0.3 \times 0.1 = 0.06\)
The combined understanding of these pairings leads to insights on how heterozygosity affects genetic diversity. This affects traits expressed and can influence a population's adaptability to changes in the environment.
Random Mating
Random mating is a key assumption in classical population genetics, particularly in the Hardy-Weinberg equilibrium. It occurs when individuals in a population choose their mates without regard to the alleles they carry, ensuring that all possible allele combinations have the chance to form.

In populations where random mating occurs, allele and genotype frequencies remain constant from generation to generation, provided no other evolutionary forces act on them. This concept is foundational for predicting genetic variations, such as heterozygotes, among offspring.

In the exercise with alleles \(A_{1}, A_{2},\) and \(A_{3}\), assuming random mating allows us to use simple probability to predict offspring genotypes. Since mating is random, the chance of any allele pairing are solely determined by their respective frequencies. Thus, knowing the allele frequencies enables us to predict the combined frequency of all heterozygotes in the population.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In an isolated population, the frequencies of the \(I^{A}, I^{B}\) and \(i\) alleles of the \(A-B-O\) blood type gene are, respectively, \(0.15,0.25,\) and \(0.60 .\) If the genotypes of the \(\mathrm{A}-\mathrm{B}-\mathrm{O}\) blood type gene are in Hardy-Weinberg proportions, what fraction of the people who have type \(A\) blood in this population are expected to be homozygous for the \(F^{A}\) allele?

In controlled experiments with different genotypes of an insect, a researcher has measured the probability of survival from fertilized eggs to mature, breeding adults. The survival probabilities of the three genotypes tested are: \(0.92(\text { for } G G), 0.90 \text { (for } G g),\) and 0.56 (for \(g g\) ). If all breeding adults are equally fertile, what are the relative fitnesses of the three genotypes? What are the selection coefficients for the two least fit genotypes?

The frequency of newborn infants homozygous for a recessive lethal allele is about 1 in 25,000 . What is the expected frequency of carriers of this allele in the population?

A phenotypically normal couple has had one normal child and a child with cystic fibrosis, an autosomal recessive disease. The incidence of cystic fibrosis in the population from which this couple came is \(1 / 500\). If their normal child eventually marries a phenotypically normal person from the same population, what is the risk that the newlyweds will produce a child with cystic fibrosis?

A population consists of 25 percent tall individuals \(\text { (genotype }T T), 25 \text { percent short individuals (genotype } t t)\) and 50 percent individuals of intermediate height (genotype \(T t\) ). Predict the ultimate phenotypic and genotypic composition of the population if, generation after generation, mating is strictly assortative (that is, tall individuals mate with tall individuals, short individuals mate with short individuals, and intermediate individuals mate with intermediate individuals).

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.